Breathing and Exchange of Gases ISC Class 11: Mechanism, Transport and Volumes
Updated 15 October 2026 · Fact-checked
Breathing and Exchange of Gases is a chapter in Unit 5 (Human Physiology) of ISC Class 11 Biology. It covers the human respiratory system, the action of the diaphragm and intercostal muscles, pulmonary gas exchange, oxygen transport and the dissociation curve, carbon dioxide transport and chloride shift, regulation of breathing, lung volumes and capacities, and respiratory disorders.
What Breathing and Exchange of Gases is about
Cells need a continuous supply of oxygen for aerobic respiration and must get rid of the carbon dioxide it produces. Breathing (ventilation) moves air in and out of the lungs; respiration in its wider sense also includes gas exchange and transport.
Respiratory organs in animals vary with habitat and body organisation: body surface (earthworm), tracheal tubes (insects), gills (most aquatic animals), and lungs (land vertebrates). Frogs use both skin and lungs.
In humans, air passes through the nostrils, nasal chamber, pharynx, larynx, trachea, bronchi and bronchioles to millions of alveoli, where exchange occurs across a very thin membrane.
Breathing depends on changing the volume of the air-tight thoracic cavity. Contraction of the diaphragm and external intercostal muscles enlarges it, lowering the pressure in the lungs so air flows in; relaxation reverses this.
Gases move by diffusion down partial pressure gradients. Oxygen is carried mostly as oxyhaemoglobin; the oxygen–haemoglobin dissociation curve is sigmoid and shifts right in tissues (high pCO₂, H⁺, temperature). Carbon dioxide is carried mostly as bicarbonate (with chloride shift), partly as carbaminohaemoglobin and a little dissolved in plasma.
Breathing is controlled by centres in the medulla and pons, which respond mainly to CO₂ and H⁺. Learn the lung volumes and capacities with typical values, and the disorders asthma, emphysema and occupational respiratory disorders.
Weightage: Breathing and Exchange of Gases belongs to the unit Human Physiology, which CISCE weights at 18 of the 70 marks in the ISC Class XI Biology Paper I (Theory). Class XI is examined by the school, so your school sets the paper within this weightage.Source: CISCE ISC Biology syllabus, examination year 2028, Class XI unit weightage
Key concepts
- Respiratory organs in animals (recall) and the human respiratory system
Recall: lower invertebrates such as sponges, cnidarians and flatworms exchange gases by simple diffusion over the whole body surface; earthworms use their moist cuticle; insects use a network of tracheal tubes; most aquatic arthropods and molluscs use gills (branchial respiration), as do fishes; amphibians use moist skin and lungs; reptiles, birds and mammals use lungs (pulmonary respiration). Human respiratory system: a pair of external nostrils opens into the nasal chamber, which leads to the pharynx, a common passage for food and air. The pharynx opens through the larynx, a cartilaginous sound box, into the trachea. During swallowing the glottis is covered by a thin elastic flap, the epiglottis, which stops food entering the larynx. The trachea runs down to the middle of the thorax and divides (at about the level of the 5th thoracic vertebra) into right and left primary bronchi; these branch repeatedly into secondary and tertiary bronchi and bronchioles, ending in very thin terminal bronchioles. The trachea, bronchi and early bronchioles are kept open by incomplete (C-shaped) cartilaginous rings. Each terminal bronchiole ends in many thin-walled, highly vascular bag-like alveoli. The branching tubes and alveoli form the two lungs, covered by a double-layered pleura with pleural fluid between the layers, which reduces friction. The part from nostrils to terminal bronchioles is the conducting part (it warms, humidifies and cleans the air); the alveoli and their ducts form the respiratory or exchange part. The lungs lie in the air-tight thoracic chamber, bounded by the vertebral column (dorsally), sternum (ventrally), ribs (laterally) and the dome-shaped diaphragm (below).
Worked example
Why are the trachea and bronchi supported by cartilage rings, and why are the rings incomplete?
Try it first, then show the solutionSolution
- Cartilage keeps the airway open so it does not collapse when pressure inside falls during inspiration
- The rings are open at the back where the trachea lies against the oesophagus, so swallowed food can expand the oesophagus
Answer: To prevent collapse of the airway while allowing the oesophagus to expand
- Mechanism of breathing: role of diaphragm and intercostal muscles
Breathing has two phases: inspiration (air in) and expiration (air out). Air moves because of a pressure gradient between the lungs and the atmosphere, created by changing the volume of the thoracic cavity; since the lungs are attached to it through the pleura, lung volume changes with it. Inspiration (active): (1) the diaphragm contracts and flattens, increasing the volume of the thorax in the antero-posterior (top-to-bottom) axis; (2) the external intercostal muscles contract, lifting the ribs and sternum upwards and outwards, increasing the volume in the dorso-ventral axis; (3) the larger volume lowers intra-pulmonary pressure below atmospheric pressure; (4) air flows into the lungs. Expiration (normally passive): the diaphragm and external intercostals relax; the diaphragm domes up and the ribs and sternum return; thoracic and lung volume fall; intra-pulmonary pressure rises above atmospheric, and air is expelled. During forced breathing (exercise), internal intercostal muscles and abdominal muscles contract to push air out more strongly, and extra muscles help inspiration. A healthy adult at rest breathes about 12–16 times per minute. Breathing volumes can be measured with a spirometer.
