CBSE Class 12 Mathematics 2026: question 36
Set in the CBSE Class 12 board exam of 2026, paper 65/5/1, section E, question 36, for 4 marks. Try it first; the hints and our step-by-step solution are below.
Q36 · 4 marks · Case-basedCompetency-basedRelations and Functions
A school wants the students of class XII to do a project on 'Sustainability' keeping the world environment in mind. They select the student participants on the basis of an essay writing competition.
7 students out of 80 are selected for the project and are categorized into two sets such that :
Girl students belong to Set A = {G, G, G, G},
Boy students belong to Set B = {B, B, B}.
Based on the above information, answer the following questions :
- (i)1 mark
How many relations are possible from Set A Set B ?
- (ii)1 mark
Let R be a relation from A B such that R = {(G, B), (G, B), (G, B), (G, B), (G, B)}. Is R an injective function ? Justify your answer.
- (iii)(a)2 marks
Let the relation R from A A be such that R = {(x, y), x, y A, x and y are students from the same colony in the city}. Verify if R is an equivalence relation.
OR
(iii)(b)2 marksVerify if any function f : B A is bijective. Give reason to support your answer.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 65/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
A relation from A to B is any subset of . Count the elements of first.
Hint 2
For a function, each element of A must have exactly one image. Check in R.
Hint 3
For (iii), test reflexive, symmetric and transitive one by one using 'same colony'. For the bijection, compare the number of elements in B and A.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(i) . Every subset of is a relation from A to B, so the number of relations is .
- ½ mark
(ii) No, R is not an injective function.
- ½ mark
(ii) R is not even a function, because is related to two images, and .
- ½ mark
(iii)(a) Reflexive: every student x lives in the same colony as himself or herself, so for all .
- ½ mark
(iii)(a) Symmetric: if , then x and y live in the same colony. So y and x live in the same colony, and .
- ½ mark
(iii)(a) Transitive: if and , then x, y live in the same colony and y, z live in the same colony. So x and z live in the same colony, and .
- ½ mark
(iii)(a) R is reflexive, symmetric and transitive, hence R is an equivalence relation.
- 1 mark
(iii)(b) No function is bijective.
- 1 mark
(iii)(b) Reason: . The range of f has at most 3 elements, so at least one girl in A has no pre-image. Thus f cannot be onto, and so it cannot be bijective.
Answer: (i) ; (ii) No, R is not a function ( has two images), so not injective; (iii)(a) R is an equivalence relation; (iii)(b) No is bijective, since so f cannot be onto
Where the marks are
- (i) Number of relations (1 mark)
- (ii) States R is not injective (½ mark)
- (ii) Justifies that R is not a function since has two images (½ mark)
- (iii)(a) Proves R is reflexive (½ mark)
- (iii)(a) Proves R is symmetric (½ mark)
- (iii)(a) Proves R is transitive (½ mark)
- (iii)(a) Concludes R is an equivalence relation (½ mark)
- (iii)(b) States no function from B to A is bijective (1 mark)
- (iii)(b) Reason: , so f cannot be onto (1 mark)
Revise the chapter
- Chapter: Relations and Functions (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.