CBSE Class 12 Physics 2025: question 17
Set in the CBSE Class 12 board exam of 2025, paper 55/7/1, section B, question 17, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q17 · 2 marks · Very short answerCurrent Electricity
A cell of emf E and internal resistance r is connected across a resistor of variable resistance R. Show graphically the variation of
(a) the terminal voltage across the cell,
(b) the current supplied by the cell,
with R as it is increased from 0 to the maximum value.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 55/7/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Write the current using Ohm's law for the complete circuit, including r.
Hint 2
Use V = E − Ir and check what happens at R = 0 and when R becomes very large.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
Current in the circuit: . Terminal voltage: .
- 1 mark
(a) V versus R graph: at , . As increases, rises quickly at first and then more slowly. The curve is concave downward and approaches asymptotically as . It never crosses the line , and when .
- 1 mark
(b) I versus R graph: at , (the maximum, short-circuit current). As increases, falls along a hyperbola-like curve, concave upward, and tends to zero as .
Answer: (a) V rises from 0 and tends asymptotically to E; (b) I falls from E/r and tends to 0.
Where the marks are
- Correct V–R graph: starting at 0 and saturating at E (1 mark)
- Correct I–R graph: starting at E/r and decreasing towards zero (1 mark)
Revise the chapter
- Chapter: Current Electricity (notes, formulas, where marks are lost and every past question)
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