Worked example
If the pleural membrane is punctured so that air enters between the lung and the chest wall, the lung on that side collapses. Explain.
Try it first, then show the solutionSolution
- Normally the pressure between the pleural layers is below atmospheric, which keeps the elastic lungs stretched against the chest wall
- When air enters, this pressure equals atmospheric, the lung is no longer held out and its elasticity makes it recoil and collapse
Answer: Loss of the pressure difference that keeps the lung expanded
- Pulmonary gas exchange
Alveoli are the main sites of exchange; exchange also takes place between blood and tissues. Gases move by simple diffusion, which depends on the partial pressure gradient, the solubility of the gas and the thickness of the membrane. Partial pressures (mm Hg, typical values): atmospheric air: pO₂ 159, pCO₂ 0.3; alveoli: pO₂ 104, pCO₂ 40; blood arriving at lungs (deoxygenated): pO₂ 40, pCO₂ 45; blood leaving lungs (oxygenated): pO₂ 95, pCO₂ 40; tissues: pO₂ 40, pCO₂ 45. So O₂ diffuses from alveoli (104) into blood (40) and from blood (95) into tissues (40); CO₂ diffuses from tissues (45) into blood (40) and from blood (45) into alveoli (40). Although the CO₂ gradient is small, CO₂ is about 20–25 times more soluble than O₂, so the amount of CO₂ that diffuses per unit difference is much higher. The diffusion membrane has three layers: the thin squamous epithelium of the alveolus, the endothelium of the capillary, and a basement substance between them; its total thickness is far less than a millimetre, which favours diffusion. The very large total alveolar area and the rich capillary network also help.
Worked example
Using typical partial pressures, give the O₂ gradient from alveolus to blood and the CO₂ gradient from blood to alveolus. Why does CO₂ still diffuse efficiently?
Try it first, then show the solutionSolution
- O₂: 104 − 40 = 64 mm Hg; CO₂: 45 − 40 = 5 mm Hg
- CO₂ is 20–25 times more soluble than O₂, so a small gradient moves a large amount
Answer: 64 mm Hg and 5 mm Hg; CO₂'s high solubility compensates
- Transport of oxygen and the oxygen–haemoglobin dissociation curve
About 97% of O₂ is carried by haemoglobin in red blood cells, and only about 3% dissolved in plasma. Haemoglobin is a red, iron-containing pigment; each molecule can bind up to four O₂ molecules reversibly, forming oxyhaemoglobin. Binding depends mainly on pO₂, and also on pCO₂, H⁺ concentration and temperature. The oxygen–haemoglobin dissociation curve plots percentage saturation of haemoglobin against pO₂. It is sigmoid (S-shaped): at low pO₂ saturation rises slowly, then steeply over the range found in tissues, and flattens near 100% at the pO₂ of the lungs. In the alveoli (high pO₂, low pCO₂, fewer H⁺, lower temperature) haemoglobin loads O₂ almost fully. In the tissues (low pO₂, high pCO₂, more H⁺, higher temperature) these conditions shift the curve to the right, lowering haemoglobin's affinity so that it unloads more O₂ (the Bohr effect). Under normal resting conditions, every 100 mL of oxygenated blood delivers about 5 mL of O₂ to the tissues.
Worked example
During exercise, muscle temperature and CO₂ rise. What happens to the dissociation curve and why is this useful?
Try it first, then show the solutionSolution
- Higher pCO₂, H⁺ and temperature shift the curve to the right
- At the same pO₂, haemoglobin is less saturated, so it releases more O₂ to the working muscle
Answer: The curve shifts right, increasing O₂ unloading where it is needed
- Transport of carbon dioxide and the chloride shift
CO₂ is carried in three ways: (1) about 7% dissolved in plasma; (2) about 20–25% combined with haemoglobin as carbaminohaemoglobin (CO₂ binds to amino groups of the globin, not to iron); binding is favoured by high pCO₂ and low pO₂ (tissues) and reversed in the lungs; (3) about 70% as bicarbonate ions. In the tissues, CO₂ diffuses into red blood cells, where the enzyme carbonic anhydrase rapidly converts it: CO₂ + H₂O ⇌ H₂CO₃ ⇌ HCO₃⁻ + H⁺. The H⁺ is buffered by haemoglobin. HCO₃⁻ diffuses out of the red cell into the plasma, and to keep the cell electrically neutral chloride ions (Cl⁻) move from the plasma into the red cell: this exchange is the chloride shift (Hamburger phenomenon). In the lungs, where pCO₂ is low, the reaction runs in reverse: HCO₃⁻ re-enters the red cell (Cl⁻ moves out, a reverse chloride shift), is converted back to CO₂ and water, and CO₂ diffuses into the alveoli. Every 100 mL of deoxygenated blood delivers about 4 mL of CO₂ to the alveoli.
Worked example
Why does the chloride ion move into red blood cells as blood passes through tissues?
