CBSE Class 10 Mathematics Basic sample paper 2023-24: question 22(b)
From the official CBSE sample question paper for 2023-24, section B, question 22(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q22(b) · 2 marks · Very short answerTriangles
In figure, if cm, cm, cm and cm and . Find .
Figure in the paper: Triangle ABC with A at the top. D lies on side AB and E lies on side AC; DE is joined. Marked: AD = 6 cm, DB = 9 cm, AE = 8 cm, EC = 12 cm, and angle ADE = 48° at D. Angle ABC at B is marked. See it in the official paper.
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2023-24.
Hints
Open one hint at a time and try again before the next.
Hint 1
Compare the ratios and .
Hint 2
Equal ratios mean DE is parallel to BC (converse of BPT). Which angle at B corresponds to ?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
In : and , so .
- 1 mark
Therefore [converse of BPT]. So [corresponding angles], giving .
Answer:
Where the marks are
- Shows (1 mark)
- Concludes by the converse of BPT, and as corresponding angles (1 mark)
Revise the chapter
- Chapter: Triangles (notes, formulas, where marks are lost and every past question)
- Topic: Basic Proportionality Theorem (Thales Theorem)
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- 2023 board paper, set 430/1/1 (Basic), Q31(a) · 3 marksIn the given figure, DE ∥ AC and DF ∥ AE. Prove that BF/FE = BE/EC.
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.