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MathsCBSE Class 10 · Basic · Board exam 2023, set 430/6/1 · 4 marks · Case-based

CBSE Class 10 Mathematics Basic 2023: question 36

Set in the CBSE Class 10 board exam of 2023, paper 430/6/1, section E, question 36, for 4 marks. Try it first; the hints and our step-by-step solution are below.

Q36 · 4 marks · Case-basedCompetency-basedAreas Related to Circles

For the inauguration of 'Earth day' week in a school, badges were given to volunteers. Organisers purchased these badges from an NGO, who made these badges in the form of a circle inscribed in a square of side 8 cm.

O is the centre of the circle and . Based on the above information, answer the following questions:

  1. (i)

    What is the area of square ABCD?

    1 mark
  2. (ii)

    What is the length of diagonal AC of square ABCD?

    1 mark
  3. (iii)

    Find the area of sector OPRQO.

    2 marks
  4. OR

    (iii)

    Find the area of remaining part of square ABCD when area of circle is excluded.

    2 marks

Figure in the paper: Square ABCD with A bottom-left, B bottom-right, C top-right, D top-left. A circle is inscribed in the square, touching all four sides; its centre O is marked in the middle. Side AB = 8 cm, with the point R marked at the bottom where the circle touches AB. Points P and Q lie on the circle near A and B respectively, and radii OP and OQ are drawn with AOB = 90° marked at O. Sector OPRQO is shaded/marked by the arc from P through R to Q. See it in the official paper.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/6/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

The diameter of the inscribed circle equals the side of the square.

Hint 2

For the diagonal, use Pythagoras theorem in triangle ABC.

Hint 3

Sector area is . For the remaining part, subtract the circle's area from the square's area.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. (i) Area of square ABCD

    1 mark
  2. (ii) By Pythagoras theorem in : cm

    1 mark
  3. (iii)(a) The radius of the inscribed circle is half the side: cm, and .
    Area of sector

    1 mark
  4. (about )

    1 mark
  5. (iii)(b) Area of circle

    1 mark
  6. Remaining area (about )

    1 mark

Answer: (i) 64 cm²; (ii) 8√2 cm; (iii)(a) 88/7 cm²; (iii)(b) 96/7 cm²

Where the marks are

  • Area of square = 64 cm² (1 mark)
  • Diagonal cm (1 mark)
  • (iii)(a) Uses sector formula with r = 4 and θ = 90° (1 mark); gets 88/7 cm² (1 mark)
  • (iii)(b) Area of circle = 352/7 cm² (1 mark); remaining area = 96/7 cm² (1 mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.