CBSE Class 10 Mathematics Basic 2025: question 25
Set in the CBSE Class 10 board exam of 2025, paper 430/3/1, section B, question 25, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q25 · 2 marks · Very short answerAreas Related to Circles
In the given figure, OPRQ is a quadrant of a circle with centre O and radius 10 cm. If OP = 10 cm and OS = 6 cm, find the area of the shaded region. (Use )
Figure in the paper: Quadrant OPRQ of a circle with centre O at bottom right; P is at the left end of the horizontal radius OP (10 cm), Q is at the top of the vertical radius OQ, and R is a point on the arc PQ. S lies on OQ with OS = 6 cm. The shaded region is bounded by the arc PRQ, the segment QS along OQ, and the segment SP. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 430/3/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
The shaded part is the quadrant with one triangle removed. Which triangle?
Hint 2
Triangle POS is right-angled at O with legs 10 cm and 6 cm.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Area of shaded region = Area of quadrant OPRQ − Area of
- 1 mark
Answer: 48.5 cm²
Where the marks are
- Writes shaded area = quadrant − ΔPOS with correct substitution (1 mark)
- Gets 48.5 cm² (1 mark)
Revise the chapter
- Chapter: Areas Related to Circles (notes, formulas, where marks are lost and every past question)
- Topic: Area of a Sector of a Circle
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.