Organisms and Populations Class 12: Concepts, Growth Numericals and Board Answers
Updated 14 October 2026 · Fact-checked
Organisms and Populations is Chapter 11 of CBSE Class 12 Biology and part of Unit X, Ecology and Environment (10 marks). The 2026-27 syllabus covers only populations: attributes such as birth rate, death rate, sex ratio and age pyramids, population growth (exponential and logistic), and interactions like mutualism, competition, predation and parasitism.
What Organisms and Populations is about
Ecology studies interactions among organisms and between organisms and their physical (abiotic) environment, at four levels: organisms, populations, communities and biomes. This chapter, in the 2026-27 syllabus, deals only with the population level. (The NCERT sections on the organism and its environment, abiotic factors, responses and adaptations are not in the syllabus.)
Scientists ask two kinds of questions: 'how' questions (mechanism, e.g. how a bulbul sings) and 'why' questions (significance, e.g. why it sings: to communicate with its mate in the breeding season).
The chapter in four parts:
1. Population attributes: birth rate and death rate (per capita), sex ratio, age distribution (age pyramids), population density and how it is measured.
2. Population growth: natality, mortality, immigration, emigration; Nₜ₊₁ = Nₜ + [(B + I) − (D + E)]; exponential growth (dN/dt = rN, J-shaped curve) and logistic growth (dN/dt = rN(K − N)/K, S-shaped curve, carrying capacity K).
3. Life history variation: populations evolve to maximise reproductive (Darwinian) fitness.
4. Population interactions: mutualism (+ +), competition (− −), predation (+ −), parasitism (+ −), commensalism (+ 0) and amensalism (− 0), with NCERT examples.
This chapter has the most numericals in ecology: per capita rates, population change, r from doubling time, and growth equations.
Weightage: This chapter is part of Unit X, Ecology and Environment, which carries 10 of the 70 theory marks together with Ecosystem and Biodiversity and Conservation.Source: CBSE Biology (044) syllabus 2026-27, course structure, Unit X Ecology and Environment
In real board papers: asked in 7 of the 8 board papers we hold (2023 to 2026), on average 3.3 marks per paper. See the questions
Key concepts
- Population and its attributes
- NCERT section 11.1.1 Population Attributes
Population: individuals of a species living in a well-defined geographical area, sharing or competing for similar resources and potentially interbreeding. (Groups produced by asexual reproduction are also treated as populations in ecology.) Examples: all the cormorants in a wetland, rats in an abandoned house, teak trees in a forest tract, bacteria in a culture plate, lotus plants in a pond.
Why population ecology matters: an individual copes with a changed environment, but natural selection operates at the population level; so population ecology links ecology to population genetics and evolution.
Attributes a population has but an individual does not:
1. Birth rate (natality rate): per capita births. Example: a pond had 20 lotus plants; 8 new plants were added: birth rate = 8/20 = 0.4 offspring per lotus per year.
2. Death rate (mortality rate): per capita deaths. Example: 4 of 40 fruit flies died in a week: death rate = 4/40 = 0.1 individuals per fruit fly per week.
3. Sex ratio: e.g. 60% females, 40% males.
4. Age distribution: the per cent of individuals in each age group; plotted as an age pyramid.Age pyramids (for humans, males and females shown side by side): the shape shows whether the population is
- (a) expanding/growing: broad base (many pre-reproductive individuals), triangular;
- (b) stable: pre-reproductive and reproductive groups about equal, bell-shaped;
- (c) declining: narrow base (fewer young than reproductive adults), urn-shaped.
Age groups are pre-reproductive, reproductive and post-reproductive.
Worked example
A pond had 50 frogs at the start of a year. During the year, 30 tadpoles grew into new frogs and 10 frogs died. Calculate the birth rate and death rate, and the population at the year's end if there was no migration. (2 marks)
Try it first, then show the solutionSolution
- Birth rate = 30/50 = 0.6 frogs per frog per year; death rate = 10/50 = 0.2 frogs per frog per year. (1)
- End population = 50 + 30 − 10 = 70. Check with rates: 50 × (1 + 0.6 − 0.2) = 50 × 1.4 = 70. (1)
Answer: Birth rate 0.6, death rate 0.2 per frog per year; 70 frogs.
- Population density and its measurement
- NCERT section 11.1.1 Population Attributes (population density)
Population size, technically population density (N), tells us a lot about the status of a population. Any ecological process (competition, predation, pesticide effect) is judged by change in population size. Sizes range from under 10 (Siberian cranes at Bharatpur wetlands in a year) to millions (Chlamydomonas in a pond).
Ways to measure density:
- Total number: usually the most appropriate, but sometimes meaningless or hard.
- Per cent cover or biomass: better when individuals differ hugely in size. Example: 200 carrot grass (Parthenium hysterophorus) plants and one huge banyan tree: saying banyan density is low underestimates its enormous role; per cent cover or biomass is more meaningful.
- For huge populations (e.g. a dense bacterial culture in a petri dish), counting is impossible; another measure (such as biomass or cover) is used.
- Relative density: absolute numbers are not always needed; e.g. number of fish caught per trap is good enough for a lake.
- Indirect estimates: e.g. the tiger census in national parks and tiger reserves is often based on pug marks and faecal pellets.
Worked example
Suggest the most suitable measure of population density for (a) one banyan tree among 200 Parthenium plants, (b) fish in a large lake, (c) tigers in a reserve. Give a reason for each. (3 marks)
Try it first, then show the solutionSolution
- (a) Per cent cover or biomass: numbers would wrongly make the huge banyan seem unimportant. (1)
- (b) Relative density, e.g. number of fish caught per trap: counting every fish is impossible, and a relative measure is enough. (1)
- (c) Indirect estimate from pug marks and faecal pellets: tigers are rarely seen and cannot be counted directly. (1)
Answer: (a) Cover or biomass (b) catch per trap (c) pug marks and faecal pellets.
- Population growth: the four processes
- NCERT section 11.1.2 Population Growth
Population density changes with food availability, predation pressure and weather, through four basic processes:
- Natality (B): number of births in a period, added to the initial density.
- Mortality (D): number of deaths in the period.
- Immigration (I): individuals of the same species that came into the habitat from elsewhere.
- Emigration (E): individuals that left the habitat for elsewhere.
Natality and immigration increase density; mortality and emigration decrease it.
Equation: if Nₜ is the density at time t, then
Nₜ₊₁ = Nₜ + [(B + I) − (D + E)]The population grows if (B + I) > (D + E).
Which factors matter most? Normally births and deaths; immigration and emigration matter only in special conditions. For example, when a new habitat is being colonised, immigration may add more than births.
Worked example
A deer population of 500 had 60 births, 30 deaths, 10 immigrants and 20 emigrants in a year. Calculate the population at the end of the year and state whether it is growing. (2 marks)
Try it first, then show the solutionSolution
- Nₜ₊₁ = 500 + [(60 + 10) − (30 + 20)] = 500 + (70 − 50) = 520. (1)
- Check by stepping through: 500 + 60 = 560; − 30 = 530; + 10 = 540; − 20 = 520. Since B + I (70) > D + E (50), the population is growing. (1)
Answer: 520 deer; growing.
