CBSE Class 10 Mathematics Basic 2026: question 32(a)
Set in the CBSE Class 10 board exam of 2026, paper 430/3/1, section D, question 32(a), for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q32(a) · 5 marks · Long answerQuadratic Equations
Find two consecutive odd integers, sum of whose squares is 290.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 430/3/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Consecutive odd integers differ by 2, so take them as x and x + 2.
Hint 2
Form the equation from the sum of squares, simplify, and factorise; look for two numbers with product −143 and sum 2.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Let the two consecutive odd integers be and .
- 1½ marks
According to the question:
- 1½ marks
- 1 mark
or
- ½ mark
The required integers are 11 and 13. Check: . (The root gives the pair , which also works.)
Answer: 11 and 13 (also −13 and −11)
Where the marks are
- Takes the integers as x and x + 2 (½ mark)
- Forms (1½ marks)
- Simplifies to (1½ marks)
- Solves to get x = 11 (1 mark)
- States the integers 11 and 13 (½ mark)
Revise the chapter
- Chapter: Quadratic Equations (notes, formulas, where marks are lost and every past question)
- Topic: Word Problems on Quadratic Equations
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