CBSE Class 10 Mathematics Basic 2024: question 26

Hints

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Step-by-step solution

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1. (i) The angle of the minor sector is $\theta =90^{\circ }$ and $r=10$ cm. Area of minor sector $=\frac{\theta }{360^{\circ }}\pi r^2=\frac{90}{360}\times 3.14\times 10\times 10$

   1 mark

2. $=\frac{314}{4}=78.5{\text{cm}}^2$

   ½ mark

3. (ii) Area of the circle $=\pi r^2=3.14\times 10\times 10=314{\text{cm}}^2$

   1 mark

4. Area of major sector $=314-78.5=235.5{\text{cm}}^2$

   ½ mark

Answer: (i) 78.5 cm²; (ii) 235.5 cm²

Revise the chapter

• Chapter: Areas Related to Circles (notes, formulas, where marks are lost and every past question)
• Topic: Area of a Sector of a Circle