- Exponential growth
- NCERT section 11.1.2 Population Growth (exponential growth)
Condition: unlimited resources (food and space). Each species can then realise fully its innate potential to grow (as Darwin noted), and the population grows exponentially (geometrically).
Equation: if b = per capita birth rate and d = per capita death rate,
dN/dt = (b − d) × N; let (b − d) = r, so dN/dt = rN.- r = intrinsic rate of natural increase, an important parameter for assessing the impact of any biotic or abiotic factor on growth.
- Examples of r: Norway rat 0.015, flour beetle 0.12, human population in India in 1981: 0.0205.
Integral form: Nₜ = N₀e^(rt), where Nₜ = density after time t, N₀ = density at time 0, e = 2.71828.
Curve: plotting N against time gives a J-shaped curve.
How fast? Any species growing exponentially can reach enormous numbers quickly. Darwin showed that even slow-breeding elephants could reach huge numbers without checks. NCERT's chessboard story: a king agrees to place 1 grain on square 1, 2 on square 2, 4 on square 3, doubling each time; by half the board, all the wheat in his kingdom is not enough. Similarly a Paramecium doubling every day by binary fission would reach a mind-boggling number in 64 days (if food and space were unlimited).
Doubling time and r: if a population doubles in time T, then 2 = e^(rT), so r = ln 2 ÷ T ≈ 0.693 ÷ T.
Worked example
A population growing exponentially doubles in size every 5 years. Find its intrinsic rate of increase, r, and the time it takes to become 8 times its present size. (2 marks)
Try it first, then show the solutionSolution
- Nₜ = N₀e^(rt); doubling in 5 years gives e^(5r) = 2, so 5r = ln 2 = 0.693 and r = 0.693 ÷ 5 ≈ 0.139 per year. Check: e^(0.139 × 5) = e^(0.693) ≈ 2. (1)
- 8 times = 2³, i.e. three doubling times: 3 × 5 = 15 years. Check: e^(0.1386 × 15) = e^(2.079) ≈ 8. (1)
Answer: r ≈ 0.139 per year; 15 years to grow eightfold.
- Logistic growth and carrying capacity
- NCERT section 11.1.2 Population Growth (logistic growth)
Reality: no population has unlimited resources. Limited resources cause competition among individuals; the 'fittest' survive and reproduce. (Many governments have likewise put restraints on human population growth.)
Carrying capacity (K): the maximum number a habitat's resources can support, beyond which no further growth is possible.
Phases of logistic growth (plot of N against time is sigmoid, S-shaped):
1. Lag phase: slow start.
2. Acceleration: rapid growth.
3. Deceleration: growth slows as resources become limiting.
4. Asymptote: density levels off at K.
This is Verhulst–Pearl logistic growth.Equation: dN/dt = rN × (K − N)/K
- When N is small compared with K, (K − N)/K ≈ 1, so growth is almost exponential.
- As N approaches K, (K − N)/K approaches 0, so growth stops.
- Growth rate dN/dt is highest at N = K/2.
Why it is more realistic: resources for most animal populations are finite and become limiting sooner or later.
Exponential versus logistic:
- Resources: unlimited versus limited.
- Curve: J-shaped versus S-shaped (sigmoid).
- Limit: none versus carrying capacity K.
- Equation: dN/dt = rN versus dN/dt = rN(K − N)/K.
Worked example
A population has r = 0.5 per year and carrying capacity K = 1000. Calculate dN/dt when N = 200 and when N = 900. Explain the difference. (3 marks)
Try it first, then show the solutionSolution
- N = 200: dN/dt = 0.5 × 200 × (1000 − 200)/1000 = 100 × 0.8 = 80 per year. (1)
- N = 900: dN/dt = 0.5 × 900 × (100/1000) = 450 × 0.1 = 45 per year. Check: rN alone would be 100 and 450; the factor (K − N)/K cuts them to 80 and 45. (1)
- Near K, resources are almost used up, so the brake (K − N)/K is strong; at 200 the population is far from K and grows nearly exponentially. (1)
Answer: 80 per year at N = 200; 45 per year at N = 900; growth slows as N approaches K.
- Life history variation
- NCERT section 11.1.3 Life History Variation
Populations evolve to maximise their reproductive fitness, also called Darwinian fitness (a high r value), in their habitat. Under a particular set of selection pressures, organisms evolve the most efficient reproductive strategy.
Variation in strategies:
- Breed once in a lifetime: Pacific salmon fish, bamboo.
- Breed many times: most birds and mammals.
- Many small offspring: oysters, pelagic fishes.
- Few large offspring: birds, mammals.
Which is best? Ecologists suggest life history traits evolve to suit the limits set by the living and non-living parts of each habitat. This is an active area of research.
Worked example
Give one example each of an organism that breeds only once in its lifetime and one that produces a large number of small offspring. What do both strategies aim to maximise? (2 marks)
Try it first, then show the solutionSolution
- Breeds once: Pacific salmon (or bamboo). Many small offspring: oysters (or pelagic fishes). (1)
- Both aim to maximise reproductive (Darwinian) fitness, a high r, under the constraints of their habitat. (1)
Answer: Pacific salmon/bamboo; oysters/pelagic fishes; maximising Darwinian fitness.
- Population interactions: predation
- NCERT section 11.1.4 Population Interactions (table; predation)
No habitat holds just one species; even a plant needs soil microbes (to return nutrients) and animals (for pollination). Interspecific interactions can be beneficial (+), detrimental (−) or neutral (0):
Species A Species B Interaction + + Mutualism − − Competition + − Predation + − Parasitism + 0 Commensalism − 0 Amensalism Predation, parasitism and commensalism share one feature: the species live closely together.
Predation: nature's way of transferring energy fixed by plants to higher trophic levels. A sparrow eating seeds is a predator too; herbivores are, broadly, predators of plants.
Roles of predators:
1. Conduits for energy across trophic levels.
2. Keep prey populations in check; without predators, prey may reach very high densities and destabilise ecosystems. Exotic species become invasive where their natural predators are absent: the prickly pear cactus introduced into Australia in the early 1920s spread over millions of hectares of rangeland and was controlled only after a cactus-feeding moth from its native habitat was introduced. Biological pest control is based on this predator–prey regulation.
3. Maintain species diversity by reducing competition among prey. When the starfish Pisaster was removed from an enclosed rocky intertidal area of the American Pacific coast, more than 10 invertebrate species became extinct within a year because of interspecific competition.
4. Predators are 'prudent': an over-efficient predator could wipe out its prey and then itself.Prey defences:
- Camouflage (cryptic colouring) in some insects and frogs.
- Being poisonous: the Monarch butterfly is distasteful to birds because of a chemical it acquires as a caterpillar by feeding on a poisonous weed.
Plant defences against herbivores (nearly 25% of insects are phytophagous; plants cannot run away):
- Morphological: thorns (Acacia, cactus).