Try it first, then show the solutionSolution
- Carbonic anhydrase in the RBC forms H₂CO₃, which gives HCO₃⁻ and H⁺; HCO₃⁻ leaves the cell into plasma
- Loss of negative ions would upset the cell's charge balance, so Cl⁻ enters from plasma in exchange
Answer: To maintain electrical neutrality as bicarbonate leaves (chloride shift)
- Regulation of breathing
Humans can adjust the rhythm and depth of breathing to match the body's demands. This is controlled by the neural system. (1) A respiratory rhythm centre in the medulla oblongata is mainly responsible for setting the basic rhythm. (2) A pneumotaxic centre in the pons can moderate the rhythm centre; its signals shorten inspiration and so change the breathing rate. (3) A chemosensitive area next to the rhythm centre is highly sensitive to CO₂ and H⁺; when these rise, it activates the rhythm centre to increase breathing so they are removed. (4) Receptors in the aortic arch and carotid arteries also detect changes in CO₂ and H⁺ and send signals to the rhythm centre. The role of O₂ in regulating normal breathing is minor; it becomes important only when O₂ falls very low (e.g. at high altitude).
Worked example
A person who holds their breath for a minute feels a strong urge to breathe. What triggers this?
Try it first, then show the solutionSolution
- CO₂ accumulates in the blood, raising pCO₂ and H⁺
- The chemosensitive area and aortic and carotid receptors stimulate the rhythm centre, forcing breathing
Answer: The rise in CO₂ and H⁺, not mainly the fall in O₂
- Respiratory volumes and capacities
Volumes (healthy adult, approximate): Tidal volume (TV): air breathed in or out in a normal breath, about 500 mL (about 6000–8000 mL per minute at rest). Inspiratory reserve volume (IRV): extra air that can be inspired forcibly after a normal inspiration, about 2500–3000 mL. Expiratory reserve volume (ERV): extra air that can be expired forcibly after a normal expiration, about 1000–1100 mL. Residual volume (RV): air that remains in the lungs even after forcible expiration, about 1100–1200 mL. Capacities (sums): Inspiratory capacity (IC) = TV + IRV. Expiratory capacity (EC) = TV + ERV. Functional residual capacity (FRC) = ERV + RV (air left after a normal expiration). Vital capacity (VC) = ERV + TV + IRV: the maximum air a person can breathe out after a forced inspiration (or in after a forced expiration). Total lung capacity (TLC) = VC + RV. Not all inspired air reaches the alveoli: about 150 mL of each breath stays in the conducting passages (anatomical dead space). Vital capacity is higher in athletes, wind-instrument players and mountain dwellers, and lower in smokers and people with lung disease.
Worked example
A student has TV 500 mL, IRV 2800 mL, ERV 1100 mL and RV 1200 mL. Find VC, TLC and FRC.
Try it first, then show the solutionSolution
- VC = TV + IRV + ERV = 500 + 2800 + 1100 = 4400 mL
- TLC = VC + RV = 5600 mL; FRC = ERV + RV = 2300 mL
Answer: VC 4400 mL; TLC 5600 mL; FRC 2300 mL
- Disorders of the respiratory system
Asthma: difficulty in breathing with wheezing, caused by inflammation and narrowing of the bronchi and bronchioles, often an allergic reaction to dust, pollen, smoke or other triggers; spasm of smooth muscle and extra mucus narrow the airways further. Emphysema: a chronic disorder in which the walls of the alveoli are damaged and many alveoli merge into larger sacs, so the respiratory surface area decreases and exchange becomes inefficient; the lungs also lose elasticity, making expiration difficult. Cigarette smoking is a major cause. Occupational respiratory disorders: in industries such as stone-grinding, quarrying, mining, construction and asbestos work, workers inhale large amounts of dust that the body's defences cannot fully clear. Long exposure causes inflammation leading to fibrosis (growth of fibrous tissue), which stiffens the lungs and seriously damages them, e.g. silicosis (silica dust) and asbestosis (asbestos fibres). Prevention: protective masks, dust control and regular health checks.
Worked example
Why do people with emphysema become breathless even at rest?
Try it first, then show the solutionSolution
- Damaged alveolar walls merge into fewer, larger sacs, so the total surface for gas exchange falls
- Less O₂ can diffuse into the blood per breath, and the stiff, less elastic lungs trap air, so breathing must be faster and harder
Answer: Loss of alveolar surface area and elasticity reduces gas exchange
Breathing and Exchange of Gases in real life
Each concept, met in an everyday situation. Read the situation, answer the question in your own words, then compare with the model answer. The one-line hook is what to remember.
Breathlessness at high altitude
Suppose a trekker climbs to a place where air pressure is about half that at sea level.
Why does she feel breathless even though air still has 21% oxygen?
Try it first, then show the solutionSolution
- pO₂ = fraction of O₂ × total pressure: 0.21 × 760 ≈ 160 mm Hg at sea level (the textbook value of 159 uses 20.9%), but 0.21 × 380 ≈ 80 mm Hg at half the pressure
- The lower pO₂ gradient from alveoli to blood means less O₂ diffuses in and haemoglobin is less saturated
Answer: The partial pressure of O₂ is lower, so less O₂ enters the blood; she breathes faster to compensate.
