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ChemistryCBSE Class 12 · Board exam 2025, set 56/1/1 · 1 mark · MCQ

CBSE Class 12 Chemistry 2025: question 10

Set in the CBSE Class 12 board exam of 2025, paper 56/1/1, section A, question 10, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q10 · 1 mark · MCQAmines

The best reagent for converting propanamide into propanamine is ________.

  1. (A)excess
  2. (B) in aqueous NaOH
  3. (C)iodine in the presence of red phosphorus
  4. (D) in ether

Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 56/1/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Count the carbons in propanamide and in propanamine.

Hint 2

Hofmann degradation removes one carbon.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Propanamine must keep all three carbons. reduces to .

  2. /NaOH (Hofmann degradation) would remove one carbon and give ethanamine. So the best reagent is in ether, option (D).

    1 mark

Answer: LiAlH₄ in ether, option (D)

Where the marks are

  • Chooses LiAlH₄ and recognises the carbon count is kept (1 mark)

Revise the chapter

  • Chapter: Amines (notes, formulas, where marks are lost and every past question)

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.