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MathsCBSE Class 12 · Board exam 2023, set 65/5/1 · 4 marks · Case-based

CBSE Class 12 Mathematics 2023: question 36

Set in the CBSE Class 12 board exam of 2023, paper 65/5/1, section E, question 36, for 4 marks. Try it first; the hints and our step-by-step solution are below.

Q36 · 4 marks · Case-basedCompetency-basedRelations and Functions

Case Study-I

An organization conducted bike race under two different categories – Boys and Girls. There were 28 participants in all. Among all of them, finally three from category 1 and two from category 2 were selected for the final race. Ravi forms two sets B and G with these participants for his college project.

Let and , where B represents the set of Boys selected and G the set of Girls selected for the final race.

Based on the above information, answer the following questions :

  1. (I)

    How many relations are possible from B to G ?

    1 mark
  2. (II)

    Among all the possible relations from B to G, how many functions can be formed from B to G ?

    1 mark
  3. (III)

    Let be defined by . Check if R is an equivalence relation.

    2 marks
  4. OR

    (III)

    A function be defined by . Check if f is bijective. Justify your answer.

    2 marks

Figure in the paper: Photograph of two riders on racing bikes, one bike ahead tilted. See it in the official paper.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 65/5/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

How many ordered pairs are in B × G? A relation is any subset of it.

Hint 2

For a function, count the choices of image for each boy.

Hint 3

In (III), notice that all members of B are boys. For the function, look for two boys with the same image.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. (I) We have .

    Every subset of is a relation from to . So the number of relations is .

    1 mark
  2. (II) In a function, each of the 3 elements of must have exactly one image in . Each has 2 choices.

    So the number of functions is .

    1 mark
  3. (III)(a) All elements of are boys, so any two of them are of the same sex. Hence .

    • Reflexive: for every .
    • Symmetric: if , then , since they are of the same sex.
    • Transitive: if , then and are of the same sex, so .

    Hence is an equivalence relation.

    2 marks
  4. (III)(b) We have and , but .

    So is not one-one. (It is onto, since both and have pre-images.)

    Since is not one-one, is not bijective.

    2 marks

Answer: (I) 64; (II) 8; (III)(a) R is an equivalence relation; (III)(b) f is not bijective (not one-one, since f(b₁) = f(b₃) = g₁)

Where the marks are

  • (I) Number of relations = 2^6 = 64 (1 mark)
  • (II) Number of functions = 2^3 = 8 (1 mark)
  • (III)(a) Shows R is reflexive, symmetric and transitive, hence equivalence (2 marks)
  • (III)(b) Shows f is not one-one as f(b₁) = f(b₃) (1 mark); concludes f is not bijective (1 mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.