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MathsCBSE Class 12 · Board exam 2026, set 65/5/1 · 4 marks · Case-based

CBSE Class 12 Mathematics 2026: question 36

Set in the CBSE Class 12 board exam of 2026, paper 65/5/1, section E, question 36, for 4 marks. Try it first; the hints and our step-by-step solution are below.

Q36 · 4 marks · Case-basedCompetency-basedRelations and Functions

A school wants the students of class XII to do a project on 'Sustainability' keeping the world environment in mind. They select the student participants on the basis of an essay writing competition.

7 students out of 80 are selected for the project and are categorized into two sets such that :

Girl students belong to Set A = {G, G, G, G},

Boy students belong to Set B = {B, B, B}.

Based on the above information, answer the following questions :

  1. (i)

    How many relations are possible from Set A Set B ?

    1 mark
  2. (ii)

    Let R be a relation from A B such that R = {(G, B), (G, B), (G, B), (G, B), (G, B)}. Is R an injective function ? Justify your answer.

    1 mark
  3. (iii)(a)

    Let the relation R from A A be such that R = {(x, y), x, y A, x and y are students from the same colony in the city}. Verify if R is an equivalence relation.

    2 marks
  4. OR

    (iii)(b)

    Verify if any function f : B A is bijective. Give reason to support your answer.

    2 marks

Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 65/5/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

A relation from A to B is any subset of . Count the elements of first.

Hint 2

For a function, each element of A must have exactly one image. Check in R.

Hint 3

For (iii), test reflexive, symmetric and transitive one by one using 'same colony'. For the bijection, compare the number of elements in B and A.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. (i) . Every subset of is a relation from A to B, so the number of relations is .

    1 mark
  2. (ii) No, R is not an injective function.

    ½ mark
  3. (ii) R is not even a function, because is related to two images, and .

    ½ mark
  4. (iii)(a) Reflexive: every student x lives in the same colony as himself or herself, so for all .

    ½ mark
  5. (iii)(a) Symmetric: if , then x and y live in the same colony. So y and x live in the same colony, and .

    ½ mark
  6. (iii)(a) Transitive: if and , then x, y live in the same colony and y, z live in the same colony. So x and z live in the same colony, and .

    ½ mark
  7. (iii)(a) R is reflexive, symmetric and transitive, hence R is an equivalence relation.

    ½ mark
  8. (iii)(b) No function is bijective.

    1 mark
  9. (iii)(b) Reason: . The range of f has at most 3 elements, so at least one girl in A has no pre-image. Thus f cannot be onto, and so it cannot be bijective.

    1 mark

Answer: (i) ; (ii) No, R is not a function ( has two images), so not injective; (iii)(a) R is an equivalence relation; (iii)(b) No is bijective, since so f cannot be onto

Where the marks are

  • (i) Number of relations (1 mark)
  • (ii) States R is not injective (½ mark)
  • (ii) Justifies that R is not a function since has two images (½ mark)
  • (iii)(a) Proves R is reflexive (½ mark)
  • (iii)(a) Proves R is symmetric (½ mark)
  • (iii)(a) Proves R is transitive (½ mark)
  • (iii)(a) Concludes R is an equivalence relation (½ mark)
  • (iii)(b) States no function from B to A is bijective (1 mark)
  • (iii)(b) Reason: , so f cannot be onto (1 mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.