- Chemical: chemicals that sicken herbivores, inhibit feeding or digestion, disrupt reproduction or kill. Calotropis produces highly poisonous cardiac glycosides, so cattle and goats never browse it. Nicotine, caffeine, quinine, strychnine, opium are actually plant defences against grazers and browsers.
Worked example
Explain with the Pisaster experiment how a predator helps maintain species diversity. (2 marks)
Try it first, then show the solutionSolution
- In rocky intertidal communities of the American Pacific coast, the starfish Pisaster preys on many invertebrates, reducing the intensity of competition among them. (1)
- When all Pisaster were removed from an enclosed area, more than 10 invertebrate species became extinct within a year because of interspecific competition: so the predator maintained diversity. (1)
Answer: By keeping competing prey in check; removing Pisaster led to the extinction of over 10 prey species.
- Competition
- NCERT section 11.1.4 Population Interactions (competition)
Darwin saw interspecific competition as a potent force in evolution ('struggle for existence', 'survival of the fittest').
Common belief and its corrections:
1. Competition is not only between closely related species: unrelated species can compete. In some shallow South American lakes, visiting flamingoes and resident fishes compete for zooplankton.
2. Resources need not be limiting: in interference competition, one species' feeding efficiency is reduced by the interfering, inhibitory presence of another, even when food and space are plentiful.Best definition: competition is a process in which the fitness of one species (measured by r) is significantly lower in the presence of another species.
Evidence:
- Gause and others showed in the laboratory that with limited resources the superior competitor eventually eliminates the other; evidence in nature is less conclusive.
- The Abingdon tortoise of the Galapagos became extinct within a decade after goats were introduced, apparently because goats browsed more efficiently.
- Competitive release: a species restricted to a small area by a superior competitor expands dramatically when the competitor is removed. Connell's experiments on the rocky coasts of Scotland: the larger, superior barnacle Balanus dominates the intertidal zone and excludes the smaller Chthamalus (spelt Chathamalus in NCERT) from it.
- Herbivores and plants seem more affected by competition than carnivores.
Gause's Competitive Exclusion Principle: two closely related species competing for the same resources cannot co-exist indefinitely; the inferior one is eventually eliminated. This may hold when resources are limiting, but not otherwise.
Resource partitioning: species may evolve ways to co-exist, e.g. feeding at different times or using different foraging patterns. MacArthur showed that five closely related species of warblers on the same tree co-existed because of behavioural differences in foraging.
Worked example
State Gause's competitive exclusion principle. How do MacArthur's warblers show that it does not always hold? (3 marks)
Try it first, then show the solutionSolution
- Two closely related species competing for the same resources cannot co-exist indefinitely; the competitively inferior one is eventually eliminated. (1)
- This may hold only when resources are limiting; species may instead evolve ways to co-exist, such as resource partitioning. (1)
- MacArthur found five closely related warbler species living on the same tree, avoiding competition by differences in their foraging behaviour. (1)
Answer: Inferior competitor eliminated; but warblers co-exist by partitioning resources through different foraging.
- Parasitism, commensalism and mutualism
- NCERT section 11.1.4 Population Interactions (parasitism, commensalism, mutualism)
Parasitism (+ −): free lodging and meals, so it has evolved in many groups.
- Many parasites are host-specific, and host and parasite co-evolve.
- Adaptations: loss of unnecessary sense organs, adhesive organs or suckers, loss of the digestive system, high reproductive capacity.
- Complex life cycles with intermediate hosts or vectors: the human liver fluke (a trematode) needs two intermediate hosts, a snail and a fish; the malarial parasite needs a mosquito vector.
- Most parasites harm the host: reduce survival, growth, reproduction and population density, and make it more vulnerable to predation.
- Ectoparasites feed on the outside: lice on humans, ticks on dogs, copepods on marine fish, and Cuscuta, a plant parasite on hedge plants that has lost its chlorophyll and leaves. (The female mosquito is not considered a parasite though it needs our blood for reproduction: it does not live on or in us.)
- Endoparasites live inside (liver, kidney, lungs, RBCs); they have more complex life cycles, simplified bodies and high reproductive potential.
- Brood parasitism: the parasitic bird lays eggs in the host's nest for the host to incubate; its eggs have evolved to resemble the host's in size and colour. Example: cuckoo (koel) and crow, in spring to summer.
Commensalism (+ 0):
- Orchid growing as an epiphyte on a mango branch.
- Barnacles on the back of a whale.
- Cattle egret and grazing cattle: cattle stir up insects that egrets catch.
- Clown fish among the stinging tentacles of a sea anemone: the fish gets protection; the anemone gets no apparent benefit.
Mutualism (+ +):
- Lichens: fungus + photosynthesising algae or cyanobacteria.
- Mycorrhizae: fungi help roots absorb nutrients; the plant gives carbohydrates.
- Plant–animal mutualism: plants pay pollinators with pollen and nectar, and seed dispersers with fruits; systems must guard against 'cheaters' (nectar thieves), so partners often co-evolve.
- Fig and wasp: a one-to-one relationship; a fig species is pollinated only by its partner wasp. The female wasp uses the fruit as an egg-laying site and its developing seeds to feed larvae, pollinating the fig while searching for egg-laying sites.
- Orchids: many floral patterns attract the right pollinators (bees, bumblebees). The Mediterranean orchid Ophrys uses 'sexual deceit': one petal resembles a female bee; males pseudocopulate with the flower and carry pollen to another flower. If the female bee's colour patterns change, the orchid must co-evolve to keep pollinated.
Amensalism (− 0): one species is harmed, the other unaffected (named in NCERT's table).
Worked example
Name the interaction and justify: (a) orchid on a mango branch, (b) cuckoo laying eggs in a crow's nest, (c) fig and fig wasp, (d) Cuscuta on a hedge plant. (2 marks)
Try it first, then show the solutionSolution
- (a) Commensalism: the orchid gains a place to grow; the mango is unaffected. (b) Brood parasitism: the crow raises the cuckoo's young at its own cost. (1)
- (c) Mutualism: the wasp pollinates the fig; the fig provides an egg-laying site and seeds for larvae. (d) Parasitism (ectoparasite): Cuscuta draws nutrition from the host. (1)
Answer: (a) commensalism (b) brood parasitism (c) mutualism (d) parasitism.
Organisms and Populations in real life
Each concept, met in an everyday situation. Read the situation, answer the question in your own words, then compare with the model answer. The one-line hook is what to remember.
Population interactions: predation
Suppose an ornamental plant from another continent is planted in a town park and within a few years it has spread over nearby farmland and grazing land.
Explain why it spreads so fast and suggest a biological solution, using an NCERT example.
Try it first, then show the solutionSolution
- In its new home the exotic species has none of its natural predators, so its population is not kept in check: it becomes invasive.
- The prickly pear cactus in Australia spread over millions of hectares in the 1920s for this reason.
- It was controlled only by introducing a cactus-feeding moth from its native habitat; a similar natural enemy could be considered after careful study.
Answer: No natural predators let it spread; introducing a specific natural enemy (biocontrol) can control it.
Memory hook: No enemy, no brake.
Logistic growth and carrying capacity
Imagine 50 rabbits are released on an island with good grass but limited area.
