CBSE Class 10 Mathematics Basic 2023: question 25
Set in the CBSE Class 10 board exam of 2023, paper 430/6/1, section B, question 25, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q25 · 2 marks · Very short answerCircles
From a point P, the length of the tangent to a circle is 24 cm and the distance of P from the centre of the circle is 25 cm. Find the radius of the circle.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/6/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
The radius to the point of contact is perpendicular to the tangent.
Hint 2
This makes a right triangle with hypotenuse 25 cm; use Pythagoras.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Figure: circle with centre O, external point P, tangent PQ touching the circle at Q, with cm, cm and OQ joined; [tangent ⟂ radius at point of contact].
- 1 mark
In right , by Pythagoras theorem:
- ½ mark
cm, so the radius is 7 cm.
Answer: Radius = 7 cm
Where the marks are
- Correct figure with right angle at point of contact (½ mark)
- Applies Pythagoras: (1 mark)
- Radius = 7 cm (½ mark)
Revise the chapter
- Chapter: Circles (notes, formulas, where marks are lost and every past question)
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