Memory hook: Percentage same, pressure lower.
Carbon monoxide poisoning
Imagine a family running a charcoal heater in a closed room overnight and waking with headaches and drowsiness.
Why is carbon monoxide dangerous?
Try it first, then show the solutionSolution
- CO binds to haemoglobin far more strongly than O₂, forming a stable compound
- Haemoglobin bound to CO cannot carry O₂, so tissues receive too little oxygen
Answer: CO blocks haemoglobin's oxygen-carrying capacity; ventilate rooms and never burn fuel in closed spaces.
Memory hook: CO takes O₂'s seat.
Stone-cutting dust
Suppose workers in a stone-cutting unit work for years without masks and develop chronic cough and breathlessness.
What disorder may they develop and why?
Try it first, then show the solutionSolution
- Inhaled silica dust lodges in the lungs and causes long-term inflammation
- Inflammation leads to fibrosis, stiffening the lungs and reducing gas exchange
Answer: An occupational disorder such as silicosis; masks and dust control prevent it.
Memory hook: Dust in, fibrosis on.
Topics in this chapter
Breathing and Exchange of Gases: key facts
- Lung capacities
- Typical: TV 500, IRV 2500–3000, ERV 1000–1100, RV 1100–1200 mL.
- Ventilation
- f = breaths per minute; dead space about 150 mL.
- Carbonic anhydrase reaction
- Forward in tissues, reverse in lungs.
- Oxygen loading and unloading
- High pO₂ favours loading (lungs); low pO₂, high pCO₂, H⁺ and temperature favour unloading (tissues).
- Partial pressures (mm Hg)
- Oxygenated blood pO₂ 95; deoxygenated blood pO₂ 40, pCO₂ 45.
Breathing and Exchange of Gases: diagrams to practise
Practise each one on paper: draw it from the checklist, then tick off every label.
Human respiratory system
Structure of the human respiratory system.
Draw
- Head and neck outline with nasal chamber, pharynx, larynx with epiglottis, and trachea with C-rings.
- Trachea dividing into two primary bronchi entering two lungs; the left lung with a notch for the heart.
- Bronchi branching into bronchioles inside one lung; an inset of a terminal bronchiole ending in a cluster of alveoli with capillaries.
- The diaphragm below the lungs; pleural membranes around one lung.
Label
- nasal chamber
- pharynx
- epiglottis
- larynx
- trachea
- primary bronchus
- bronchiole
- alveoli
- pleural membranes
- diaphragm
- rib
Watch out: Show the cartilage rings on the trachea and keep the diaphragm dome-shaped.
Mechanism of breathing
Inspiration and expiration.
Draw
- Two side views of the chest.
- Inspiration: diaphragm flattened, ribs raised outward, arrows showing air in.
- Expiration: diaphragm domed, ribs lowered, arrows showing air out.
Label
- diaphragm (contracted/relaxed)
- rib cage
- sternum
- external intercostal muscles
- lungs
- air in
- air out
Watch out: Write the pressure change beside each: below atmospheric in inspiration, above in expiration.
Diffusion membrane and alveolus
Gas exchange at the alveolus.
Draw
- An alveolus with a capillary wrapped around it.
- A magnified box of the wall: alveolar squamous epithelium, basement substance, capillary endothelium, a red blood cell.
- Arrows: O₂ from alveolus to RBC; CO₂ from blood to alveolus, with partial pressures.
Label
- alveolar epithelium
- basement substance
- capillary endothelium
- red blood cell
- O₂ (pO₂ 104 → 40)
- CO₂ (pCO₂ 45 → 40)
Watch out: Name all three layers of the diffusion membrane.
Oxygen–haemoglobin dissociation curve
Transport of oxygen.
Draw
- x-axis pO₂ (0–100 mm Hg); y-axis % saturation of haemoglobin (0–100).
- A sigmoid curve rising steeply between about 10 and 50 mm Hg and levelling near 100% at about 100 mm Hg.
- A second curve displaced to the right labelled 'high pCO₂, H⁺, temperature'.
Label
- partial pressure of O₂
- % saturation
- lungs (loading)
- tissues (unloading)
- shift to the right
Watch out: Mark the pO₂ of tissues (40) and alveoli (104) on the x-axis.
Spirogram of lung volumes
Respiratory volumes and capacities.
Draw
- A wave trace: small regular waves (tidal breathing), one deep inspiration peak, one deep expiration trough, then back to normal.
- Brackets marking TV, IRV, ERV and RV (RV below the lowest trough, not shown on the trace).
- Brackets for VC and TLC.
Label
- TV
- IRV
- ERV
- RV
- VC
- TLC
- FRC
Watch out: RV cannot be measured by a spirometer, so show it with a dashed bracket.
