CBSE Class 10 Science 2023: question 31(a)
Set in the CBSE Class 10 board exam of 2023, paper 31/2/1, section C, question 31(a), for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q31(a) · 3 marks · Short answerLight – Reflection and Refraction
A student has focussed the image of an object of height 3 cm on a white screen using a concave mirror of focal length 12 cm. If the distance of the object from the mirror is 18 cm, find the values of the following :
- (i)1 mark
Distance of the image from the mirror
- (ii)1 mark
Height of the image
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 31/2/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Use the sign convention: distances measured against incident light are negative, and a concave mirror has negative f.
Hint 2
Apply 1/v + 1/u = 1/f and solve for v.
Hint 3
Then use h′/h = −v/u to find the image height.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Given (New Cartesian sign convention): cm, cm (concave mirror), cm.
- ½ mark
(i) Mirror formula: , so
- ½ mark
- ½ mark
cm. The image is 36 cm in front of the mirror, which is where the screen is.
- ½ mark
(ii) Magnification: , so
- ½ mark
cm. The image is 6 cm tall, real and inverted.
Answer: (i) v = −36 cm (36 cm in front of the mirror); (ii) h′ = −6 cm (6 cm, inverted)
Where the marks are
- Correct data with signs (½ mark)
- Mirror formula (½ mark)
- Correct substitution (½ mark)
- v = −36 cm (½ mark)
- Magnification formula (½ mark)
- h′ = −6 cm (½ mark)
Revise the chapter
- Chapter: Light – Reflection and Refraction (notes, formulas, where marks are lost and every past question)
- Topic: Mirror Formula, Magnification and Sign Convention
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.