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BiologyCBSE Class 12 · Chapter 12

Ecosystem Class 12: Concepts, Pyramids, Numericals and Board Answers

Updated 14 October 2026 · Fact-checked

Ecosystem is Chapter 12 of CBSE Class 12 Biology and part of Unit X, Ecology and Environment (10 marks). The 2026-27 syllabus covers ecosystem structure and components, productivity (GPP, NPP, secondary productivity), decomposition, energy flow through food chains and trophic levels, and pyramids of number, biomass and energy.

What Ecosystem is about

An ecosystem is a functional unit of nature in which living organisms interact among themselves and with their physical environment. Ecosystems range from a small pond to a large forest or sea; the whole biosphere can be seen as a global ecosystem.

Types: terrestrial (forest, grassland, desert) and aquatic (pond, lake, wetland, river, estuary); man-made (crop fields, aquarium).

The chapter, as in the 2026-27 syllabus:
1. Structure: abiotic and biotic components, species composition and stratification; the pond as an example.
2. Productivity: primary production, GPP − R = NPP, secondary productivity; the biosphere's annual NPP.
3. Decomposition: detritus, fragmentation, leaching, catabolism, humification, mineralisation; factors controlling the rate.
4. Energy flow: sun → producers → consumers; PAR; food chains (grazing and detritus), food webs, trophic levels, standing crop, the 10 per cent law.
5. Ecological pyramids: number, biomass and energy; upright and inverted pyramids; limitations.

Not in the syllabus: ecological succession, nutrient cycling (carbon and phosphorus cycles) and ecosystem services (NCERT sections dropped).

Board questions often ask for GPP/NPP and 10 per cent law calculations, steps of decomposition, food chain versus food web, and drawing or explaining pyramids (especially why the pyramid of biomass in the sea is inverted and why the pyramid of energy is always upright).

Weightage: This chapter is part of Unit X, Ecology and Environment, which carries 10 of the 70 theory marks together with Organisms and Populations and Biodiversity and Conservation.Source: CBSE Biology (044) syllabus 2026-27, course structure, Unit X Ecology and Environment

In real board papers: asked in 8 of the 8 board papers we hold (2023 to 2026), on average 3.1 marks per paper. See the questions

Key concepts

Ecosystem structure and the pond as an example
NCERT section 12.1 Ecosystem – Structure and Function

Structure: interaction of biotic and abiotic components gives each ecosystem a characteristic physical structure.

  • Species composition: identification and listing of the plant and animal species of an ecosystem.
  • Stratification: vertical distribution of species at different levels; in a forest, trees occupy the top layer, shrubs the second, and herbs and grasses the bottom layers.

Functional aspects: the components work as a unit through productivity, decomposition, energy flow and nutrient cycling (nutrient cycles themselves are not in the syllabus).

A pond: a simple, fairly self-sustaining example:

  • Abiotic: water with dissolved inorganic and organic substances, rich soil deposits at the bottom; solar input, temperature cycle, day length and climate regulate its functioning.
  • Autotrophs (producers): phytoplankton, some algae, and floating, submerged and marginal plants.
  • Consumers: zooplankton, free-swimming and bottom-dwelling forms.
  • Decomposers: fungi, bacteria and flagellates, especially abundant at the bottom.

What the pond does (like any ecosystem and the biosphere):
1. Autotrophs convert inorganic into organic material using solar radiant energy.
2. Heterotrophs consume the autotrophs.
3. Dead matter is decomposed and mineralised, releasing nutrients for reuse.
4. Energy moves one way to higher trophic levels and is lost as heat.

Worked example

Identify the producers, consumers and decomposers of a pond, and state why energy flow in the pond is described as unidirectional. (2 marks)

Try it first, then show the solutionSolution
  1. Producers: phytoplankton, algae, floating, submerged and marginal plants; consumers: zooplankton, free-swimming and bottom-dwelling animals; decomposers: fungi, bacteria and flagellates at the bottom. (1)
  2. Energy goes from the sun to producers to consumers and is lost as heat at each step; it does not return to the producers, so the flow is one-way. (1)

Answer: Producers: phytoplankton and plants; consumers: zooplankton and animals; decomposers: fungi, bacteria, flagellates; energy is lost as heat and never cycles back.

Productivity
NCERT section 12.2 Productivity

A constant input of solar energy is the basic need of every ecosystem.

Primary production: the amount of organic matter (biomass) that plants make by photosynthesis in a unit area during a given period; expressed as weight (g m⁻²) or energy (kcal m⁻²).

Productivity: the rate of biomass production, in g m⁻² yr⁻¹ or kcal m⁻² yr⁻¹, so different ecosystems can be compared.

Gross and net primary productivity:

  • GPP: rate of production of organic matter during photosynthesis.
  • A large part of GPP is used by plants in respiration (R).
  • NPP = GPP − R: the biomass available to heterotrophs (herbivores and decomposers).

Secondary productivity: the rate of formation of new organic matter by consumers.

Factors affecting primary productivity:

  • the plant species of the area;
  • environmental factors (light, temperature, water);
  • availability of nutrients;
  • photosynthetic capacity of plants.

So productivity varies among ecosystems.

Global figures (NCERT): annual NPP of the whole biosphere is about 170 billion tons (dry weight). The oceans, despite covering about 70% of the surface, produce only 55 billion tons; the rest (about 115 billion tons) is on land. In aquatic ecosystems, light is the main limiting factor for productivity (it decreases with depth), and nutrients can also limit ocean productivity.

Worked example

A grassland has GPP of 2000 kcal m⁻² yr⁻¹ and plants use 800 kcal m⁻² yr⁻¹ in respiration. Calculate NPP and the percentage of GPP available to herbivores and decomposers. (2 marks)

Try it first, then show the solutionSolution
  1. NPP = GPP − R = 2000 − 800 = 1200 kcal m⁻² yr⁻¹. (1)
  2. Percentage = 1200 ÷ 2000 × 100 = 60%. Check: respiration uses 800/2000 = 40%, and 60% + 40% = 100%. (1)

Answer: NPP = 1200 kcal m⁻² yr⁻¹; 60% of GPP.

Decomposition
NCERT section 12.3 Decomposition

Decomposition: breakdown of complex organic matter by decomposers into inorganic substances such as carbon dioxide, water and nutrients. The earthworm is the 'farmer's friend' because it helps break down organic matter and loosens the soil.

