CBSE Class 12 Chemistry 2025: question 10
Set in the CBSE Class 12 board exam of 2025, paper 56/1/1, section A, question 10, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q10 · 1 mark · MCQAmines
The best reagent for converting propanamide into propanamine is ________.
- (A)excess
- (B) in aqueous NaOH
- (C)iodine in the presence of red phosphorus
- (D) in ether
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 56/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Count the carbons in propanamide and in propanamine.
Hint 2
Hofmann degradation removes one carbon.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
Propanamine must keep all three carbons. reduces to .
- 1 mark
/NaOH (Hofmann degradation) would remove one carbon and give ethanamine. So the best reagent is in ether, option (D).
Answer: LiAlH₄ in ether, option (D)
Where the marks are
- Chooses LiAlH₄ and recognises the carbon count is kept (1 mark)
Revise the chapter
- Chapter: Amines (notes, formulas, where marks are lost and every past question)
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