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ChemistryCBSE Class 12 · Sample paper, session 2025-26 · 1 mark · MCQ

CBSE Class 12 Chemistry sample paper 2025-26: question 5

From the official CBSE sample question paper for 2025-26, section A, question 5, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q5 · 1 mark · MCQSolutions

70 gm solute is dissolved in 700 gm solvent to prepare a solution having density 1.5 g/ml. The ratio of its molality and molarity will be:

  1. (A)0.77
  2. (B)1.4
  3. (C)0.73
  4. (D)1.3

Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2025-26.

Hints

Open one hint at a time and try again before the next.

Hint 1

Molality uses the mass of solvent; molarity uses the volume of solution.

Hint 2

Volume = (70 + 700)/1.5 mL.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Molality . Volume of solution mL, so molarity .

  2. Ratio .

    1 mark

Answer: 0.73, option (C)

Where the marks are

  • Correct ratio 0.73 using solution volume from density (1 mark)

Revise the chapter

  • Chapter: Solutions (notes, formulas, where marks are lost and every past question)

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.