How the school exam asks Breathing and Exchange of Gases
The question patterns to expect, and the method that works for each.
| Question type | How it is asked | Method |
|---|---|---|
| Structure and mechanism | Describe the human respiratory system; explain inspiration and expiration with the role of the diaphragm and intercostal muscles. | Path of air plus labelled diagram; muscles, volume, pressure, air flow. |
| Exchange and transport | Explain gas exchange at the alveoli; transport of O₂ and CO₂; chloride shift; the dissociation curve. | Use partial pressures and percentages. |
| Volumes and calculations | Define lung volumes; calculate capacities, ventilation or O₂ delivered. | Write the formula, then substitute values in mL. |
| Regulation | How is breathing regulated? Role of the medulla, pons and chemoreceptors. | Centre, location, stimulus, effect. |
| Disorders | Asthma, emphysema and occupational respiratory disorders: cause and effect. | Cause, what goes wrong, one prevention. |
Tricks to remember Breathing and Exchange of Gases
Short memory aids. Say each one aloud once, then use it on a question the same day.
Diaphragm Down = Draw in
Diaphragm contracts and moves down; external intercostals lift ribs: volume up, pressure down, air in.
Use it when: Inspiration.
Tired Insects Eat Rice
TV, IRV, ERV, RV: VC is the first three; TLC adds RV.
Use it when: Lung volumes.
97-3 and 70-23-7
O₂: 97% Hb, 3% plasma. CO₂: 70% bicarbonate, 20–25% carbamino-Hb, 7% dissolved.
Use it when: Transport shares.
CADET, face right
CO₂, Acid (H⁺), 2,3-BPG, Exercise, Temperature shift the curve to the right.
Use it when: Dissociation curve shifts.
Bicarb out, chloride in
In tissues HCO₃⁻ leaves the RBC and Cl⁻ enters (chloride shift).
Use it when: CO₂ transport.
Breathing and Exchange of Gases: exam-level solved questions
Ordered from exam level to HOTS. Cover the solution, write your own, then compare step by step.
Example 1: Residual volume · 1 mark · MCQExam level
The volume of air remaining in the lungs after a forcible expiration is the:
(a) tidal volume
(b) expiratory reserve volume
(c) residual volume
(d) vital capacity
Try it first, then show the solutionSolution
- Air left even after forced expiration is the residual volume (about 1100–1200 mL).
Answer: (c)
Example 2: CO₂ diffusion · 1 mark · Assertion-reasonHarder exam level
Assertion: CO₂ diffuses from blood to alveoli efficiently even though its partial pressure gradient is only about 5 mm Hg.
Reason: The solubility of CO₂ is 20–25 times that of O₂.
(a) Both Assertion and Reason are true, and Reason is the correct explanation for Assertion.
(b) Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion.
(c) Assertion is true and Reason is false.
(d) Assertion is false and Reason is true.
Try it first, then show the solutionSolution
- Higher solubility means more CO₂ diffuses per unit pressure difference, explaining efficient exchange.
Answer: (a)
Example 3: Chloride shift · 2 marks · Short answerHarder exam level
What is the chloride shift? Where and why does it occur? [2]
Try it first, then show the solutionSolution
- In tissue capillaries, HCO₃⁻ formed in RBCs (by carbonic anhydrase) diffuses into plasma and Cl⁻ moves from plasma into RBCs
- This exchange keeps the RBC electrically neutral; it reverses in the lungs
Answer: As above
Example 4: Regulation · 3 marks · Short answerHarder exam level
Describe how breathing is regulated in humans. [3]
Try it first, then show the solutionSolution
- Respiratory rhythm centre in the medulla sets the basic rhythm; pneumotaxic centre in the pons moderates it by shortening inspiration
- A chemosensitive area beside the rhythm centre responds to rising CO₂ and H⁺ and increases breathing
- Receptors in the aortic arch and carotid arteries also detect CO₂ and H⁺; O₂ has only a minor role normally
Answer: As above
Example 5: Transport of O₂ · 5 marks · Long answerHarder exam level
(a) Draw and explain the oxygen–haemoglobin dissociation curve. [3]
(b) What factors shift it to the right, and what is the significance of the shift? [2]
Try it first, then show the solutionSolution
- (a) Plot % saturation of Hb against pO₂; sigmoid shape
- At alveolar pO₂ (about 104 mm Hg) Hb is nearly fully saturated; in tissues (about 40) saturation falls steeply, so O₂ is released
- The steep middle part means a small fall in pO₂ releases a lot of O₂
- (b) High pCO₂, high H⁺ (low pH), high temperature
- Lower affinity in active tissues so more O₂ is unloaded where demand is greatest (Bohr effect)
Answer: As above
Example 6: Lung volumes · 3 marks · Short answerHarder exam level
A person has tidal volume 500 mL, IRV 3000 mL, ERV 1000 mL and RV 1200 mL, and breathes 14 times a minute. Calculate (a) vital capacity (b) total lung capacity (c) pulmonary ventilation per minute (d) alveolar ventilation per minute if dead space is 150 mL. [3]
Try it first, then show the solutionSolution
- (a) VC = 500 + 3000 + 1000 = 4500 mL; (b) TLC = 4500 + 1200 = 5700 mL
