Skip to content
MathsCBSE Class 10 · Basic · Board exam 2023, set 430/1/1 · 3 marks · Short answer

CBSE Class 10 Mathematics Basic 2023: question 31(a)

Set in the CBSE Class 10 board exam of 2023, paper 430/1/1, section C, question 31(a), for 3 marks. Try it first; the hints and our step-by-step solution are below.

Q31(a) · 3 marks · Short answerTriangles

In the given figure, and . Prove that .

Figure in the paper: Triangle ABC with D on side AB and E, F, C on base BC in the order B, F, E, C. A is the apex. DE is drawn parallel to AC and DF is drawn parallel to AE, with F on BC between B and E. See it in the official paper.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/1/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Use the Basic Proportionality Theorem in two different triangles.

Hint 2

Both triangles ABE and ABC give a ratio involving .

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. In , [given], so by the Basic Proportionality Theorem, … (i)

    1½ marks
  2. In , [given], so by BPT, … (ii)

    1 mark
  3. From (i) and (ii), . Hence proved.

    ½ mark

Answer: BF/FE = BE/EC (proved using BPT twice)

Where the marks are

  • Applies BPT in to get (i) (1½ marks)
  • Applies BPT in to get (ii) (1 mark)
  • Equates the two to conclude (½ mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.