Describe how their numbers will change over the years.
Try it first, then show the solutionSolution
- At first, growth is slow (lag phase), then rapid (acceleration) while food is plentiful.
- As grass and space run short, competition increases and growth slows (deceleration).
- Numbers level off at the island's carrying capacity K (asymptote): an S-shaped curve.
Answer: Logistic (S-shaped) growth levelling off at the carrying capacity.
Memory hook: Slow, fast, slow, stop: the S-curve.
Population density and its measurement
Suppose forest officials want to know how many tigers live in a reserve where tigers are rarely seen.
How can they estimate the number?
Try it first, then show the solutionSolution
- Direct counting is impossible for shy, wide-ranging animals.
- They use indirect evidence such as pug marks and faecal pellets to estimate numbers.
- Such estimates are compared over years to see whether the population is rising or falling.
Answer: By indirect census using pug marks and faecal pellets.
Memory hook: Count the clues, not the cats.
Exponential growth
Imagine a single Paramecium in a jar with unlimited food, dividing once every day.
How many would there be after 10 days and after 20 days?
Try it first, then show the solutionSolution
- Each division doubles the number, so after n days there are 2ⁿ individuals.
- After 10 days: 2¹⁰ = 1024.
- After 20 days: 2²⁰ = 1024 × 1024 = 1,048,576 (check: about a million, just 10 more doublings).
Answer: 1024 after 10 days; 1,048,576 after 20 days.
Memory hook: Ten doublings ≈ a thousand times.
Topics in this chapter
Organisms and Populations: key facts
- Per capita rates
- Lotus: 8/20 = 0.4; fruit flies: 4/40 = 0.1.
- Change in population density
- B births, I immigrants, D deaths, E emigrants.
- Exponential growth
- J-shaped curve; e = 2.71828.
- Doubling time
- T = doubling time.
- Logistic growth
- S-shaped curve; growth fastest at N = K/2; stops at N = K.
- Interactions
- Predation, parasitism and commensalism involve close living.
Organisms and Populations: diagrams to practise
Practise each one on paper: draw it from the checklist, then tick off every label.
Age pyramids
Draw age pyramids for expanding, stable and declining populations.
Draw
- Three pyramids side by side, each split vertically into males (left) and females (right).
- Each with three bands from bottom to top: pre-reproductive, reproductive, post-reproductive.
- Expanding: widest at the base (triangular). Stable: base about equal to the reproductive band (bell). Declining: narrow base (urn).
Label
- Pre-reproductive
- Reproductive
- Post-reproductive
- Males
- Females
- Expanding
- Stable
- Declining
Watch out: The base width compared with the middle decides the label.
Population growth curves
Draw exponential and logistic growth curves on one graph.
Draw
- Axes: population density (N) on y; time (t) on x.
- Curve a: J-shaped, rising ever more steeply (dN/dt = rN).
- Curve b: S-shaped, levelling off at a horizontal dashed line marked K (dN/dt = rN(K − N)/K).
- Mark lag, acceleration, deceleration and asymptote on curve b.
Label
- Population density (N)
- Time (t)
- Exponential (J-shaped)
- Logistic (S-shaped)
- Carrying capacity (K)
- Lag phase
- Asymptote
Watch out: Write both equations next to their curves.
Factors changing population density
Show the four processes that change population density.
Draw
- A central box labelled 'Population density (N)'.
- Two arrows in: natality (B) and immigration (I).
- Two arrows out: mortality (D) and emigration (E).
- Write Nₜ₊₁ = Nₜ + [(B + I) − (D + E)] below.
Label
- Natality (B)
- Immigration (I)
- Mortality (D)
- Emigration (E)
- Population density
Watch out: Use + signs on incoming arrows and − signs on outgoing ones.
Fig–wasp mutualism
Show the mutualism between a fig and its wasp.
Draw
- A fig inflorescence with a female wasp entering.
- Wasp pollinating flowers while searching for egg-laying sites.
- Wasp laying eggs in the fig; larvae feeding on some developing seeds.
Label
- Fig inflorescence
- Female wasp
- Pollination
- Egg-laying site
- Developing seeds (larval food)
Watch out: Add the signs (+, +) and the note 'one-to-one relationship'.
How the board asks Organisms and Populations
The question patterns to expect, and the method that works for each.
| Question type | How it is asked | Method |
|---|---|---|
| Population numericals | Calculate birth or death rate, population after a period using B, I, D, E, r from doubling time, dN/dt in exponential or logistic growth. | Write the formula, substitute with units, and check by a second route (step-by-step addition or back-substitution). |
| Growth curves | Draw and compare J- and S-shaped curves; mark K; explain phases; which is more realistic and why. | Label axes (N against time), K line, lag, acceleration, deceleration, asymptote. |
| Age pyramids | Identify expanding, stable or declining populations from pyramid shapes; predict future growth. | Compare the width of the pre-reproductive base with the reproductive band. |
| Interactions | Name the interaction for examples (orchid–mango, cuckoo–crow, fig–wasp, Balanus–Chthamalus, cattle egret–cattle); explain Gause's principle, resource partitioning, competitive release, plant defences, Monarch butterfly, Pisaster. | Give the +/−/0 signs, the name and the NCERT example. |
| Measuring density | Choose a suitable measure (cover, biomass, relative density, pug marks) for a situation. | Justify why counting is unsuitable in that case. |
Tricks to remember Organisms and Populations
Short memory aids. Say each one aloud once, then use it on a question the same day.
B-I up, D-E down
Births and Immigration add; Deaths and Emigration subtract: Nₜ₊₁ = Nₜ + (B + I) − (D + E).
Use it when: Population change numericals.
J for 'Jungle with no limits', S for 'Stops at K'
Exponential = J-shaped, unlimited resources; logistic = S-shaped, levels off at carrying capacity K.
Use it when: Comparing growth curves.
Pyramid shapes: Triangle, Bell, Urn
Broad base = expanding; bell = stable; urn (narrow base) = declining.
Use it when: Age pyramid questions.
Signs table: 'MC-PP-CA'
Mutualism ++, Competition −−, Predation +−, Parasitism +−, Commensalism +0, Amensalism −0.
Use it when: Interaction classification.
Barnacles: 'Big Balanus Bullies'
Larger Balanus excludes smaller Chthamalus in Connell's Scottish coast study.
Use it when: Competition examples.
Five warblers, one tree
MacArthur: different foraging behaviour (resource partitioning) lets them co-exist.
Use it when: Exceptions to competitive exclusion.
Organisms and Populations: board-level solved questions
Ordered from board level to HOTS. Cover the solution, write your own, then compare step by step.
Example 1: Identify the interaction · 1 mark · MCQBoard level
The interaction between the cattle egret and grazing cattle is an example of:
(a) mutualism (b) commensalism (c) parasitism (d) competition
Try it first, then show the solutionSolution
- Egrets benefit from insects flushed out by cattle.
- Cattle neither gain nor lose.
Answer: (b) commensalism
Example 2: Competitive release · 1 mark · Assertion-reasonHarder board level
Assertion (A): Chthamalus expands its range in the intertidal zone when Balanus is removed.