- (c) 500 × 14 = 7000 mL per minute
- (d) (500 − 150) × 14 = 4900 mL per minute
Answer: 4500 mL; 5700 mL; 7000 mL/min; 4900 mL/min
Example 7: Shallow, fast breathing · 3 marks · Short answerHOTS / competency
Person A breathes 500 mL × 12 per minute; person B breathes 250 mL × 24 per minute. Both move 6000 mL a minute. With a dead space of 150 mL, compare their alveolar ventilation and explain which breathing pattern is more effective. [3]
Try it first, then show the solutionSolution
- A: (500 − 150) × 12 = 4200 mL per minute
- B: (250 − 150) × 24 = 2400 mL per minute
- Each breath wastes 150 mL in the dead space, so shallow rapid breathing wastes a larger fraction; deep, slow breathing is more effective
Answer: A 4200 mL/min vs B 2400 mL/min; deep breathing is more effective
Example 8: Oxygen delivery · 3 marks · Short answerHOTS / competency
Blood contains 15 g haemoglobin per 100 mL, and each gram can carry 1.34 mL O₂ when fully saturated. Arterial blood is 97% saturated; venous blood leaving resting muscle is 75% saturated, and during exercise 25%. Calculate the O₂ delivered per 100 mL of blood at rest and during exercise, and explain the difference. [3]
Try it first, then show the solutionSolution
- Capacity = 15 × 1.34 = 20.1 mL O₂ per 100 mL
- Rest: 20.1 × (0.97 − 0.75) = 4.4 mL; exercise: 20.1 × (0.97 − 0.25) = 14.5 mL
- In exercising muscle, pO₂ is lower and pCO₂, H⁺ and temperature are higher, shifting the curve right so Hb unloads far more O₂
Answer: About 4.4 mL at rest and 14.5 mL in exercise per 100 mL
Case-study practice (Section D style)
Read the situation, then answer every part. In a school exam set on the board pattern this is a 5-mark question split into 1 + 1 + 1 + 2 marks.
A spirometry test
Suppose a school health camp tests students with a spirometer. One student, a regular swimmer, records a vital capacity of 5000 mL; another, who has asthma, records 3200 mL.
(i) · 1 mark
Define vital capacity.
Answer
Answer: Maximum volume of air that can be breathed out after a forced inspiration (ERV + TV + IRV)
Sum of three volumes.
(ii) · 1 mark
Why can't the spirometer measure total lung capacity?
Answer
Answer: Residual volume never leaves the lungs, so it cannot be measured by breathing into a spirometer
TLC = VC + RV.
(iii) · 1 mark
Why might the swimmer have a higher vital capacity?
Answer
Answer: Regular training strengthens respiratory muscles and increases the expansion of the chest
Athletes have larger VC.
(iv) · 2 marks
Explain why asthma reduces air flow.
Answer
Answer: Inflammation and spasm of bronchi and bronchioles with extra mucus narrow the airways, so less air moves per breath and expiration is difficult (wheezing)
Airway narrowing.
Breath-holding diver
Imagine a pearl diver who holds her breath under water for two minutes and then surfaces gasping.
(i) · 1 mark
Which gas builds up and drives the urge to breathe?
Answer
Answer: CO₂ (with H⁺)
Detected by chemosensitive area.
(ii) · 1 mark
Name the centre that sets breathing rhythm.
Answer
Answer: Respiratory rhythm centre in the medulla oblongata
Neural control.
(iii) · 1 mark
In which form is most CO₂ carried in her blood?
Answer
Answer: Bicarbonate ions (about 70%)
Formed by carbonic anhydrase.
(iv) · 2 marks
Why do her muscles keep receiving O₂ even as her blood pO₂ falls?
Answer
Answer: Falling pO₂ and rising pCO₂ and H⁺ shift the dissociation curve right, so haemoglobin releases more of its O₂ to tissues
Bohr effect.
Where the marks are
How a typical answer is split into step marks. Show every step: a right final answer alone rarely earns full marks.
Name the three layers of the diffusion membrane in the lungs. (2 marks)
| Step | Marks |
|---|---|
| Squamous epithelium of the alveolus; endothelium of the alveolar capillary | 1 |
| Basement substance between them | 1 |
Explain the mechanism of inspiration. (3 marks)
| Step | Marks |
|---|---|
| Diaphragm contracts and flattens: thoracic volume increases antero-posteriorly | 1 |
| External intercostal muscles contract, raising ribs and sternum: volume increases dorso-ventrally | 1 |
| Lung volume rises, intra-pulmonary pressure falls below atmospheric, air flows in | 1 |
Explain how carbon dioxide is transported in blood. (5 marks)
| Step | Marks |
|---|---|
| About 7% dissolved in plasma | 1 |
| About 20–25% as carbaminohaemoglobin; favoured by high pCO₂ and low pO₂ in tissues | 1 |
| About 70% as bicarbonate: carbonic anhydrase in RBC converts CO₂ + H₂O to H₂CO₃, which dissociates to HCO₃⁻ and H⁺ | 1 |
| HCO₃⁻ moves to plasma and Cl⁻ enters RBC (chloride shift) | 1 |
| In lungs the reactions reverse and CO₂ diffuses into alveoli; about 4 mL CO₂ released per 100 mL blood | 1 |
Where students lose marks in Breathing and Exchange of Gases
The slips examiners see most often, and what to write instead.
Mistake: Saying expiration is caused by muscle contraction at rest
Both phases are assumed to be active.
Wrong working
Internal intercostals contract in every expiration.