Detritus: the raw material: dead plant remains (leaves, bark, flowers) and dead animal remains, including faecal matter.

Steps:
1. Fragmentation: detritivores (e.g. earthworm) break detritus into smaller particles.
2. Leaching: water-soluble inorganic nutrients go down into the soil horizon and precipitate as unavailable salts.
3. Catabolism: bacterial and fungal enzymes degrade detritus into simpler inorganic substances.
(These three steps work simultaneously on the detritus.)
4. Humification: accumulation of humus, a dark, amorphous substance, highly resistant to microbial action, decomposed extremely slowly; being colloidal, it is a reservoir of nutrients.
5. Mineralisation: humus is further degraded by some microbes, releasing inorganic nutrients.

Factors controlling the rate:

  • Chemical composition of detritus: slower if rich in lignin and chitin; faster if rich in nitrogen and water-soluble substances such as sugars.
  • Climate: temperature and soil moisture are the most important, acting through soil microbes. Warm and moist conditions favour decomposition; low temperature and anaerobiosis inhibit it, so organic matter builds up.
  • Decomposition is largely an oxygen-requiring process.

Worked example

Two leaf samples are buried in the same moist, warm soil: sample A is rich in lignin; sample B is rich in nitrogen and sugars. Which decomposes faster and why? What would happen if the soil were waterlogged and cold? (3 marks)

Try it first, then show the solutionSolution
  1. Sample B decomposes faster: detritus rich in nitrogen and water-soluble substances like sugars is broken down quickly. (1)
  2. Sample A is slower because lignin (like chitin) resists breakdown. (1)
  3. In waterlogged (anaerobic) and cold soil, microbial activity falls; decomposition is inhibited and organic matter builds up. (1)

Answer: B (nitrogen, sugars) decomposes faster; lignin slows A; cold, anaerobic soil inhibits decomposition.

Energy flow, food chains and trophic levels
NCERT section 12.4 Energy Flow

Source: except for deep-sea hydrothermal ecosystems, the sun is the only source of energy.

  • Of the incident solar radiation, less than 50% is photosynthetically active radiation (PAR).
  • Plants capture only 2–10% of the PAR, and this small amount sustains the entire living world.
  • Energy flow is unidirectional: sun → producers → consumers.
  • Ecosystems obey the second law of thermodynamics: they need a constant supply of energy to make the molecules they need and to counter the tendency towards disorder.

Producers: green plants; on land, herbaceous and woody plants; in water, phytoplankton, algae and higher plants.

Consumers (heterotrophs):

  • Primary consumers = herbivores (insects, birds, mammals on land; molluscs in water).
  • Secondary consumers = primary carnivores (eat herbivores).
  • Tertiary consumers = secondary carnivores.

Grazing food chain (GFC): Grass (producer) → Goat (primary consumer) → Man (secondary consumer).

Detritus food chain (DFC): begins with dead organic matter; made up of decomposers (mainly fungi and bacteria), also called saprotrophs. They secrete digestive enzymes that break dead matter into simple inorganic materials, which they absorb.

  • In aquatic ecosystems, the GFC is the major conduit of energy.
  • In terrestrial ecosystems, a much larger fraction of energy flows through the DFC.

Food web: the DFC and GFC are linked (some DFC organisms are prey of GFC animals; omnivores such as cockroaches and crows); these natural interconnections form a food web.

Trophic level: an organism's place in the food chain based on its source of food: producers 1st, herbivores 2nd, carnivores 3rd, and so on. A trophic level is a functional level, not a species: a sparrow is a primary consumer when eating seeds and fruits and a secondary consumer when eating insects and worms.

Standing crop: the mass of living material at a trophic level at a particular time, measured as biomass or number per unit area. Biomass is better measured as dry weight (more accurate, because water content varies).

10 per cent law: only about 10% of the energy at one trophic level is transferred to the next. This limits the number of trophic levels in a grazing food chain (producer, herbivore, primary carnivore, secondary carnivore).

Worked example

In a grazing food chain, producers fix 20,000 J of energy. Using the 10 per cent law, how much energy reaches (a) the herbivores, (b) the primary carnivores, (c) the secondary carnivores? Why are food chains rarely longer than 4–5 levels? (3 marks)

Try it first, then show the solutionSolution
  1. (a) 10% of 20,000 = 2000 J; (b) 10% of 2000 = 200 J; (c) 10% of 200 = 20 J. (1½)
  2. Check: 20,000 × (0.1)³ = 20,000 × 0.001 = 20 J for the fourth level. (½)
  3. So little energy remains after a few transfers (most is lost as heat) that it cannot support another level. (1)

Answer: (a) 2000 J (b) 200 J (c) 20 J; energy runs out after a few levels.

Ecological pyramids
NCERT section 12.5 Ecological Pyramids

Ecological pyramids show the food or energy relationship between trophic levels as number, biomass or energy. The base is the producers (first trophic level); the apex is the top consumer.

1. Pyramid of number:

  • Grassland: upright; NCERT's example: nearly 6 million plants support only 3 top carnivores.
  • Tree ecosystem: one big tree supports many insects, which support small birds, which support fewer large birds: the pyramid is inverted at the base (spindle-shaped).

2. Pyramid of biomass:

  • Usually upright: biomass drops sharply at higher levels (e.g. on land).
  • In the sea it is generally inverted: a small standing crop of phytoplankton supports a large standing crop of zooplankton (and fishes). This is not a paradox: phytoplankton reproduce and are eaten very fast, so their standing crop at any moment is small even though their production over time is large.

3. Pyramid of energy:

  • Always upright, never inverted: when energy passes from one trophic level to the next, some is always lost as heat.
  • Each bar shows the energy at a trophic level in a given time or annually per unit area.
  • NCERT's ideal pyramid notes that primary producers convert only about 1% of the energy in sunlight available to them into NPP.

Rules for calculating: include all organisms at a trophic level; a species can occupy more than one trophic level at the same time.

Limitations of ecological pyramids:
1. They do not account for the same species at two or more trophic levels.
2. They assume a simple food chain, which almost never exists in nature; they cannot show a food web.
3. Saprophytes (decomposers) get no place, although they play a vital role.

