CBSE Class 10 Mathematics Basic 2025: question 25(a)
Set in the CBSE Class 10 board exam of 2025, paper 430/2/1, section B, question 25(a), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q25(a) · 2 marks · Very short answerAreas Related to Circles
The area of a smaller circle is equal to the area of a sector of a larger circle with central angle . The radii of the smaller and larger circles are 'r' and 'R' respectively. Find r : R.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 430/2/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Area of a sector of angle θ is (θ/360°) × πR².
Hint 2
Equate the two areas and cancel π, then take square roots.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Area of smaller circle = area of sector of larger circle: .
- ½ mark
.
- ½ mark
, so .
Answer: r : R = 1 : √3
Where the marks are
- Forms the equation (1 mark)
- Gets (½ mark)
- Gets (½ mark)
Revise the chapter
- Chapter: Areas Related to Circles (notes, formulas, where marks are lost and every past question)
- Topic: Area of a Sector of a Circle
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