CBSE Class 10 Mathematics Basic 2023: question 31(a)
Set in the CBSE Class 10 board exam of 2023, paper 430/6/1, section C, question 31(a), for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q31(a) · 3 marks · Short answerIntroduction to Trigonometry
Prove that .
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/6/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Replace cot A by cos A / sin A.
Hint 2
After simplifying to (1 − sin A)/(1 + sin A), multiply top and bottom by (1 + sin A).
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
LHS
- 1 mark
Taking common from numerator and denominator:
- 1 mark
Multiplying numerator and denominator by :
- ½ mark
RHS [since ]
Answer: LHS = RHS, hence proved
Where the marks are
- Writes cot A as cos A / sin A (½ mark)
- Simplifies to (1 − sin A)/(1 + sin A) (1 mark)
- Multiplies by (1 + sin A) above and below (1 mark)
- Uses identity to reach cos²A/(1 + sin A)² (½ mark)
Revise the chapter
- Chapter: Introduction to Trigonometry (notes, formulas, where marks are lost and every past question)
More questions from Introduction to Trigonometry
- 2023 board paper, set 430/6/1 (Basic), Q31(b) · 3 marksProve that (θ + θ)(1 - θ) = θ.
- 2026 board paper, set 30/5/1 (Standard), Q28 · 3 marksProve that: (θ)/(1 - θ) + (θ)/(1 - θ) = 1 + θ + θ.
- Sample paper 2026-27 (Standard), Q8 · 1 markIf (A + B) = √(3) and (A - B) = (1)/(√(3)), 0° B, then the value of A and B respectively are:
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.