Worked example

Why is the pyramid of biomass in the sea inverted, whereas the pyramid of energy can never be inverted? (3 marks)

Try it first, then show the solutionSolution
  1. In the sea, the standing crop (biomass at one time) of phytoplankton is small, while zooplankton and fish standing crops are larger: the biomass pyramid is inverted. (1)
  2. Phytoplankton multiply and are consumed very rapidly, so a small standing crop can support a larger consumer biomass over time. (1)
  3. Energy is measured as flow over time; at each transfer some energy is lost as heat, so each higher level always has less energy: the energy pyramid is always upright. (1)

Answer: Small but fast-renewing phytoplankton standing crop inverts the biomass pyramid; energy is always lost as heat at each step, so the energy pyramid is always upright.

Ecosystem in real life

Each concept, met in an everyday situation. Read the situation, answer the question in your own words, then compare with the model answer. The one-line hook is what to remember.

Decomposition

Suppose a gardener makes two compost heaps: one of fresh vegetable peels kept moist and turned often, and one of dry woody branches left in a cold, waterlogged corner.

Which heap will turn into compost faster and why?

Try it first, then show the solutionSolution
  1. Vegetable peels are rich in nitrogen and sugars, which microbes break down quickly; woody branches are rich in lignin, which resists breakdown.
  2. Keeping the heap moist and turning it supplies water and oxygen; decomposition is largely oxygen-requiring and favoured by warm, moist conditions.
  3. The cold, waterlogged heap is anaerobic and cold, which inhibits microbial activity.

Answer: The moist, aerated vegetable heap composts faster; the woody, cold, waterlogged heap decomposes very slowly.

Memory hook: Green, warm, wet and airy: fast rot.

Energy flow, food chains and trophic levels

Imagine a student asks why a vegetarian diet could feed more people from the same farmland than a meat-based diet.

Explain using the 10 per cent law.

Try it first, then show the solutionSolution
  1. Only about 10% of the energy at one trophic level passes to the next.
  2. Eating plants directly (second trophic level) gets about 10% of crop energy; eating animals that ate the crops (third level) gets only about 1%.
  3. So the same crop energy can support about ten times as many people when eaten directly.

Answer: Each extra trophic level loses about 90% of energy, so eating at a lower level feeds more people.

Memory hook: Every step up costs nine-tenths.

Ecological pyramids

Suppose you count the living things on one large mango tree: 1 tree, 5000 insects, 30 small birds and 2 hawks.

What shape is the pyramid of numbers and why?

Try it first, then show the solutionSolution
  1. Producers: 1 tree; herbivores: 5000 insects; primary carnivores: 30 small birds; secondary carnivores: 2 hawks.
  2. The bar for the tree (1) is narrower than that for insects (5000), so the base is inverted, then the pyramid narrows again upward.
  3. One huge tree has enough biomass to support thousands of small herbivores.

Answer: A spindle-shaped (base-inverted) pyramid of numbers.

Memory hook: One tree, many bugs: numbers can lie, energy cannot.

Productivity

Imagine a student notes that oceans cover about 70% of the earth yet produce only 55 of the 170 billion tons of annual NPP.

Calculate the ocean's share and suggest a reason for it.

Try it first, then show the solutionSolution
  1. Share = 55 ÷ 170 × 100 ≈ 32%; land gives 115 ÷ 170 ≈ 68% (check: 32% + 68% = 100%).
  2. In water, light becomes limiting because it decreases with depth, so photosynthesis is confined to surface layers.
  3. Nutrient availability can also limit productivity in open oceans.

Answer: About 32% of global NPP from about 70% of the surface; light (and nutrients) limit ocean productivity.

Memory hook: Big ocean, thin green skin.

Topics in this chapter

Ecosystem: key facts

Net primary productivity
R = energy or biomass used by plants in respiration.
Units of productivity
Primary production (not rate) is in g m⁻² or kcal m⁻².
Ten per cent law
Limits the number of trophic levels.
Solar energy capture
About 1% of sunlight available to producers becomes NPP (NCERT's ideal energy pyramid).
Global NPP
Oceans cover about 70% of the surface but give only about a third of NPP.
Decomposition steps
First three act together on detritus.

Ecosystem: diagrams to practise

Practise each one on paper: draw it from the checklist, then tick off every label.

Decomposition cycle in a terrestrial ecosystem

Draw a diagram of the decomposition cycle.

Draw

  1. Detritus (dead leaves, remains, faecal matter) on the soil surface.
  2. Arrows showing fragmentation by detritivores (earthworm), leaching of soluble nutrients into the soil, and catabolism by bacteria and fungi.
  3. Humus forming in the soil, then mineralisation releasing inorganic nutrients taken up by plant roots.
  4. Plant shedding leaves back as detritus to close the cycle.

Label

  • Detritus
  • Fragmentation (detritivores)
  • Leaching
  • Catabolism (bacteria, fungi)
  • Humification (humus)
  • Mineralisation
  • Inorganic nutrients
  • Plant uptake

Watch out: Show the first three steps acting together on the detritus.

Trophic levels and energy flow

Show trophic levels and energy flow through a grazing food chain.

Draw

  1. Sun at the top left with arrows to producers.
  2. Boxes in a column: producers (1st), herbivores (2nd), primary carnivores (3rd), secondary carnivores (4th).
  3. Arrows between boxes getting thinner (10% passed on) with side arrows for heat lost (respiration).
  4. Arrows from every level to decomposers (detritus).

Label

  • Sun
  • Producers
  • Herbivores
  • Primary carnivores
  • Secondary carnivores
  • Heat loss
  • Decomposers
  • 10% transfer

Watch out: Write energy values (e.g. 10,000 → 1000 → 100 → 10 J) beside the boxes.

Ecological pyramids

Draw pyramids of number (grassland and tree), biomass (land and sea) and energy.

Draw

  1. Number, grassland: wide base (producers) narrowing to a tiny top (3 top carnivores).
  2. Number, tree: narrow base (1 tree), wide second bar (insects), narrowing upward (birds): spindle shape.
  3. Biomass, sea: narrow base (phytoplankton), wider bar above (zooplankton): inverted.
  4. Energy: always upright, each bar about one-tenth of the one below.

Label

  • Producers (PC)
  • Primary consumers (PC)
  • Secondary consumers (SC)
  • Tertiary consumers (TC)
  • Upright
  • Inverted
  • Spindle-shaped

Watch out: Always put producers at the base, whatever the shape.

How the board asks Ecosystem

The question patterns to expect, and the method that works for each.

