CBSE Class 10 Mathematics Standard 2026: question 25
Set in the CBSE Class 10 board exam of 2026, paper 30/5/1, section B, question 25, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q25 · 2 marks · Very short answerProbability
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is , then find the number of yellow balls.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 30/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
The two events 'yellow' and 'green' are complementary.
Hint 2
Find P(yellow) first.
Hint 3
P(yellow) = number of yellow balls ÷ total balls.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Each ball is either yellow or green, so , i.e. .
- 1 mark
Number of yellow balls .
Answer: 10 yellow balls
Where the marks are
- Uses (1 mark)
- Number of yellow balls = 10 (1 mark)
Revise the chapter
- Chapter: Probability (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.