CBSE Class 12 Chemistry 2025: question 17
Set in the CBSE Class 12 board exam of 2025, paper 56/7/1, section B, question 17, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q17 · 2 marks · Very short answerSolutions
What is meant by positive deviation from Raoult’s law ? Give an example. What type of azeotrope is formed by positive deviation ?
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 56/7/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Compare the actual vapour pressure with the value Raoult's law predicts.
Hint 2
Think about whether the A–B attractions are weaker or stronger than A–A and B–B.
Hint 3
If vapour pressure is higher, is the boiling point of the azeotrope lower or higher?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Positive deviation: a solution shows positive deviation from Raoult's law when its vapour pressure is higher than the value predicted by Raoult's law. This happens because the A–B (solute–solvent) attractions are weaker than the A–A and B–B attractions, so molecules escape more easily. For such solutions and .
- ½ mark
Example: a mixture of ethanol and acetone. Carbon disulphide + acetone is another example.
- ½ mark
Solutions showing a large positive deviation form a minimum boiling azeotrope. An example is about 95% ethanol–water.
Answer: Vapour pressure is higher than predicted by Raoult's law; e.g. ethanol + acetone; minimum boiling azeotrope.
Where the marks are
- States that vapour pressure of the solution is higher than expected for ideal behaviour (1 mark)
- Gives a correct example such as ethanol + acetone (½ mark)
- Names minimum boiling azeotrope (½ mark)
Revise the chapter
- Chapter: Solutions (notes, formulas, where marks are lost and every past question)
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