Reason (R): Balanus is the competitively superior barnacle that excludes Chthamalus.
(a) Both A and R are true and R is the correct explanation of A.
(b) Both A and R are true but R is not the correct explanation of A.
(c) A is true but R is false.
(d) A is false but R is true.
Try it first, then show the solutionSolution
- Connell's work showed Balanus excludes Chthamalus.
- Removing a superior competitor lets the restricted species expand (competitive release).
Answer: (a)
Example 3: Exponential growth calculation · 2 marks · Very short answerHarder board level
A bacterial population of 1000 cells grows exponentially with r = 0.2 per hour. Using Nₜ = N₀e^(rt), calculate the population after 5 hours (e = 2.718). (2 marks)
Try it first, then show the solutionSolution
- rt = 0.2 × 5 = 1, so Nₜ = 1000 × e¹ = 1000 × 2.718 = 2718 cells. (1)
- Check with the small-step idea: growing about 20% per hour compounding continuously for 5 hours gives a factor e ≈ 2.72 (compounding 20% hourly in steps gives 1.2⁵ ≈ 2.49, slightly less, as expected). (1)
Answer: About 2718 cells.
Example 4: Logistic peak growth · 3 marks · Short answerHOTS / competency
For a population with r = 0.4 per year and K = 600, calculate dN/dt at N = 200, 300 and 400. At which N is growth fastest, and why? (3 marks)
Try it first, then show the solutionSolution
- N = 200: 0.4 × 200 × (400/600) = 80 × 0.667 ≈ 53.3. N = 300: 0.4 × 300 × (300/600) = 120 × 0.5 = 60. N = 400: 0.4 × 400 × (200/600) = 160 × 0.333 ≈ 53.3. (1½)
- Growth is fastest at N = 300 = K/2. Check: values on either side (200 and 400) are equal and lower, so 300 is the peak. (1)
- At K/2, there are many individuals to reproduce while resources are still only half used; beyond this, the (K − N)/K brake dominates. (½)
Answer: 53.3, 60 and 53.3 per year; fastest at N = K/2 = 300.
Example 5: Age pyramid prediction · 2 marks · Very short answerBoard level
Suppose a country's age pyramid has a very broad base of children under 15 and a narrow top. Predict its population trend and explain what this means for future resource needs. (2 marks)
Try it first, then show the solutionSolution
- A broad pre-reproductive base means many individuals will soon enter the reproductive age: an expanding (growing) population. (1)
- Future needs for food, schools, jobs and housing will rise, so planning and population control measures are needed. (1)
Answer: Expanding population; rising future demand for resources.
Example 6: Defences and co-evolution · 5 marks · Long answerHarder board level
(a) How does the Monarch butterfly protect itself from birds? (1)
(b) Explain sexual deceit in Ophrys and why it requires co-evolution. (2)
(c) Give two examples of plant chemicals that act as defences, and the source of one. (2) (5 marks)
Try it first, then show the solutionSolution
- (a) It is highly distasteful to birds because of a chemical it acquires as a caterpillar by feeding on a poisonous weed. (1)
- (b) One petal of the Ophrys flower resembles a female bee in size, colour and markings; male bees pseudocopulate with it and are dusted with pollen, which they carry to the next flower. (1)
- If the female bee's colour pattern changes during evolution, pollination success falls unless the orchid co-evolves to maintain the resemblance. (1)
- (c) Cardiac glycosides from Calotropis (cattle and goats avoid it). (1)
- Nicotine, caffeine, quinine, strychnine or opium are produced by plants as defences against grazers and browsers. (1)
Answer: Distasteful chemical from food plant; petal mimics female bee, needing co-evolution; cardiac glycosides (Calotropis), nicotine, caffeine etc.
Example 7: Doubling and r · 2 marks · Very short answerHarder board level
Population A doubles in 2 years and population B in 10 years, both growing exponentially. Calculate r for each and state which has the higher Darwinian fitness. (2 marks)
Try it first, then show the solutionSolution
- r = 0.693 ÷ T: A: 0.693 ÷ 2 ≈ 0.347 per year; B: 0.693 ÷ 10 ≈ 0.069 per year. Check: e^(0.347 × 2) = e^0.693 = 2 and e^(0.069 × 10) ≈ e^0.69 ≈ 2. (1)
- A has the higher r, hence higher reproductive (Darwinian) fitness. (1)
Answer: r(A) ≈ 0.347, r(B) ≈ 0.069 per year; A is fitter.
Example 8: Starfish removal · 3 marks · Short answerHOTS / competency
Suppose in a hypothetical rocky shore study, removing a starfish predator led the number of invertebrate prey species to fall from 15 to 4 within a year. Explain the result and name the type of interaction among the prey. (3 marks)
Try it first, then show the solutionSolution
- The starfish kept the populations of its prey species in check, so no single prey could monopolise space and food. (1)
- Without the predator, the superior competitors among the prey multiplied and eliminated the weaker ones: interspecific competition, as in the Pisaster experiment. (1)
- So predators maintain species diversity by reducing the intensity of competition among prey; 11 of 15 species were lost here. (1)
Answer: Predator loss intensified competition among prey, causing exclusion of 11 species; predators maintain diversity.
Case-study practice (Section D style)
Read the situation, then answer every part. In the board paper this is a 4-mark question split into 1 + 2 + 1 marks.
Deer in a reserve
Suppose a forest reserve had 400 deer at the start of a year. During the year there were 80 births, 40 deaths, 20 deer moved in from a nearby forest and 10 left. The reserve's carrying capacity is estimated at 600 deer.
(i) · 1 mark
Calculate the population at the end of the year.
Answer
Answer: 400 + (80 + 20) − (40 + 10) = 450.
Check stepwise: 400 + 80 = 480; − 40 = 440; + 20 = 460; − 10 = 450.
(ii) · 2 marks
Calculate the birth rate and death rate, and explain what happens to growth as numbers approach 600.
Answer
Answer: Birth rate 80/400 = 0.2; death rate 40/400 = 0.1 per deer per year. As N approaches K = 600, resources become limiting, competition increases and growth slows (logistic).
Rates (1); logistic slowing near K (1).
(iii) · 1 mark
Which type of growth curve will the deer population most likely show?
Answer
Answer: An S-shaped (sigmoid) logistic curve levelling off at K.
Resources in the reserve are limited.
Birds on one tree
Suppose a student observes five closely related warbler species feeding on the same tall tree: some feed at the top, some in the middle, some near the trunk, and some at the outer twigs.
(i) · 1 mark
Which principle predicts that closely related species competing for the same resource cannot co-exist?
Answer
Answer: Gause's Competitive Exclusion Principle.
The inferior competitor should eventually be eliminated.
(ii) · 2 marks
Explain how the warblers co-exist, and who first showed this.
Answer
Answer: By resource partitioning: different foraging positions and behaviours reduce competition; MacArthur showed this with five warbler species.
Mechanism (1); MacArthur (1).
(iii) · 1 mark
Under what condition does Gause's principle hold?
Answer
Answer: When resources are limiting.
