CBSE Class 12 Chemistry sample paper 2025-26: question 19
From the official CBSE sample question paper for 2025-26, section B, question 19, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q19 · 2 marks · Very short answerAmines
Carry out following conversions :
I. Nitrobenzene to 4- bromobenzenamine
II. Chlorophenylmethane to 2-phenyl-ethanamine
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2025-26.
Hints
Open one hint at a time and try again before the next.
Hint 1
For I, first make aniline, then protect –NH₂ so that only one Br enters at the para position.
Hint 2
For II, the product has one more carbon than the starting compound, so which reagent adds a carbon and can be reduced to –CH₂NH₂?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
I. Nitrobenzene aniline acetanilide 4-bromoacetanilide 4-bromobenzenamine.
Acetylation lowers the activating power of –NH, so mainly the mono para-bromo product forms.
- 1 mark
II. (2-phenylethanamine).
Answer: I. PhNO₂ → (Sn/HCl) PhNH₂ → (Ac₂O) PhNHCOCH₃ → (Br₂) p-BrC₆H₄NHCOCH₃ → (hydrolysis) p-BrC₆H₄NH₂. II. PhCH₂Cl → (KCN) PhCH₂CN → (LiAlH₄) PhCH₂CH₂NH₂.
Where the marks are
- Correct sequence: reduction, acetylation, bromination, hydrolysis (1 mark)
- Cyanide substitution then reduction to 2-phenylethanamine (1 mark)
Revise the chapter
- Chapter: Amines (notes, formulas, where marks are lost and every past question)
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