CBSE Class 10 Mathematics Basic 2023: question 31(a)
Set in the CBSE Class 10 board exam of 2023, paper 430/1/1, section C, question 31(a), for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q31(a) · 3 marks · Short answerTriangles
In the given figure, and . Prove that .
Figure in the paper: Triangle ABC with D on side AB and E, F, C on base BC in the order B, F, E, C. A is the apex. DE is drawn parallel to AC and DF is drawn parallel to AE, with F on BC between B and E. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Use the Basic Proportionality Theorem in two different triangles.
Hint 2
Both triangles ABE and ABC give a ratio involving .
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1½ marks
In , [given], so by the Basic Proportionality Theorem, … (i)
- 1 mark
In , [given], so by BPT, … (ii)
- ½ mark
From (i) and (ii), . Hence proved.
Answer: BF/FE = BE/EC (proved using BPT twice)
Where the marks are
- Applies BPT in to get (i) (1½ marks)
- Applies BPT in to get (ii) (1 mark)
- Equates the two to conclude (½ mark)
Revise the chapter
- Chapter: Triangles (notes, formulas, where marks are lost and every past question)
- Topic: Basic Proportionality Theorem (Thales Theorem)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.