CBSE Class 12 Chemistry 2025: question 26(B)
Set in the CBSE Class 12 board exam of 2025, paper 56/1/1, section C, question 26(B), for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q26(B) · 3 marks · Short answerHaloalkanes and Haloarenes
How do you convert : (3 × 1 = 3)
(a) Chlorobenzene to biphenyl
(b) Propene to 1-Iodopropane
(c) 2-bromobutane to but-2-ene.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 56/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Joining two aryl groups using sodium is a named reaction.
Hint 2
To put a halogen on the terminal carbon of propene, use the peroxide effect, then swap Br for I.
Hint 3
Removing HBr from an alkyl halide needs a strong base in alcohol; apply Saytzeff's rule.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(a) Fittig reaction, heating chlorobenzene with sodium in dry ether:
- 1 mark
(b) Anti-Markovnikov addition of HBr in the presence of peroxide, then the Finkelstein reaction:
- 1 mark
(c) Dehydrohalogenation with alcoholic KOH on heating; by Saytzeff's rule the more substituted alkene is the major product:
Answer: (a) Fittig reaction with Na/dry ether; (b) HBr/peroxide, then NaI/acetone; (c) alcoholic KOH, heat
Where the marks are
- Fittig reaction giving biphenyl (1 mark)
- Peroxide HBr addition followed by Finkelstein reaction (1 mark)
- Elimination with alcoholic KOH giving but-2-ene (1 mark)
Revise the chapter
- Chapter: Haloalkanes and Haloarenes (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.