CBSE Class 12 Physics 2025: question 2
Set in the CBSE Class 12 board exam of 2025, paper 55/7/1, section A, question 2, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q2 · 1 mark · MCQCurrent Electricity
The effective resistance between points A and B in the given circuit is :
- (A)
- (B)
- (C)
- (D)
Figure in the paper: Resistor network between terminals A (left) and B (right). A connects to a left node; B connects to a right node. Top path from A: 4 Ω up to a top-middle node via 2 Ω; top-middle node connects to the right node via 3 Ω then 6 Ω (down the right side). Top-middle node also connects to left node via 3 Ω, to right node via 18 Ω, and to a bottom node via a vertical 7 Ω. Bottom path: left node to bottom node via 4 Ω, bottom node to right node via 12 Ω. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 55/7/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
First combine resistors that are clearly in series.
Hint 2
Check whether the vertical 7 Ω branch is balanced, so that it can be ignored.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Reduce the network step by step: combine resistors in series, then combine parallel pairs, and check whether the 7 Ω branch forms a balanced bridge (equal potential at its two ends, so it carries no current).
- ½ mark
The reduced network gives an equivalent resistance of .
Answer: 16/3 Ω, option (C)
Where the marks are
- Correct reduction of the network to (1 mark)
Revise the chapter
- Chapter: Current Electricity (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.