Recent studies show co-existence is possible otherwise.
Where the marks are
How a typical answer is split into step marks. Show every step: a right final answer alone rarely earns full marks.
If 4 out of 40 fruit flies in a laboratory population die in a week, and 12 new flies emerge, calculate the death rate, birth rate and the population at the end of the week. (2 marks) (2 marks)
| Step | Marks |
|---|---|
| Death rate = 4/40 = 0.1 per fly per week; birth rate = 12/40 = 0.3 per fly per week. | 1 |
| Population = 40 + 12 − 4 = 48 (check: 40 × (1 + 0.3 − 0.1) = 48). | 1 |
Distinguish between exponential and logistic growth with equations and curves. (3 marks) (3 marks)
| Step | Marks |
|---|---|
| Exponential: unlimited resources; dN/dt = rN; J-shaped curve. | 1 |
| Logistic: limited resources; dN/dt = rN(K − N)/K; S-shaped (sigmoid) curve with lag, acceleration, deceleration and asymptote at K. | 1 |
| Logistic is more realistic because resources become limiting; the population levels off at carrying capacity. | 1 |
(a) Explain three roles of predators in an ecosystem with examples. (3)
(b) Describe two morphological or chemical defences of plants against herbivores. (2) (5 marks) (5 marks)
| Step | Marks |
|---|---|
| (a) Conduits of energy from plants to higher trophic levels. | 1 |
| Keep prey populations in check: prickly pear cactus in Australia was controlled by a cactus-feeding moth; biocontrol relies on this. | 1 |
| Maintain species diversity by reducing competition among prey: removing Pisaster led to extinction of over 10 invertebrate species. | 1 |
| (b) Morphological: thorns in Acacia and cactus. | 1 |
| Chemical: cardiac glycosides in Calotropis; nicotine, caffeine, quinine, strychnine and opium deter herbivores. | 1 |
Where students lose marks in Organisms and Populations
The slips examiners see most often, and what to write instead.
Mistake: Using total numbers instead of per capita rates
Wrong working
8 lotus plants were born, so the birth rate is 8.
Right working
Birth rate = 8/20 = 0.4 offspring per lotus per year.
Do this: Divide by the population size and give units (per individual per unit time).
Usually costs: 1 mark.
Mistake: Writing the logistic equation without the (K − N)/K factor or swapping K and N
Do this: dN/dt = rN(K − N)/K; check that growth becomes zero when N = K.
Usually costs: 1 mark.
Mistake: Calling the orchid on a mango tree a parasite
Do this: The orchid is an epiphyte using the branch for support; the mango is unaffected: commensalism.
Usually costs: 1 mark.
Mistake: Saying competition happens only between closely related species and only when resources are limiting
Do this: Unrelated species can compete (flamingoes and fishes for zooplankton), and interference competition can occur even with abundant resources.
Usually costs: 1 mark.
Mistake: Calling the female mosquito a parasite
Do this: NCERT notes the female mosquito is not considered a parasite even though it needs blood for reproduction (it does not live on or in the host).
Usually costs: ½ mark.
Mistake: Answering questions on abiotic factors or adaptations from this chapter
Do this: Organism and its environment, abiotic factors, responses and adaptations are not in the 2026-27 syllabus; focus on populations.
Usually costs: Time and marks spent on unasked content.
NCERT exercise guide: Organisms and Populations
What each exercise in the NCERT chapter tests, how to approach it, and a question of the same kind solved step by step. Questions here are written in our own words.
Exercises on population attributes and growth
What it tests: Attributes of populations, r from doubling in 3 years, logistic curve, three characteristics of a population, definitions of population and community.
How to approach it: Use r = ln 2 ÷ T for doubling; define with examples; draw the S-curve with K.
From per capita rates to next year's size
A colony of 800 cattle egrets has 200 births and 40 deaths in a year, with no migration. Find the per capita birth and death rates, r = b − d, and the expected size after one year. Which attribute here belongs to the population and not to any single egret?
Show the solutionSolution
- b = 200 ÷ 800 = 0.25 and d = 40 ÷ 800 = 0.05 per egret per year; r = 0.25 − 0.05 = 0.20.
- Nₜ₊₁ = 800 + (200 − 40) = 960. Check: 800 × (1 + 0.20) = 960.
- Birth rate and death rate are per capita measures of the whole group: an individual is born or dies, but has no birth rate.
Answer: b = 0.25, d = 0.05, r = 0.20; 960 egrets; birth and death rates are population attributes.
Exercises on interactions
What it tests: Plant defences, orchid on mango, principle of biological control, commensalism, parasitism, camouflage, mutualism, interspecific competition, best statement for parasitism.
How to approach it: Give the +/−/0 signs and an NCERT example for each term.
Why a biocontrol agent worked
Prickly pear cactus introduced into Australia spread over millions of hectares until a cactus-feeding moth from its native home was introduced. Explain why the cactus spread so fast and why the moth controlled it. What property should be checked in any agent before it is released?
Show the solutionSolution
- In Australia the cactus was an exotic species without its natural predators, so its population was not kept in check and it became invasive.
- The moth from its native habitat fed on the cactus, restoring predator–prey regulation and bringing the cactus down to manageable levels; biological pest control relies on this principle.
- The agent should be specific to the target pest, so that it does not harm useful or native species.
Answer: No natural predators let the cactus explode; its native moth restored predation; agents must be pest-specific.
Exercise on choosing the right statement
What it tests: Which statement best describes parasitism.
How to approach it: Match the signs (+, −).
Naming interactions with + / − / 0
Name the interaction and give its signs: (a) a cuckoo lays its eggs in a crow's nest and the crow raises the chicks, (b) a clownfish lives among the stinging tentacles of a sea anemone, (c) Balanus excludes Chthamalus from the intertidal rocks of the Scottish coast, (d) goats introduced on the Galapagos led to the extinction of the Abingdon tortoise.
Show the solutionSolution
- (a) Brood parasitism (+, −): the cuckoo gains, the crow loses effort.
- (b) Commensalism (+, 0): the clownfish gets protection from predators; the anemone does not appear to benefit.
- (c) Competition (−, −): the larger, competitively superior Balanus excludes the smaller Chthamalus.
- (d) Competition (−, −): goats with greater browsing efficiency outcompeted the tortoise within a decade.
Answer: (a) brood parasitism (+ −) (b) commensalism (+ 0) (c) and (d) competition (− −).
Organisms and Populations: previous year questions
- Asked in 7 of the 8 board papers we hold (2023 to 2026), on average 3.3 marks per paper; 12 questions in all, counting OR alternatives. In 4 of 4 sample papers.
Counted from the real papers on our previous year papers page, not estimated. Average marks are over every board paper we hold, with an OR pair counted once. Chapter tags are ours.
Solved board questions from Organisms and Populations
Real questions from recent papers. Try each one first, then open our step-by-step solution with marks per step.
2026, set 57/1/1, Q29 · 4 marks · Case-basedCompetency-based
The diagram below shows the distribution of two barnacle species, Chthamalus and Balanus on a rocky sea shore.
When Balanus is experimentally removed, Chthamalus expands its range in lower intertidal zone.