Question typeHow it is askedMethod
Productivity and energy numericalsCalculate NPP from GPP and R; energy at a given trophic level using the 10 per cent law; percentage of PAR or sunlight captured; ocean versus land NPP.Write the formula, substitute with units, then check (e.g. NPP + R = GPP; multiply back by 10).
DecompositionSteps in order with definitions; factors affecting rate; humus and its role; why decomposition is slow in cold or waterlogged soil.Name the agent for each step (earthworm, water, microbial enzymes) and link rate to chemistry and climate.
Food chains and websGrazing versus detritus food chain; food chain versus food web; trophic level of organisms like the sparrow or humans; standing crop.Use NCERT examples and remember that a trophic level is functional, not a species.
Ecological pyramidsDraw pyramids of number (grassland, tree), biomass (land, sea) and energy; explain inversions; limitations.Label trophic levels from the base; state why each is upright or inverted.
Ecosystem structureComponents of a pond; stratification; species composition; functional aspects.Give abiotic, producers, consumers and decomposers with examples.

Tricks to remember Ecosystem

Short memory aids. Say each one aloud once, then use it on a question the same day.

  • GPP − R = NPP: 'Gross minus Respiration = Net'

    Think of salary: gross pay minus expenses (respiration) = net pay available for others (herbivores).

    Use it when: Productivity numericals.

  • Decomposition: 'Fat Lions Can't Hunt Mice'

    Fragmentation, Leaching, Catabolism, Humification, Mineralisation.

    Use it when: Order of decomposition steps.

  • 10% law: 'Drop a zero'

    Each step up the food chain, drop one zero: 10,000 → 1000 → 100 → 10.

    Use it when: Energy at trophic levels.

  • GFC in water, DFC on land

    Aquatic: grazing food chain is the main conduit. Terrestrial: more energy flows through the detritus food chain.

    Use it when: Comparing food chains.

  • Energy pyramid: 'Never Upside down'

    Energy is always lost as heat, so the energy pyramid is always upright; numbers (tree) and biomass (sea) can be inverted.

    Use it when: Pyramid questions.

  • Slow rot: 'Lignin and Chitin are Lazy'

    Lignin- and chitin-rich detritus decomposes slowly; nitrogen and sugars speed it up.

    Use it when: Factors affecting decomposition.

Ecosystem: board-level solved questions

Ordered from board level to HOTS. Cover the solution, write your own, then compare step by step.

Example 1: Second trophic level in a lake · 1 mark · MCQBoard level

The second trophic level in a lake is occupied by:
(a) phytoplankton (b) zooplankton (c) benthos (d) fishes

Try it first, then show the solutionSolution
  1. Phytoplankton are producers (first level).
  2. Zooplankton feed on them (primary consumers).

Answer: (b) zooplankton

Example 2: Inverted pyramid assertion · 1 mark · Assertion-reasonHarder board level

Assertion (A): The pyramid of biomass in the sea is generally inverted.
Reason (R): The biomass of phytoplankton far exceeds that of fishes.
(a) Both A and R are true and R is the correct explanation of A.
(b) Both A and R are true but R is not the correct explanation of A.
(c) A is true but R is false.
(d) A is false but R is true.

Try it first, then show the solutionSolution
  1. A is true.
  2. R is the reverse of the truth: fish biomass exceeds the standing crop of phytoplankton.

Answer: (c)

Example 3: Energy at the top · 2 marks · Very short answerHarder board level

Suppose 1,000,000 J of sunlight reaches a field and producers convert 1% of it into NPP. Using the 10 per cent law, how much energy reaches a secondary carnivore (fourth trophic level)? (2 marks)

Try it first, then show the solutionSolution
  1. Producers: 1% of 1,000,000 = 10,000 J; herbivores 1000 J; primary carnivores 100 J; secondary carnivores 10 J. (1)
  2. Check: 1,000,000 × 0.01 × (0.1)³ = 10,000 × 0.001 = 10 J. (1)

Answer: 10 J.

Example 4: Working backwards · 3 marks · Short answerHOTS / competency

A secondary carnivore receives 50 kJ from its food. Assuming the 10 per cent law, how much energy was available at the producer level? If the producers' respiration used 30% of GPP, what was the GPP? (3 marks)

Try it first, then show the solutionSolution
  1. Secondary carnivore is the 4th level: producer energy (NPP available) = 50 × 10 × 10 × 10 = 50,000 kJ. (1)
  2. This is NPP = 70% of GPP (since R = 30%), so GPP = 50,000 ÷ 0.7 ≈ 71,429 kJ. (1)
  3. Check: R = 0.3 × 71,429 ≈ 21,429; GPP − R = 71,429 − 21,429 = 50,000 kJ = NPP. (1)

Answer: Producer NPP 50,000 kJ; GPP ≈ 71,430 kJ.

Example 5: Food chains compared · 3 marks · Short answerBoard level

Differentiate between the grazing food chain and the detritus food chain, and state which carries more energy in a forest. (3 marks)

Try it first, then show the solutionSolution
  1. GFC starts with living green plants (producers) eaten by herbivores, e.g. grass → goat → man. (1)
  2. DFC starts with dead organic matter (detritus), broken down by decomposers (saprotrophs, mainly fungi and bacteria) that secrete digestive enzymes. (1)
  3. In terrestrial ecosystems such as forests, a much larger fraction of energy flows through the DFC (in aquatic ecosystems the GFC is the main conduit). (1)

Answer: GFC begins with living producers, DFC with detritus; in a forest more energy flows through the DFC.

Example 6: Decomposition rates across climates · 3 marks · Short answerHOTS / competency

Suppose leaf litter of the same type is placed in (i) a tropical rain forest, (ii) a cold coniferous forest, (iii) a waterlogged marsh. Rank the decomposition rates and explain. Where would humus or peat-like organic matter build up most? (3 marks)

Try it first, then show the solutionSolution
  1. Fastest in the tropical rain forest: warm, moist conditions favour soil microbial activity. (1)
  2. Slower in the cold forest (low temperature inhibits microbes) and in the waterlogged marsh (anaerobiosis inhibits this largely oxygen-requiring process). (1)
  3. Organic matter builds up most where decomposition is inhibited: the cold and especially the waterlogged, anaerobic site. (1)

Answer: Rain forest > cold forest and marsh; build-up greatest in cold, waterlogged (anaerobic) conditions.

