CBSE Class 10 Mathematics Standard 2024: question 21
Set in the CBSE Class 10 board exam of 2024, paper 30/4/1, section B, question 21, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q21 · 2 marks · Very short answerCompetency-basedReal Numbers
Three bells toll at intervals of 9, 12 and 15 minutes respectively. If they start tolling together, after what time will they next toll together ?
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 30/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
The bells toll together at a time that is a multiple of every interval.
Hint 2
Find the smallest common multiple of 9, 12 and 15 using prime factorisation.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Prime factorise the intervals: , , .
- 1 mark
The bells next toll together after the LCM of the intervals: . So they toll together again after 180 minutes, i.e. 3 hours.
Answer: After 180 minutes (3 hours)
Where the marks are
- Correct prime factorisation of 9, 12 and 15 (1 mark)
- LCM = 180, so the bells toll together after 180 min (1 mark)
Revise the chapter
- Chapter: Real Numbers (notes, formulas, where marks are lost and every past question)
- Topic: HCF and LCM by Prime Factorisation
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.