CBSE Class 12 Biology 2023: question 4
Set in the CBSE Class 12 board exam of 2023, paper 57/5/1, section A, question 4, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q4 · 1 mark · MCQMolecular Basis of Inheritance
Given below is a sequence of bases in mRNA of a bacterial cell. Identify the amino acid that would be incorporated at codon position 3 and codon position 5 during the process of its translation.
3' AUCAGGUUUGUGAUGGUACGA 5'
- (A)Phenylalanine, Methionine
- (B)Cysteine, Glycine
- (C)Alanine, Proline
- (D)Serine, Valine
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 57/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Remember the direction in which ribosomes read mRNA.
Hint 2
Reverse the sequence so that it reads 5′→3′, then split it into triplets.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Read the mRNA 5′→3′: AGC AUG GUA GUG UUU GGA CUA. Codon 3 is GUA (Valine) and codon 5 is UUU (Phenylalanine).
- ½ mark
Read as written instead: AUC AGG UUU GUG AUG … gives codon 3 = UUU (Phe) and codon 5 = AUG (Met), which is option (A). Translation is always 5′→3′, so no option is strictly correct. The board awards the mark for any attempt.
Answer: No correct option; mark awarded for attempting
Where the marks are
- Award 1 mark for attempting the question (1 mark)
Revise the chapter
- Chapter: Molecular Basis of Inheritance (notes, formulas, where marks are lost and every past question)
- Topic: Genetic Code and Translation
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.