CBSE Class 10 Mathematics Basic 2023: question 9
Set in the CBSE Class 10 board exam of 2023, paper 430/1/1, section A, question 9, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q9 · 1 mark · MCQTriangles
In the given figure, . If cm, cm and cm, then the length of OC is
- (A) cm
- (B) cm
- (C) cm
- (D) cm
Figure in the paper: Points B (top left), A (bottom left), D (top right) and C (bottom right). Segment BC and segment AD cross at point O. AB is marked 5 cm and CD is marked 2 cm, with arrow marks showing AB parallel to CD. BO is marked 3 cm. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Look for two similar triangles meeting at O.
Hint 2
Corresponding sides: OB matches OC, AB matches CD.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
(AA: alternate angles as , vertically opposite angles at O).
- 1 mark
cm. Option (C).
Answer: cm, option (C)
Where the marks are
- Uses similarity ratio to get cm (1 mark)
Revise the chapter
- Chapter: Triangles (notes, formulas, where marks are lost and every past question)
- Topic: Basic Proportionality Theorem (Thales Theorem)
More questions from Triangles
- 2023 board paper, set 430/1/1 (Basic), Q31(a) · 3 marksIn the given figure, DE ∥ AC and DF ∥ AE. Prove that BF/FE = BE/EC.
- 2023 board paper, set 430/1/1 (Basic), Q31(b) · 3 marksThe diagonals of a quadrilateral ABCD intersect each other at the point O such that AO/BO = CO/OD. Show that q…
- 2023 board paper, set 430/2/1 (Basic), Q21 · 2 marksIn the given figure, DE ∥ AC and BE/EC = BC/CP. Prove that DC ∥ AP.
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.