Example 7: Pyramids in full · 5 marks · Long answerHarder board level

(a) Define standing crop and explain why dry weight is preferred. (2)
(b) Explain with diagrams an upright pyramid of numbers and an inverted pyramid of biomass. (2)
(c) State one limitation of ecological pyramids. (1) (5 marks)

Try it first, then show the solutionSolution
  1. (a) Standing crop is the mass of living material at a trophic level at a given time, measured as biomass or number per unit area. (1)
  2. Dry weight is preferred because water content varies, so it measures organic matter more accurately. (1)
  3. (b) Grassland pyramid of numbers: wide base of producers narrowing to very few top carnivores (about 6 million plants support 3 top carnivores). (1)
  4. Sea pyramid of biomass: small base of phytoplankton standing crop with a larger zooplankton/fish bar above: inverted. (1)
  5. (c) Pyramids ignore species at more than one level, assume simple chains not webs, and omit saprophytes (any one). (1)

Answer: Standing crop as biomass at a time (dry weight more accurate); grassland numbers upright, sea biomass inverted; limitations as listed.

Example 8: Ocean productivity · 2 marks · Very short answerBoard level

The biosphere's annual NPP is about 170 billion tons, of which oceans contribute 55 billion tons. What percentage comes from land, and why are oceans less productive despite their area? (2 marks)

Try it first, then show the solutionSolution
  1. Land = 170 − 55 = 115 billion tons; 115 ÷ 170 × 100 ≈ 67.6% (check: 55 ÷ 170 ≈ 32.4%, sum 100%). (1)
  2. In aquatic ecosystems light is the main limiting factor (it falls off with depth), and nutrients may be scarce in open oceans. (1)

Answer: About 68% from land; light (and nutrient) limitation in oceans.

Case-study practice (Section D style)

Read the situation, then answer every part. In the board paper this is a 4-mark question split into 1 + 2 + 1 marks.

Energy in a grassland

Suppose an ecologist measures a grassland and finds GPP = 25,000 kJ m⁻² yr⁻¹ and plant respiration R = 10,000 kJ m⁻² yr⁻¹. Grasshoppers eat the grass, frogs eat grasshoppers and snakes eat frogs.

  1. (i) · 1 mark

    Calculate the NPP.

    Answer

    Answer: NPP = 25,000 − 10,000 = 15,000 kJ m⁻² yr⁻¹.

    Check: NPP + R = 15,000 + 10,000 = 25,000 = GPP.

  2. (ii) · 2 marks

    Using the 10 per cent law, find the energy reaching the frogs and the snakes. Show a check.

    Answer

    Answer: Grasshoppers 1500; frogs 150; snakes 15 kJ m⁻² yr⁻¹.

    Step-by-step tenths (1); check 15,000 × 0.001 = 15 (1).

  3. (iii) · 1 mark

    Why would a hawk eating the snakes find it hard to survive on this grassland alone?

    Answer

    Answer: Only about 1.5 kJ m⁻² yr⁻¹ would reach it: too little energy to support a fifth level over a small area.

    The 10 per cent law limits the number of trophic levels.

A forest floor

Suppose students study a forest floor and find thick leaf litter, many earthworms and termites, white fungal threads, and a dark crumbly layer just below the litter.

  1. (i) · 1 mark

    What is the dark crumbly layer, and why is it important?

    Answer

    Answer: Humus; it is colloidal and acts as a reservoir of nutrients, released slowly by mineralisation.

    Formed by humification; highly resistant to microbial action.

  2. (ii) · 2 marks

    Name the steps carried out by the earthworms and by the fungi, and explain each.

    Answer

    Answer: Earthworms: fragmentation (break detritus into smaller particles); fungi: catabolism (enzymes degrade detritus into simpler inorganic substances).

    Each step with agent (1 + 1).

  3. (iii) · 1 mark

    Which food chain carries most of the energy on this forest floor?

    Answer

    Answer: The detritus food chain.

    In terrestrial ecosystems a much larger fraction of energy flows through the DFC.

Where the marks are

How a typical answer is split into step marks. Show every step: a right final answer alone rarely earns full marks.

Distinguish between gross primary productivity and net primary productivity. (2 marks) (2 marks)

StepMarks
GPP is the rate of production of organic matter during photosynthesis.1
NPP = GPP minus respiration losses (R); it is the biomass available to herbivores and decomposers.1

Describe the steps of decomposition. (3 marks) (3 marks)

StepMarks
Fragmentation: detritivores like earthworms break detritus into smaller particles.1
Leaching: water-soluble nutrients go down into the soil and precipitate as unavailable salts; catabolism: bacterial and fungal enzymes degrade detritus into simpler inorganic substances.1
Humification: dark, colloidal, slowly decomposed humus accumulates; mineralisation: humus is degraded by microbes, releasing inorganic nutrients.1

(a) What are ecological pyramids? Describe the pyramids of number and biomass with examples, including inverted forms. (4)
(b) Why is the pyramid of energy always upright? (1) (5 marks)
(5 marks)

StepMarks
(a) Graphic representation of number, biomass or energy at successive trophic levels; producers at the base, top consumers at the apex.1
Pyramid of number: upright in a grassland (about 6 million plants support only 3 top carnivores).1
Inverted (spindle) pyramid of number for a tree: one tree supports many insects, then fewer birds.1
Pyramid of biomass: usually upright on land; inverted in the sea, where a small standing crop of phytoplankton supports a larger standing crop of zooplankton and fish.1
(b) At each transfer some energy is always lost as heat, so energy at a higher level is always less.1

Where students lose marks in Ecosystem

The slips examiners see most often, and what to write instead.

  • Mistake: Writing NPP = GPP + R

    Wrong working

    GPP = 1500, R = 500, so NPP = 2000.

    Right working

    NPP = GPP − R = 1500 − 500 = 1000.

    Do this: Respiration is a loss; NPP is always less than GPP.

    Usually costs: 1 mark.

  • Mistake: Saying the pyramid of energy can be inverted

    Do this: It is always upright because energy is lost as heat at each transfer; only number and biomass pyramids can be inverted.

    Usually costs: 1 mark.

  • Mistake: Mixing up leaching and catabolism

    Do this: Leaching: water-soluble nutrients move down and precipitate as unavailable salts. Catabolism: bacterial and fungal enzymes break detritus into simpler inorganic substances.

    Usually costs: 1 mark.

  • Mistake: Saying the GFC carries most energy on land

    Do this: On land, a much larger fraction of energy flows through the detritus food chain; in water the GFC is the main conduit.