Right working
Normal expiration is passive (relaxation and elastic recoil); internal intercostals and abdominal muscles act only in forced expiration.
Do this: Specify 'normal' or 'forced'.
Usually costs: 1 mark.
Mistake: Adding the wrong volumes
Capacities are confused.
Wrong working
VC = TV + IRV + ERV + RV.
Right working
VC excludes RV; TLC = VC + RV.
Do this: VC is what you can blow out.
Usually costs: 1-2 marks.
Mistake: Saying CO₂ binds to the iron of haemoglobin
CO₂ and O₂ are assumed to bind the same site.
Wrong working
Carbaminohaemoglobin forms when CO₂ binds to haem iron.
Right working
CO₂ binds to amino groups of the globin protein; O₂ binds to iron.
Do this: Carbamino = amino group.
Usually costs: 1 mark.
Mistake: Saying O₂ is the main regulator of breathing
We breathe to get oxygen.
Wrong working
Low O₂ is the main stimulus for breathing.
Right working
Rising CO₂ and H⁺ are the main stimuli; O₂ plays a minor role normally.
Do this: CO₂ drives the urge to breathe.
Usually costs: 1 mark.
Mistake: Wrong direction of chloride shift
Ion movements are reversed.
Wrong working
In tissues Cl⁻ leaves the RBC.
Right working
In tissues HCO₃⁻ leaves and Cl⁻ enters the RBC; the reverse occurs in the lungs.
Do this: Bicarb out, chloride in (at tissues).
Usually costs: 1 mark.
Practice questions on Breathing and Exchange of Gases
Write each answer on paper first. Open the hint only if you are stuck, and the answer only when you have finished.
Q1 · 1 mark · MCQExam level
The respiratory rhythm centre is located in the:
(a) cerebrum
(b) pons
(c) medulla oblongata
(d) cerebellumHint
Hindbrain.
Answer
(c)
Q2 · 1 mark · MCQExam level
Most CO₂ is transported in blood as:
(a) dissolved CO₂
(b) carbaminohaemoglobin
(c) bicarbonate
(d) carbonic acidHint
About 70%.
Answer
(c)
Q3 · 1 mark · Very short answerExam level
Name the flap that prevents food from entering the larynx.
Hint
Covers the glottis.
Answer
Epiglottis
Q4 · 1 mark · Very short answerExam level
Name the enzyme in RBCs that speeds up the formation of carbonic acid.
Hint
Contains zinc.
Answer
Carbonic anhydrase
Q5 · 2 marks · Short answerExam level
Name the respiratory organs of an earthworm, a cockroach and a fish.
Hint
Recall.
Answer
Earthworm: moist skin (cuticle); cockroach: tracheal tubes; fish: gills.
Q6 · 2 marks · Short answerHarder exam level
Distinguish between the conducting part and the respiratory part of the respiratory system.
Hint
Exchange happens where?
Answer
Conducting part: nostrils to terminal bronchioles; transports air, warms, humidifies and filters it; no exchange. Respiratory part: alveoli and alveolar ducts; site of actual diffusion of O₂ and CO₂.
Q7 · 2 marks · Short answerHarder exam level
What is the significance of the sigmoid shape of the dissociation curve?
Hint
Flat top, steep middle.
Answer
The flat top ensures near-full loading even if alveolar pO₂ falls a little; the steep middle means that a small fall in pO₂ in tissues releases a large amount of O₂.
Q8 · 3 marks · Short answerHarder exam level
Define tidal volume, inspiratory reserve volume and expiratory reserve volume, giving approximate values.
Hint
500; 2500–3000; 1000–1100.
Answer
TV: air moved in a normal breath, about 500 mL. IRV: extra air inspired by forcible inspiration after a normal one, about 2500–3000 mL. ERV: extra air expired by forcible expiration after a normal one, about 1000–1100 mL.
Q9 · 3 marks · Short answerHarder exam level
Describe asthma and emphysema and give one cause of each.
Hint
Bronchi vs alveoli.
Answer
Asthma: inflammation and narrowing of bronchi and bronchioles causing wheezing and breathlessness; often allergic (dust, pollen). Emphysema: chronic damage to alveolar walls, reducing respiratory surface and lung elasticity; mainly due to cigarette smoking.
Q10 · 3 marks · Short answerHarder exam level
Give the typical partial pressures of O₂ and CO₂ in alveoli, deoxygenated blood and tissues, and use them to explain the direction of diffusion.
Hint
104/40; 40/45; 40/45.
Answer
Alveoli pO₂ 104, pCO₂ 40; deoxygenated blood pO₂ 40, pCO₂ 45; tissues pO₂ 40, pCO₂ 45 (oxygenated blood pO₂ 95, pCO₂ 40). O₂ moves alveoli → blood → tissues; CO₂ moves tissues → blood → alveoli, each from higher to lower partial pressure.
Q11 · 5 marks · Long answerHarder exam level
(a) Draw a labelled diagram of the human respiratory system. [3]
(b) Explain the role of the pleura and of cartilage rings. [2]Hint
Nostrils to alveoli.
