CBSE Class 12 Physics 2023: question 6
Set in the CBSE Class 12 board exam of 2023, paper 55/1/1, section A, question 6, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q6 · 1 mark · MCQElectromagnetic Induction
A circular coil of radius cm and 40 turns is rotated about its vertical diameter with an angular speed of rad s in a uniform horizontal magnetic field of magnitude T. The maximum emf induced in the coil is :
- (A)0·12 V
- (B)0·15 V
- (C)0·19 V
- (D)0·22 V
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 55/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Recall the peak emf of a rotating coil.
Hint 2
, with ; notice that the cancels.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
The maximum emf is .
- ½ mark
V. This is option (C).
Answer: 0.19 V, option (C)
Where the marks are
- Uses and gets 0.19 V (1 mark)
Revise the chapter
- Chapter: Electromagnetic Induction (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.