CBSE Class 12 Physics sample paper 2026-27: question 25
From the official CBSE sample question paper for 2026-27, section C, question 25, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q25 · 3 marks · Short answerRay Optics and Optical Instruments
A diamond has a refractive index of 2.42.
I. A ray of light inside the diamond strikes the surface at an angle of incidence of . State whether it will undergo refraction or total internal reflection.
II. Explain why diamonds sparkle when cut properly.
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2026-27.
Hints
Open one hint at a time and try again before the next.
Hint 1
Find the critical angle using sin θc = 1/μ.
Hint 2
Compare 30° with θc for light going from diamond to air.
Hint 3
What happens to light repeatedly hitting facets at angles larger than θc?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Critical angle for diamond–air: .
- 1 mark
I. The ray travels from denser (diamond) to rarer (air) medium and , so it undergoes total internal reflection, not refraction.
- 1 mark
II. Because diamond's critical angle is very small, a properly cut diamond has facets angled so that light entering it strikes the inner faces at angles greater than and is totally internally reflected many times. Light finally leaves through only a few faces, concentrated and dispersed into colours, so the diamond sparkles.
Answer: θc ≈ 24.4°; I. total internal reflection; II. repeated TIR due to small critical angle and proper cut.
Where the marks are
- Calculates critical angle ≈ 24.4° (1 mark)
- Concludes TIR since 30° > θc (1 mark)
- Explains sparkle by multiple TIR from cut facets (1 mark)
Revise the chapter
- Chapter: Ray Optics and Optical Instruments (notes, formulas, where marks are lost and every past question)
- Topic: Total Internal Reflection
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