CBSE Class 12 Physics 2024: question 6
Set in the CBSE Class 12 board exam of 2024, paper 55/1/1, section A, question 6, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q6 · 1 mark · MCQMoving Charges and Magnetism
A galvanometer of resistance G Ω is converted into an ammeter of range 0 to I A. If the current through the galvanometer is 0.1% of I A, the resistance of the ammeter is :
- (A)
- (B)
- (C)
- (D)
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 55/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
First find the shunt from .
Hint 2
The ammeter's resistance is the galvanometer and shunt in parallel.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
With , the shunt is .
- 1 mark
The ammeter resistance is G in parallel with S: . Option (B).
Answer: , option (B)
Where the marks are
- Finds S = G/999 and the parallel combination G/1000 (1 mark)
Revise the chapter
- Chapter: Moving Charges and Magnetism (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.