CBSE Class 12 Physics 2024: question 8
Set in the CBSE Class 12 board exam of 2024, paper 55/5/1, section A, question 8, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q8 · 1 mark · MCQDual Nature of Radiation and Matter
The variation of the stopping potential () with the frequency () of the incident radiation for four metals A, B, C and D is shown in the figure. For the same frequency of incident radiation producing photo-electrons in all metals, the kinetic energy of photo-electrons will be maximum for metal
- (A)A
- (B)B
- (C)C
- (D)D
Figure in the paper: Graph of V0 (vertical axis) versus frequency v (horizontal axis) with four parallel straight lines labelled A, B, C, D, each with positive slope, starting at increasing frequency intercepts on the v-axis from A (smallest intercept) to D (largest intercept). See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 55/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
The intercept on the frequency axis is the threshold frequency.
Hint 2
Use Einstein's equation .
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
. For the same , is largest for the smallest threshold frequency .
- ½ mark
Metal A has the smallest intercept on the -axis, so its photoelectrons have maximum KE. Option (A).
Answer: Metal A, option (A)
Where the marks are
- Relates max KE to lowest threshold frequency, picks A (1 mark)
Revise the chapter
- Chapter: Dual Nature of Radiation and Matter (notes, formulas, where marks are lost and every past question)
- Topic: Photoelectric Effect: Experimental Study
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.