    Usually costs: 1 mark.

  • Mistake: Treating a trophic level as a species

    Do this: A trophic level is a functional level; one species (sparrow, humans) can occupy more than one level.

    Usually costs: ½ to 1 mark.

  • Mistake: Answering about nutrient cycles or succession

    Do this: Carbon and phosphorus cycles, ecological succession and ecosystem services are not in the 2026-27 syllabus.

    Usually costs: Time and marks spent on unasked content.

NCERT exercise guide: Ecosystem

What each exercise in the NCERT chapter tests, how to approach it, and a question of the same kind solved step by step. Questions here are written in our own words.

Exercises on fill-in-the-blanks and MCQs

What it tests: Plants as producers, pyramid type in a tree-dominated ecosystem, limiting factor in aquatic productivity, common detritivores, largest population in a food chain, second trophic level in a lake, secondary producers, percentage of PAR.

How to approach it: Answer with exact NCERT terms and figures.

Trophic levels and energy in a lake

In a lake, phytoplankton → zooplankton → small fish → kingfisher. (a) Give the trophic level of each. (b) If the phytoplankton make 5000 kJ m⁻² yr⁻¹ of net production, how much energy reaches the kingfisher by the 10 per cent law? (c) Which pyramid of this ecosystem may be inverted, and why?

Show the solutionSolution
  1. (a) Phytoplankton: first (producers); zooplankton: second (primary consumers); small fish: third; kingfisher: fourth.
  2. (b) 5000 → 500 → 50 → 5 kJ m⁻² yr⁻¹. Check: 5000 × (0.1)³ = 5.
  3. (c) The pyramid of biomass can be inverted, because the standing crop of phytoplankton at any moment is small though they reproduce fast; the pyramid of energy stays upright.

Answer: (a) 1st, 2nd, 3rd, 4th (b) 5 kJ m⁻² yr⁻¹ (c) the biomass pyramid.

Exercises on distinguishing terms

What it tests: Grazing versus detritus food chain, production versus decomposition, upright versus inverted pyramid, food chain versus food web, litter versus detritus, primary versus secondary productivity.

How to approach it: Two-column comparisons with two or three points each.

One bird, two food chains

A sparrow eats grain in winter and caterpillars in spring. Write the two food chains it belongs to, give its trophic level in each, and explain why such feeding makes a food web rather than separate chains.

Show the solutionSolution
  1. Winter: grain (producer) → sparrow: the sparrow is a primary consumer (second trophic level).
  2. Spring: plant → caterpillar → sparrow: the sparrow is a secondary consumer (third trophic level).
  3. Because one species feeds at different levels and chains share members, the chains interconnect into a food web; a trophic level is a functional level, not a species.

Answer: Grain → sparrow (2nd level) and plant → caterpillar → sparrow (3rd level); shared members link chains into a food web.

Exercises on description

What it tests: Components of an ecosystem, ecological pyramids, primary productivity and its factors, decomposition, energy flow.

How to approach it: Use the key-concept outlines; include a labelled diagram where useful.

Comparing productivity of two ecosystems

A hectare of tropical rainforest and a hectare of desert receive similar sunlight. Which is likely to have higher net primary productivity? Explain using the factors that affect primary productivity.

Show the solutionSolution
  1. The rainforest: its plant species are many, large and leafy, with high photosynthetic capacity.
  2. Environmental factors favour it: abundant water and warm temperatures, while the desert is limited by water.
  3. Nutrient availability is higher, and dead matter is recycled quickly in the warm, moist conditions; so its NPP per unit area is far higher.

Answer: The rainforest, because of its plant species and photosynthetic capacity, plentiful water, warmth and nutrients.

Ecosystem: previous year questions

  • Asked in 8 of the 8 board papers we hold (2023 to 2026), on average 3.1 marks per paper; 17 questions in all, counting OR alternatives. In 4 of 4 sample papers.

Counted from the real papers on our previous year papers page, not estimated. Average marks are over every board paper we hold, with an OR pair counted once. Chapter tags are ours.

Solved board questions from Ecosystem

Real questions from recent papers. Try each one first, then open our step-by-step solution with marks per step.

2026, set 57/1/1, Q6 · 1 mark · MCQ

In an ecosystem, different species occupy different levels and vertical distribution of species is found. This is called _________.

  1. (A)Stratification
  2. (B)Layering
  3. (C)Fragmentation
  4. (D)Population
Try it first, then show our solutionSolution
  1. The vertical distribution of different species occupying different levels in an ecosystem is called stratification. For example, trees, shrubs and herbs form separate layers in a forest.

    1 mark

Answer: (A) Stratification

Where the marks are

  • Selects stratification (1 mark)

See it in the full 2026 board paper, set 57/1/1

2026, set 57/1/1, Q21(a) · 2 marks · Very short answerCompetency-based

Given below is a pyramid found in an ecosystem, where each bar represents the standing crop available in the trophic level.

  1. (i)

    Identify the kind of pyramid and with the help of an example explain the conditions where this kind of pyramid is possible in nature.

    1 mark
  2. (ii)

    Write any two limitations of ecological pyramids.

    1 mark

Figure in the paper: Inverted pyramid of two bars: the upper bar labelled PC (primary consumer) is wider than the lower bar labelled PP (primary producer). See it in the official paper.

Try it first, then show our solutionSolution
  1. (i) Because the bars show standing crop and the consumer bar is wider than the producer bar, this is an inverted pyramid of biomass.

    ½ mark
  2. Such a pyramid occurs in aquatic ecosystems such as the sea. There, a small standing crop of phytoplankton reproduces very fast and supports a larger standing crop of zooplankton or fish.

    ½ mark
  3. (ii) Any two limitations: (1) It does not account for the same species occupying two or more trophic levels. (2) It assumes a simple food chain and cannot accommodate a food web.

    1 mark
  4. (Another accepted limitation: saprophytes or decomposers are given no place in the pyramid, though they play a vital role in the ecosystem.)

Answer: (i) Inverted pyramid of biomass, e.g. in the sea a small standing crop of phytoplankton supports a larger standing crop of zooplankton or fish; (ii) it ignores species at more than one trophic level, and it cannot show food webs (or it omits saprophytes)

Where the marks are

  • Identifies an inverted pyramid of biomass (½ mark)
  • Correct condition or example, e.g. phytoplankton supporting zooplankton or fish in the sea (½ mark)
  • Any two limitations (½ + ½ mark)

See it in the full 2026 board paper, set 57/1/1

2025, set 57/7/1, Q28 · 3 marks · Short answer

Name the type of food chains responsible for the flow of larger fraction of energy in an aquatic ecosystem and a terrestrial ecosystem, respectively. Mention any two differences between the two food chains.

