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An amine ‘X’ reacts with… (Class 12 Chemistry 2025, Q11)

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ChemistryCBSE Class 12 · Board exam 2025, set 56/7/1 · 1 mark · MCQ

CBSE Class 12 Chemistry 2025: question 11

Set in the CBSE Class 12 board exam of 2025, paper 56/7/1, section A, question 11, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q11 · 1 mark · MCQAmines

An amine ‘X’ reacts with Hinsberg reagent and the product obtained is soluble in alkali. The amine ‘X’ is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)N-methylaniline (benzene ring attached to )

Figure in the paper: Option D shows a benzene ring bonded to NH–CH3. See it in the official paper.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 56/7/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Alkali solubility needs an acidic H on the nitrogen of the sulphonamide.

Hint 2

How many H atoms are on N in each amine?

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. A primary amine forms an N-alkylbenzenesulphonamide with Hinsberg reagent. Its N–H is acidic because of the strong electron-withdrawing sulphonyl group, so the product dissolves in alkali.

    1 mark

  2. Secondary amines, including N-methylaniline, give products with no N–H, which are insoluble in alkali. Tertiary amines do not react. Hence X is .

Answer: (A)

Where the marks are

  • Primary amine gives an alkali-soluble sulphonamide (1 mark)

Revise the chapter

  • Chapter: Amines (notes, formulas, where marks are lost and every past question)
Practise this chapterBoard-style questions from Amines, one at a time, marked against the answer key and marking points.Back to the full paper2025 board paper, set 56/7/1: every question, by section.

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.