CBSE Class 12 Physics 2025: question 6
Set in the CBSE Class 12 board exam of 2025, paper 55/7/1, section A, question 6, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q6 · 1 mark · MCQElectromagnetic Induction
A metal rod of length 50 cm is held vertically and moved with a velocity of 10 m/s towards east. The horizontal component of the Earth's magnetic field at the place is 0·4 G. The emf induced across the ends of the rod is :
- (A)0·1 mV
- (B)0·2 mV
- (C)0·8 mV
- (D)1·6 mV
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 55/7/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Use the motional emf formula.
Hint 2
Convert gauss to tesla: T.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
A vertical rod moving east cuts the horizontal (south–north) field, so .
- ½ mark
Answer: 0.2 mV, option (B)
Where the marks are
- Uses with T to get 0.2 mV (1 mark)
Revise the chapter
- Chapter: Electromagnetic Induction (notes, formulas, where marks are lost and every past question)
- Topic: Motional EMF
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.