- (a)1 mark
Identify and define the ecological phenomenon demonstrated by this observation.
OR
(a)1 markState the principle that explains the elimination of one species.
- (b)1 mark
Two different species can compete for the same resource. Give another example of it.
- (c)2 marks
How do species avoid competition in nature ? Explain with an example.
Figure in the paper: Rocky sea shore diagram with Balanus balanoides and Chthamalus stellatus shown. Zones from highest tides to lowest tides: Upper intertidal zone – Balanus dessicates in this zone, allowing Chthamalus to thrive; Middle intertidal zone – where it can survive, Balanus outcompetes Chthamalus for space; Lower intertidal zone – Balanus is subject to predation in the lower tidal zone. See it in the official paper.
Try it first, then show our solutionSolution
- ½ mark
(a) The phenomenon is competitive release.
- ½ mark
Definition: a species whose distribution is restricted to a small area, because a competitively superior species is present, expands its range when the superior competitor is removed. Here Chthamalus spreads into the lower zones once Balanus is removed.
- 1 mark
(a) OR: Gause's competitive exclusion principle: two closely related species competing for the same resources cannot coexist indefinitely, and the competitively inferior one is eventually eliminated.
- 1 mark
(b) In some shallow South American lakes, visiting flamingos and resident fishes compete for the same food, zooplankton.
- 1 mark
(c) Species avoid competition by resource partitioning: they choose different times for feeding or different foraging patterns.
- 1 mark
Example: MacArthur showed that five closely related species of warblers living on the same tree avoid competition and coexist. They do this by behavioural differences in foraging, each feeding in a different part of the tree.
Answer: (a) Competitive release (or Gause's competitive exclusion principle); (b) flamingos and fishes competing for zooplankton in South American lakes; (c) resource partitioning, e.g. MacArthur's warblers foraging in different parts of the same tree
Where the marks are
- Names competitive release (½ mark)
- Correct definition (½ mark)
- OR: states Gause's competitive exclusion principle (1 mark)
- Example of interspecific competition, e.g. flamingos and fish for zooplankton (1 mark)
- Resource partitioning (1 mark)
- Example, e.g. MacArthur's warblers (1 mark)
2026, set 57/5/1, Q9 · 1 mark · MCQ
Choose a correct option that shows an interaction in which one species benefits while the other is neither harmed nor benefitted.
- (A)Mycorrhizal associations between fungi and roots of higher plants
- (B)Sea anemone and clownfish
- (C)Abingdon tortoises and goats in the Galapagos Island
- (D)Cuscuta on hedge plants
Try it first, then show our solutionSolution
- ½ mark
A +/0 interaction, where one species benefits and the other is unaffected, is called commensalism.
- ½ mark
The clownfish gains protection among the stinging tentacles of the sea anemone, and the anemone gets no benefit or harm. Mycorrhiza is mutualism, the tortoise–goat case is competition and Cuscuta is a parasite. The answer is (B).
Answer: (B) Sea anemone and clownfish
Where the marks are
- Identifies commensalism and chooses (B) (1 mark)
2026, set 57/5/1, Q27 · 3 marks · Short answer
Explain Gause's 'Competitive Exclusion Principle' with the help of a suitable example.
Try it first, then show our solutionSolution
- 1 mark
Statement: Gause's competitive exclusion principle states that two closely related species competing for the same limited resources cannot co-exist indefinitely.
- 1 mark
The competitively inferior species is eventually eliminated, because the superior competitor uses the limited resource more efficiently and dominates.
- 1 mark
Example: The Abingdon tortoise of the Galapagos Islands became extinct within about a decade after goats were introduced on the island. This was probably because the goats browsed more efficiently. (Another example: in some shallow South American lakes, visiting flamingoes and resident fishes compete for the same food, zooplankton.)
Answer: Closely related species competing for the same limited resource cannot co-exist indefinitely; the inferior one is eliminated. Example: Abingdon tortoise eliminated by introduced goats.
Where the marks are
- States that closely related species competing for the same limited resource cannot co-exist indefinitely (1 mark)
- States that the inferior competitor is eliminated (1 mark)
- Gives a suitable example, e.g. goats and Abingdon tortoise, or flamingoes and fishes (1 mark)
Every Organisms and Populations question, by year
- For 2027
Sample paper 2026-27: Q21(B) (2 marks, solved), Q28 (3 marks, solved)
- 2026
Set 57/1/1: Q29 (4 marks, solved)
Set 57/5/1: Q9 (1 mark, solved), Q27 (3 marks, solved)
Sample paper 2025-26: Q28 (3 marks, solved), Q33(A) (5 marks, solved)
- 2025
Set 57/1/1: Q30 (4 marks, solved)
Set 57/7/1: Q10 (1 mark, solved), Q33(b) (5 marks, solved)
Sample paper 2024-25: Q28 (3 marks, solved)
- 2024
Set 57/5/1: Q19 (2 marks, solved)
Sample paper 2023-24: Q30 (4 marks, solved)
- 2023
Set 57/1/1: Q3 (1 mark, solved), Q14 (1 mark, solved)
Set 57/5/1: Q5 (1 mark, solved), Q11 (1 mark, solved), Q18 (2 marks, solved)
Practice questions on Organisms and Populations
Write each answer on paper first. Open the hint only if you are stuck, and the answer only when you have finished.
Q1 · 1 mark · MCQBoard level
Which of the following is a (−, 0) interaction?
(a) Commensalism (b) Amensalism (c) Competition (d) ParasitismHint
One harmed, one unaffected.
Answer
(b) Amensalism
Q2 · 1 mark · Assertion-reasonBoard level
Assertion (A): In a logistic growth curve, population growth slows down as density approaches K.
Reason (R): The factor (K − N)/K approaches zero as N approaches K.
(a) Both A and R are true and R is the correct explanation of A.
(b) Both A and R are true but R is not the correct explanation of A.
(c) A is true but R is false.
(d) A is false but R is true.Hint
Look at the equation.
Answer
(a)
Q3 · 1 mark · MCQHarder board level
In a population of 200 individuals, 30 are born and 20 die in a year. The per capita birth rate is:
(a) 0.10 (b) 0.15 (c) 0.05 (d) 0.25Hint
Births ÷ N.
Answer
(b) 0.15 (30/200)
Q4 · 2 marks · Very short answerBoard level
Define population and community. Give one example of each. (2 marks)
Hint
One species versus many.
Answer
Population: individuals of one species in a defined area, sharing or competing for resources and potentially interbreeding, e.g. lotus plants in a pond (1). Community: populations of different species living and interacting in an area, e.g. the plants, animals and microbes of a pond (1).
Q5 · 2 marks · Very short answerHarder board level
Why is per cent cover or biomass a better measure than number for some populations? Give an NCERT example. (2 marks)
Hint
Banyan and Parthenium.
Answer
When individuals differ greatly in size, numbers misrepresent their importance (1). One huge banyan among 200 Parthenium plants would seem insignificant by count, though its canopy dominates; cover or biomass reflects its role (1).