Answer
(a) Diagram with nasal chamber, pharynx, epiglottis, larynx, trachea with rings, bronchi, bronchioles, alveoli, lungs, pleura, diaphragm. (b) Pleura: double membrane with pleural fluid that reduces friction as lungs expand and keeps them attached to the chest wall. Cartilage rings keep the trachea and bronchi open against pressure changes.
Q12 · 5 marks · Long answerHarder exam level
(a) Explain the transport of oxygen in blood. [3]
(b) What are occupational respiratory disorders? Give two examples and one preventive measure. [2]Hint
97% Hb.
Answer
(a) About 97% bound to Hb (up to 4 O₂ per molecule) as oxyhaemoglobin; 3% dissolved in plasma. Loading at high pO₂ in lungs; unloading in tissues at low pO₂, high pCO₂, H⁺ and temperature; about 5 mL O₂ per 100 mL blood delivered at rest. (b) Lung diseases due to long exposure to dust at work, causing inflammation and fibrosis, e.g. silicosis and asbestosis; workers should wear protective masks.
Q13 · 2 marks · Short answerHarder exam level
A person breathes 16 times per minute with a tidal volume of 450 mL. Calculate the pulmonary ventilation and the alveolar ventilation (dead space 150 mL).
Hint
TV × f.
Answer
Pulmonary ventilation = 450 × 16 = 7200 mL/min; alveolar ventilation = (450 − 150) × 16 = 4800 mL/min.
Q14 · 3 marks · Short answerHOTS / competency
Foetal haemoglobin has a dissociation curve to the left of adult haemoglobin. Explain why this is an advantage to the foetus.
Hint
Higher affinity.
Answer
A curve to the left means higher affinity for O₂ at the same pO₂. In the placenta, the mother's haemoglobin (lower affinity) releases O₂ while the foetal haemoglobin, with higher affinity, picks it up even at the low pO₂ there, so O₂ moves from mother to foetus.
Q15 · 3 marks · Short answerHOTS / competency
A patient's lung disease thickens the diffusion membrane but does not change lung volumes. Predict the effect on blood O₂ and CO₂ levels and explain which gas is affected more.
Hint
Solubility.
Answer
A thicker membrane slows diffusion of both gases, so blood leaving the lungs carries less O₂ and more CO₂ than normal. O₂ is affected more because it is far less soluble than CO₂; CO₂, being 20–25 times more soluble, still diffuses relatively well, so low blood O₂ appears first.
Test your recall
Answer in your head or on paper first, then open the card. Pulling an answer out of memory makes it stick far better than re-reading.
1.Sound box?Show answer
Larynx.
2.Membrane covering the lungs?Show answer
Pleura (double-layered).
3.Muscles contracting in normal inspiration?Show answer
Diaphragm and external intercostals.
4.Alveolar pO₂?Show answer
About 104 mm Hg.
5.O₂ carried by haemoglobin?Show answer
About 97%.
6.Chloride shift is also called?Show answer
Hamburger phenomenon.
7.Typical tidal volume?Show answer
About 500 mL.
8.Centre that moderates the rhythm?Show answer
Pneumotaxic centre (pons).
Best order to study it
- Recall respiratory organs of animals, then learn the human respiratory system with a diagram.
- Learn the mechanism of breathing with muscles, volume and pressure changes.
- Learn partial pressures and gas exchange across the diffusion membrane.
- Learn O₂ transport and the dissociation curve.
- Learn CO₂ transport and chloride shift, then regulation of breathing.
- Finish with lung volumes, capacities, calculations and disorders.
Quick revision checklist
The night before the exam: can you do each of these without looking?
- Can you trace the path of air from nostrils to alveoli?
- Can you explain inspiration and expiration?
- Can you quote partial pressures of O₂ and CO₂ in alveoli, blood and tissues?
- Can you draw the dissociation curve and explain right shift?
- Can you describe the three forms of CO₂ transport?
- Can you explain chloride shift?
- Can you define all lung volumes and capacities?
- Can you describe asthma, emphysema and silicosis?
Breathing and Exchange of Gases: frequently asked questions
How much do I need to know about respiratory organs in other animals?
The ISC 2028 syllabus says recall only: name the respiratory organs of a few groups, such as skin in earthworms, tracheae in insects, gills in fishes and lungs in land vertebrates.
Why can't all air be breathed out of the lungs?
The residual volume stays because the rib cage and lungs cannot collapse completely. It keeps alveoli open and allows gas exchange to continue between breaths.
What is the Bohr effect?
The reduction in haemoglobin's affinity for O₂ caused by high pCO₂ and H⁺ (low pH). It shifts the dissociation curve to the right and helps release O₂ in active tissues.
Why does breathing through the nose matter?
The nasal chamber filters dust with hairs and mucus, and warms and moistens the air before it reaches the delicate alveoli.
Is smoking linked only to emphysema?
No. Smoking damages the lining of the airways, reduces ciliary cleaning, and is linked to bronchitis, lung cancer and heart disease as well as emphysema.
What is anatomical dead space?
The air (about 150 mL) that fills the conducting passages at the end of each inspiration and never reaches the alveoli, so it takes no part in gas exchange.
Based on: CISCE ISC 2028 Biology syllabus (Classes XI and XII); CISCE Regulations for the ISC Examination Year 2028 (Class XI internal examination)