Try it first, then show our solutionSolution
  1. In an aquatic ecosystem, the Grazing Food Chain (GFC) carries the larger fraction of energy.

    ½ mark
  2. In a terrestrial ecosystem, the Detritus Food Chain (DFC) carries the larger fraction of energy.

    ½ mark
  3. Differences (any two):

    Grazing food chainDetritus food chain
    Begins with producers (green plants)Begins with detritus (dead organic matter)
    Energy comes from the sunEnergy comes from dead organic matter
    Major conduit of energy flow in aquatic ecosystemsMajor conduit of energy flow in terrestrial ecosystems
    2 marks

Answer: Aquatic: Grazing Food Chain; Terrestrial: Detritus Food Chain; they differ in their starting point (producers vs detritus) and energy source (sun vs dead organic matter).

Where the marks are

  • Aquatic ecosystem: GFC (½ mark)
  • Terrestrial ecosystem: DFC (½ mark)
  • Any two correct differences (1 + 1 mark)

See it in the full 2025 board paper, set 57/7/1

Every Ecosystem question, by year

For 2027

Sample paper 2026-27: Q21(A) (2 marks, solved), Q33(B) (5 marks, solved)

2026

Set 57/1/1: Q6 (1 mark, solved), Q16 (1 mark, solved), Q21(a) (2 marks, solved)

Set 57/5/1: Q21(a) (2 marks, solved), Q21(b) (2 marks, solved)

Sample paper 2025-26: Q21(A) (2 marks, solved), Q33(B) (5 marks, solved)

2025

Set 57/1/1: Q4 (1 mark, solved), Q18(A) (2 marks, solved), Q18(B) (2 marks, solved)

Set 57/7/1: Q28 (3 marks, solved)

Sample paper 2024-25: Q21(A) (2 marks, solved), Q21(B) (2 marks, solved)

2024

Set 57/1/1: Q12 (1 mark, solved), Q20(b) (2 marks, solved), Q21 (2 marks, solved)

Set 57/5/1: Q23(b) (3 marks, solved)

Sample paper 2023-24: Q12 (1 mark, solved), Q21(a) (2 marks, solved), Q21(b) (2 marks, solved)

2023

Set 57/1/1: Q4 (1 mark, solved), Q20 (2 marks, solved)

Set 57/5/1: Q7 (1 mark, solved), Q15 (1 mark, solved)

Practice questions on Ecosystem

Write each answer on paper first. Open the hint only if you are stuck, and the answer only when you have finished.

  1. Q1 · 1 mark · MCQBoard level

    Which step of decomposition makes nutrients unavailable by precipitating them as salts?
    (a) Fragmentation (b) Leaching (c) Catabolism (d) Mineralisation

    Hint

    Water carries them down.

    Answer

    (b) Leaching

  2. Q2 · 1 mark · Assertion-reasonBoard level

    Assertion (A): The pyramid of energy is always upright.
    Reason (R): Some energy is lost as heat at each transfer between trophic levels.
    (a) Both A and R are true and R is the correct explanation of A.
    (b) Both A and R are true but R is not the correct explanation of A.
    (c) A is true but R is false.
    (d) A is false but R is true.

    Hint

    Second law of thermodynamics.

    Answer

    (a)

  3. Q3 · 1 mark · MCQHarder board level

    A sparrow eating seeds and later eating insects occupies:
    (a) only the second trophic level (b) only the third trophic level (c) the second and third trophic levels (d) the first and second trophic levels

    Hint

    Trophic level is functional.

    Answer

    (c) the second and third trophic levels

  4. Q4 · 2 marks · Very short answerBoard level

    Define stratification and give an example. (2 marks)

    Hint

    Vertical layers.

    Answer

    Stratification is the vertical distribution of different species at different levels in an ecosystem (1). In a forest, trees occupy the top layer, shrubs the second, and herbs and grasses the bottom layers (1).

  5. Q5 · 2 marks · Very short answerHarder board level

    Distinguish between litter and detritus. (2 marks)

    Hint

    Detritus includes animal remains.

    Answer

    Litter refers to dead plant parts (leaves, twigs, bark, flowers) lying on the soil surface (1). Detritus is all dead organic matter, plant remains as well as dead animal remains and faecal matter, which is the raw material for decomposition (1).

  6. Q6 · 2 marks · Very short answerHOTS / competency

    Give two reasons why a terrestrial ecosystem sends more energy through the detritus food chain than an aquatic one. (2 marks)

    Hint

    What do land plants leave behind?

    Answer

    Land plants such as trees produce large amounts of tough tissue (wood, leaves) that herbivores eat little of, so much NPP becomes litter and detritus (1). In water, small phytoplankton are eaten rapidly by zooplankton, so most energy passes through the grazing chain; on land, most NPP reaches decomposers instead (1).

  7. Q7 · 3 marks · Short answerBoard level

    Describe the components of an ecosystem. (3 marks)

    Hint

    Abiotic and three biotic groups.

    Answer

    Abiotic: air, water, soil, dissolved substances, sunlight and climate (1). Biotic: producers (green plants, phytoplankton) that make food from inorganic materials using sunlight; consumers (herbivores and carnivores) that depend on producers (1). Decomposers (fungi, bacteria, flagellates) break dead matter into inorganic nutrients for reuse (1).

  8. Q8 · 3 marks · Short answerHarder board level

    An ecosystem has NPP of 6000 kcal m⁻² yr⁻¹, which is 75% of GPP. Calculate GPP and R, and the energy available to primary carnivores using the 10 per cent law. (3 marks)

    Hint

    NPP = 0.75 × GPP.

    Answer

    GPP = 6000 ÷ 0.75 = 8000 kcal m⁻² yr⁻¹ (1). R = 8000 − 6000 = 2000 kcal m⁻² yr⁻¹; check 2000/8000 = 25% (1). Herbivores get 600; primary carnivores get 60 kcal m⁻² yr⁻¹ (1).

  9. Q9 · 5 marks · Long answerHarder board level

    (a) Give an account of energy flow in an ecosystem, including PAR and the second law of thermodynamics. (3)
    (b) Explain why the number of trophic levels in a grazing food chain is limited. (2) (5 marks)

    Hint

    Sun → producers → consumers.

