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MathsCBSE Class 10 · Basic · Board exam 2024, set 430/2/1 · 5 marks · Long answer

CBSE Class 10 Mathematics Basic 2024: question 32

Set in the CBSE Class 10 board exam of 2024, paper 430/2/1, section D, question 32, for 5 marks. Try it first; the hints and our step-by-step solution are below.

Q32 · 5 marks · Long answerQuadratic Equations

A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day. On a particular day, the total cost of production was ₹ 750. Find the total number of toys produced on that day.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 430/2/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Let the number of toys be and write the cost of one toy in terms of .

Hint 2

Total cost = (number of toys) × (cost of one toy). Set this equal to 750.

Hint 3

Rearrange into a quadratic and factorise: look for two numbers with product 750 and sum 55.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Let the number of toys produced that day be . Then the cost of each toy is ₹.

    ½ mark
  2. Total cost number of toys cost per toy:

    1 mark
  3. 1 mark
  4. Split the middle term, since and :

    1½ marks
  5. or . Both values give a total cost of ₹750 (25 × ₹30 or 30 × ₹25). So 25 or 30 toys were produced that day.

    1 mark

Answer: 25 toys or 30 toys

Where the marks are

  • Takes the number of toys as and the cost per toy as (½ mark)
  • Forms (1 mark)
  • Gets (1 mark)
  • Factorises as (1½ marks)
  • Gets or (1 mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.