CBSE Class 10 Science 2026: question 37
Set in the CBSE Class 10 board exam of 2026, paper 31/2/1, section C, question 37, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q37 · 3 marks · Short answerElectricity
The values of current flowing in a given resistor for the corresponding values of potential difference applied across the ends of resistor are given below in the table :
| (Amperes) | 0·4 | 0·8 | 1·2 | 1·6 | 2·0 |
|---|---|---|---|---|---|
| (Volts) | 1·2 | 2·4 | 3·6 | 4·8 | 6·0 |
Plot a graph between and and calculate the resistance of that resistor.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 31/2/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Plot on the x-axis and on the y-axis; what shape do the points make?
Hint 2
The slope of a – graph gives resistance.
Hint 3
Choose two points far apart on the line and find .
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 2 marks
Graph: Take current (A) on the x-axis and potential difference (V) on the y-axis with a suitable scale (e.g. 1 cm = 0.2 A, 1 cm = 0.6 V). Plot the points (0.4, 1.2), (0.8, 2.4), (1.2, 3.6), (1.6, 4.8), (2.0, 6.0). Joining them gives a straight line passing through the origin, which shows (Ohm's law).
- ½ mark
Resistance = slope of the – graph. Take points A(0.4 A, 1.2 V) and B(2.0 A, 6.0 V) on the line, with C at (2.0 A, 1.2 V):
- ½ mark
Answer: Straight-line – graph through the origin;
Where the marks are
- Correctly plotted straight-line – graph with labelled axes (2 marks)
- Uses slope = with substitution (½ mark)
- (½ mark)
Revise the chapter
- Chapter: Electricity (notes, formulas, where marks are lost and every past question)
- Topic: Ohm's Law
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.