Q6 · 2 marks · Very short answerBoard level
Explain brood parasitism with an example, and the adaptation of the parasite's eggs. (2 marks)
Hint
Koel and crow.
Answer
The parasitic bird lays eggs in the host's nest and lets the host incubate them, e.g. the cuckoo (koel) laying in a crow's nest (1). Its eggs have evolved to resemble the host's eggs in size and colour, reducing the chance of being detected and thrown out (1).
Q7 · 3 marks · Short answerHarder board level
List four adaptations of parasites and explain why the human liver fluke has a complex life cycle. (3 marks)
Hint
Lose, cling, reproduce.
Answer
Loss of unnecessary sense organs; adhesive organs or suckers; loss of the digestive system; high reproductive capacity (2). The liver fluke depends on two intermediate hosts, a snail and a fish, to reach and infect its primary host (1).
Q8 · 3 marks · Short answerHarder board level
Give three pieces of evidence that competition occurs in nature. (3 marks)
Hint
Tortoise, barnacles, flamingoes.
Answer
The Abingdon tortoise of the Galapagos went extinct within a decade of goats being introduced, apparently because goats browsed more efficiently (1). Competitive release: Connell showed the superior barnacle Balanus excludes Chthamalus on Scottish rocky coasts, and Chthamalus expands when Balanus is removed (1). Unrelated flamingoes and fishes compete for zooplankton in South American lakes (1).
Q9 · 5 marks · Long answerHarder board level
(a) Draw the logistic growth curve and label its phases. (2)
(b) Write its equation and explain each term. (2)
(c) Why is it more realistic than exponential growth? (1) (5 marks)Hint
S-curve with K.
Answer
(a) S-shaped curve of N against time with lag phase, acceleration, deceleration and asymptote at the dashed K line (2). (b) dN/dt = rN(K − N)/K, where N is population density at time t, r the intrinsic rate of natural increase, and K the carrying capacity; (K − N)/K is the fraction of resources still available (2). (c) Resources for most populations are finite and become limiting, so growth must level off (1).
Q10 · 3 marks · Short answerHOTS / competency
Suppose a lake has a population of 2000 fish with r = 0.1 per year and K = 10,000. A fishing company wants to harvest the maximum sustainable number each year. At about what population size should the fish be kept, and roughly how many can be harvested yearly at that size? (3 marks)
Hint
Logistic growth peaks at K/2.
Answer
Growth dN/dt = rN(K − N)/K is greatest at N = K/2 = 5000 (1). At N = 5000: dN/dt = 0.1 × 5000 × (5000/10,000) = 500 × 0.5 = 250 fish per year (1). Harvesting about 250 per year while holding the population near 5000 keeps it stable; check at N = 4000: 0.1 × 4000 × 0.6 = 240 and N = 6000: 0.1 × 6000 × 0.4 = 240, both lower (1).
Q11 · 2 marks · Very short answerHOTS / competency
A newly formed island is colonised by a species of lizard. In the first few years, which process contributes most to population growth, and why? (2 marks)
Hint
Special conditions.
Answer
Immigration (1). When a new habitat is being colonised, arrivals from elsewhere may add more individuals than births, which matter more only once a breeding population is established (1).
Q12 · 2 marks · Very short answerHarder board level
Explain with an example why predators are described as 'prudent'. (2 marks)
Hint
Over-exploitation.
Answer
If a predator were too efficient and over-exploited its prey, the prey could become extinct, and then the predator would also die out for lack of food (1). So natural predators do not wipe out their prey, keeping both populations going (e.g. predators regulating prey without eliminating them) (1).
Test your recall
Answer in your head or on paper first, then open the card. Pulling an answer out of memory makes it stick far better than re-reading.
1.Name four attributes of a population not found in an individual.Show answer
Birth rate, death rate, sex ratio and age distribution.
2.What is the r value of the Norway rat and the flour beetle?Show answer
0.015 and 0.12 respectively.
3.What was India's r value in 1981?Show answer
0.0205.
4.What is the shape of an exponential growth curve?Show answer
J-shaped.
5.What is carrying capacity?Show answer
The maximum population size a habitat's resources can support (K).
6.What is Darwinian fitness?Show answer
Reproductive fitness, a high r value.
7.Which organisms breed only once in their lifetime?Show answer
Pacific salmon fish and bamboo.
8.What percentage of insects are phytophagous?Show answer
Nearly 25%.
9.Which poisonous chemical does Calotropis produce?Show answer
Cardiac glycosides.
10.Why did the Abingdon tortoise become extinct?Show answer
Goats introduced to the Galapagos browsed more efficiently and out-competed it within a decade.
11.Name the two intermediate hosts of the human liver fluke.Show answer
A snail and a fish.
12.What is 'sexual deceit' in Ophrys?Show answer
One petal resembles a female bee, so male bees pseudocopulate with the flower and carry pollen between flowers.
Best order to study it
- Learn the definition of a population and its attributes; practise birth and death rate numericals and age pyramids.
- Learn ways of measuring population density with NCERT examples.
- Learn the four processes and the Nₜ₊₁ equation; practise numericals.
- Learn exponential and logistic growth with equations and curves; practise r and dN/dt calculations.
- Learn life history variation, then each interaction with its sign and NCERT examples.
Quick revision checklist
The night before the exam: can you do each of these without looking?
- Can you calculate per capita birth and death rates?
- Can you identify expanding, stable and declining age pyramids?
- Can you choose the right measure of density for a banyan tree, fish in a lake and tigers?
- Can you use Nₜ₊₁ = Nₜ + [(B + I) − (D + E)]?
- Can you derive r from a doubling time and use Nₜ = N₀e^(rt)?
- Can you draw J- and S-shaped curves and calculate logistic dN/dt?
- Can you name the six interactions with signs and an example each?
- Can you explain Gause's principle, competitive release, resource partitioning and plant defences?
Organisms and Populations: frequently asked questions
How many marks does Organisms and Populations carry in CBSE Class 12 Biology 2026-27?
It is part of Unit X, Ecology and Environment, which carries 10 of the 70 theory marks together with Ecosystem and Biodiversity and Conservation.
Which parts of the NCERT chapter are not in the syllabus?
Organism and its environment, the major abiotic factors (temperature, water, light, soil), responses to abiotic factors (regulate, conform, migrate, suspend) and adaptations. The syllabus covers population attributes, growth and interactions.
Do I need calculus for the growth equations?
No. You need to use the given equations: dN/dt = rN, Nₜ = N₀e^(rt) and dN/dt = rN(K − N)/K, substituting numbers. For doubling-time questions, r = 0.693 ÷ doubling time.
Why is logistic growth considered more realistic?
Resources for most populations are finite and become limiting sooner or later, so growth slows and levels off at the carrying capacity, as the logistic model predicts.
What is the difference between predation and parasitism if both are (+, −)?
A predator usually kills and eats its prey, transferring energy up trophic levels. A parasite lives on or in its host and draws nourishment from it, usually harming but not immediately killing it, often with host-specific adaptations.
Based on: CBSE Biology (044) syllabus 2026-27; NCERT Biology, Textbook for Class XII (Reprint 2026-27)