ChemistryCBSE Class 12 · Sample paper, session 2026-27 · 1 mark · MCQ

CBSE Class 12 Chemistry sample paper 2026-27: question 3

From the official CBSE sample question paper for 2026-27, section A, question 3, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q3 · 1 mark · MCQElectrochemistry

The quantity of charge required to obtain one mole of metal “M” from $M_{2} O_{3}$ is:

(A)1F
(B)6F
(C)3F
(D)2F

Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2026-27.

Hints

Open one hint at a time and try again before the next.

Hint 1

Find the oxidation state of M in $M_{2} O_{3}$ .

Hint 2

Remember that 1 mol of electrons carries 1F of charge.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

In $M_{2} O_{3}$ the metal is present as $M^{3 +}$ .
The reduction is $M^{3 +} + 3 e^{-} \to M$ . One mole of metal needs 3 mol of electrons, which is 3F of charge.
1 mark

Answer: 3F, option (C)

Where the marks are

Writes $M^{3 +} + 3 e^{-} \to M$ and concludes 3F (1 mark)

Revise the chapter

Chapter: Electrochemistry (notes, formulas, where marks are lost and every past question)

Practise this chapterBoard-style questions from Electrochemistry, one at a time, marked against the answer key and marking points.Back to the full paperSample paper 2026-27: every question, by section.

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CBSE Class 12 Chemistry sample paper 2026-27: question 3

Hints

Step-by-step solution

Revise the chapter

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