CBSE Class 12 Chemistry sample paper 2025-26: question 5
From the official CBSE sample question paper for 2025-26, section A, question 5, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q5 · 1 mark · MCQSolutions
70 gm solute is dissolved in 700 gm solvent to prepare a solution having density 1.5 g/ml. The ratio of its molality and molarity will be:
- (A)0.77
- (B)1.4
- (C)0.73
- (D)1.3
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2025-26.
Hints
Open one hint at a time and try again before the next.
Hint 1
Molality uses the mass of solvent; molarity uses the volume of solution.
Hint 2
Volume = (70 + 700)/1.5 mL.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
Molality . Volume of solution mL, so molarity .
- 1 mark
Ratio .
Answer: 0.73, option (C)
Where the marks are
- Correct ratio 0.73 using solution volume from density (1 mark)
Revise the chapter
- Chapter: Solutions (notes, formulas, where marks are lost and every past question)
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