CBSE Class 10 Mathematics Standard 2026: question 30

Hints

Open one hint at a time and try again before the next.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

1. Area of minor sector $=\frac{\theta }{360^{\circ }}\times \pi r^2=\frac{30}{360}\times \frac{22}{7}\times 42\times 42$

   1 mark

2. $=\frac{1}{12}\times 5544=462$ cm²

   ½ mark

3. Angle of the major sector $=360^{\circ }-30^{\circ }=330^{\circ }$

   ½ mark

4. Area of major sector $=\frac{330}{360}\times \frac{22}{7}\times 42\times 42$

   ½ mark

5. $=\frac{11}{12}\times 5544=5082$ cm² (equivalently $5544-462$)

   ½ mark

Answer: Minor sector = 462 cm²; major sector = 5082 cm²

Revise the chapter

• Chapter: Areas Related to Circles (notes, formulas, where marks are lost and every past question)
• Topic: Area of a Sector of a Circle