CBSE Class 10 Mathematics Basic 2024: question 38
Set in the CBSE Class 10 board exam of 2024, paper 430/5/1, section E, question 38, for 4 marks. Try it first; the hints and our step-by-step solution are below.
Q38 · 4 marks · Case-basedCompetency-basedSome Applications of Trigonometry
Case Study – 3
Two poles of different heights stand on level ground and at a distance of 40 m. Both poles are supported by wires attached from the top of each pole to the bottom of the other. A coupling is placed at point C, where the two wires cross (as shown in the figure).
Based on the above information, answer the following questions :
- (i)1 mark
Find the height of pole AB.
- (ii)1 mark
Find the height of pole PQ.
- (iii)2 marks
(a) If the angle of elevation of the top of the pole PQ from the top of the pole AB is , find the distance BQ.
OR
(iii)2 marks(b) If the coupling is at a height of 20 m from the ground, how far down the wire from the smaller pole AB is the coupling ?
Figure in the paper: Two poles AB and PQ stand on level ground, with A and P at the base, 40 m apart (marked on the ground line). AB is the shorter pole (B at top) and PQ is the taller pole (Q at top). A wire runs from A to Q and another from P to B; the two wires cross at point C. At A, the angle between ground AP and wire AQ is . At P, the angle between ground PA and wire PB is . Right angles are at A and P. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 430/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Each pole, the ground and a wire form a right triangle, and the 40 m base is known.
Hint 2
Use tan of the given angle at the far end to get each pole's height: opposite side over the 40 m base.
Hint 3
For (iii), draw a horizontal line from B to PQ, or a perpendicular from C to the ground, to make a new right triangle with a known side.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
(i) In right (right angle at A):
- ½ mark
(i) m
- ½ mark
(ii) In right (right angle at P):
- ½ mark
(ii) m
- ½ mark
(iii)(a) Figure: draw , so ABMP is a rectangle and m. Then in right .
- ½ mark
(iii)(a)
- 1 mark
(iii)(a) m
- ½ mark
(iii)(b) Figure: draw , so m. In right , .
- ½ mark
(iii)(b)
- 1 mark
(iii)(b) m m. So the coupling is m along the wire from the foot A of pole AB.
Answer: (i) AB = 40√3/3 m; (ii) PQ = 40√3 m; (iii)(a) BQ = 80√3/3 m; (iii)(b) AC = 40√3/3 m
Where the marks are
- (i) Uses (½ mark)
- (i) Gets m (½ mark)
- (ii) Uses (½ mark)
- (ii) Gets m (½ mark)
- (iii)(a) Figure with , m (½ mark)
- (iii)(a) Uses (½ mark)
- (iii)(a) Gets m (1 mark)
- (iii)(b) Figure with m (½ mark)
- (iii)(b) Uses (½ mark)
- (iii)(b) Gets m (1 mark)
Revise the chapter
- Chapter: Some Applications of Trigonometry (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.