CBSE Class 12 Physics 2023: question 25
Set in the CBSE Class 12 board exam of 2023, paper 55/5/1, section B, question 25, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q25 · 2 marks · Very short answerElectromagnetic Induction
Two coils and are placed close to each other. The magnetic flux linked with the coil varies with the current flowing in coil , as shown in the figure. Find
(i) the mutual inductance of the arrangement, and
(ii) the rate of change of current that will induce an emf of 100 V in coil .
Figure in the paper: Graph of (wb) on vertical axis (marks 5, 10, 15) versus (A) on horizontal axis (marks 2, 4, 6): a straight line through the origin rising to about 15 wb at = 6 A. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 55/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
The relation between the flux in C₂ and the current in C₁ is linear. What does its slope represent?
Hint 2
Use Faraday's law in the form ε = M dI₁/dt.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
(i) Flux linkage is related to current by , so the mutual inductance is the slope of the – graph.
- ½ mark
From the graph, H.
- ½ mark
(ii) The induced emf is .
- ½ mark
So .
Answer: (i) M = 2.5 H; (ii) dI₁/dt = 40 A/s
Where the marks are
- Uses φ₂ = MI₁ / slope (½ mark)
- M = 2.5 H (½ mark)
- Uses ε = M dI₁/dt (½ mark)
- dI₁/dt = 40 A s⁻¹ (½ mark)
Revise the chapter
- Chapter: Electromagnetic Induction (notes, formulas, where marks are lost and every past question)
- Topic: Self and Mutual Inductance
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