    Answer

    (a) The sun is the energy source of all ecosystems except deep-sea hydrothermal ones; less than 50% of incident radiation is PAR, and plants capture only 2–10% of PAR (1). Energy flows one way: from the sun to producers, then to herbivores and carnivores, and to decomposers through detritus (1). Ecosystems obey the second law of thermodynamics: they need a constant energy input to build molecules and counter disorder, and energy is lost as heat at each step (1). (b) Only about 10% of energy passes from one level to the next (1). After a few transfers the energy left is too little to support another level, so chains have only about 4–5 levels (1).

  10. Q10 · 3 marks · Short answerHOTS / competency

    Suppose a lake receives warm wastewater and a large algal bloom develops, but the lake bottom becomes oxygen-poor and dead plant matter piles up. Explain the pile-up of organic matter using factors that control decomposition. (3 marks)

    Hint

    Oxygen-requiring process.

    Answer

    The bloom produces a large amount of dead organic matter (detritus) that sinks (1). Decomposition is largely oxygen-requiring; the oxygen-poor (anaerobic) bottom inhibits microbial breakdown (1). So detritus is added faster than it is decomposed and builds up, as NCERT notes for anaerobic conditions (1).

  11. Q11 · 2 marks · Very short answerHarder board level

    Explain why the pyramid of numbers is upright in a grassland but spindle-shaped for a single large tree. (2 marks)

    Hint

    Size of producers.

    Answer

    In a grassland, producers are many small grass plants, so their number far exceeds herbivores and carnivores (about 6 million plants support 3 top carnivores): upright (1). A single big tree (one producer) supports thousands of insects, which support fewer birds, so the base is narrow and the next bar wide: spindle-shaped (1).

  12. Q12 · 2 marks · Very short answerHarder board level

    Why is humus important for soil fertility even though it decomposes very slowly? (2 marks)

    Hint

    Colloidal reservoir.

    Answer

    Humus is colloidal and holds nutrients, acting as a reservoir of nutrients in the soil (1). Its slow mineralisation by microbes releases inorganic nutrients gradually, supplying plants over a long period (1).

Test your recall

Answer in your head or on paper first, then open the card. Pulling an answer out of memory makes it stick far better than re-reading.

  1. 1.What is stratification?Show answer

    Vertical distribution of species at different levels, e.g. trees at the top, shrubs next, herbs and grasses at the bottom of a forest.

  2. 2.Define primary productivity.Show answer

    The rate of biomass or organic matter production per unit area by plants during photosynthesis.

  3. 3.What is secondary productivity?Show answer

    The rate of formation of new organic matter by consumers.

  4. 4.What is the annual NPP of the biosphere?Show answer

    About 170 billion tons (dry weight) of organic matter.

  5. 5.What is detritus?Show answer

    Dead plant remains (leaves, bark, flowers) and dead animal remains, including faecal matter.

  6. 6.What are the properties of humus?Show answer

    Dark, amorphous, highly resistant to microbial action, decomposes very slowly, colloidal and a reservoir of nutrients.

  7. 7.What fraction of incident solar radiation is PAR?Show answer

    Less than 50%.

  8. 8.What percentage of PAR do plants capture?Show answer

    2–10%.

  9. 9.What are saprotrophs?Show answer

    Decomposers (mainly fungi and bacteria) that obtain energy and nutrients by degrading dead organic matter.

  10. 10.What is standing crop?Show answer

    The mass of living material at a trophic level at a particular time, measured as biomass or number per unit area.

  11. 11.Which is the only kind of ecosystem not powered by the sun?Show answer

    The deep-sea hydrothermal ecosystem.

  12. 12.Give one limitation of ecological pyramids.Show answer

    They do not account for a species at more than one trophic level, assume simple food chains (not webs), and leave out saprophytes (any one).

Best order to study it

  1. Learn the definition and types of ecosystems, structure (species composition, stratification) and the pond example.
  2. Learn productivity: GPP, R, NPP, secondary productivity, factors and global figures; practise NPP numericals.
  3. Learn decomposition steps in order and the factors controlling the rate; draw the decomposition cycle.
  4. Learn energy flow: PAR, producers and consumers, GFC and DFC, food webs, trophic levels, standing crop and the 10 per cent law; practise energy numericals.
  5. Finish with the three pyramids, their inversions and limitations; draw each.

Quick revision checklist

The night before the exam: can you do each of these without looking?

  • Can you describe the components of a pond ecosystem?
  • Can you define GPP, NPP and secondary productivity and calculate NPP?
  • Can you explain why oceans have low productivity?
  • Can you list the five steps of decomposition and the factors that speed or slow it?
  • Can you compare grazing and detritus food chains, and food chains and food webs?
  • Can you apply the 10 per cent law to find energy at the fourth trophic level?
  • Can you draw pyramids of number for a grassland and a tree, and biomass for the sea?
  • Can you explain why the pyramid of energy is always upright, and list three limitations of pyramids?

Ecosystem: frequently asked questions

How many marks does Ecosystem carry in CBSE Class 12 Biology 2026-27?

It is part of Unit X, Ecology and Environment, which carries 10 of the 70 theory marks together with Organisms and Populations and Biodiversity and Conservation.

Are nutrient cycles and ecological succession in the syllabus?

No. Ecological succession, nutrient cycling (carbon and phosphorus cycles) and ecosystem services were dropped. The syllabus covers ecosystem patterns and components, productivity and decomposition, energy flow, and pyramids of number, biomass and energy.

Why is dry weight a better measure of biomass than fresh weight?

Water content varies a lot between organisms and with conditions, so fresh weight can mislead; dry weight measures the actual organic matter and is more accurate.

Is there a 10 per cent limit in the detritus food chain?

NCERT applies the 10 per cent law to explain why grazing food chains have few levels, and asks you to think about detritus chains. Decomposers draw on dead matter from every level, so the DFC is not built up as a simple ladder in the same way.

How can a small amount of phytoplankton support a larger biomass of fish?

Phytoplankton have a small standing crop but reproduce very fast and are eaten quickly, so their production over time is large. The biomass pyramid shows only the standing crop at one moment, which is why it appears inverted in the sea.

Based on: CBSE Biology (044) syllabus 2026-27; NCERT Biology, Textbook for Class XII (Reprint 2026-27)