CBSE Class 12 Chemistry 2026: question 17(b)
Set in the CBSE Class 12 board exam of 2026, paper 56/5/1, section B, question 17(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q17(b) · 2 marks · Very short answerSolutions
State Henry’s law. Calculate the mole fraction of in water at 298 K under 760 mm Hg.
(Given : for in at 298 K = mm Hg)
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 56/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Henry's law links the partial pressure of a gas to its mole fraction in solution through .
Hint 2
Rearrange to make the subject.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Henry's law: at a constant temperature, the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid. Equivalently, , where is the mole fraction of the gas in solution.
- ½ mark
- ½ mark
Answer:
Where the marks are
- Correct statement of Henry's law (1 mark)
- Uses with correct substitution (½ mark)
- Gets (½ mark)
Revise the chapter
- Chapter: Solutions (notes, formulas, where marks are lost and every past question)
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