CBSE Class 12 Chemistry sample paper 2025-26: question 24
From the official CBSE sample question paper for 2025-26, section C, question 24, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q24 · 3 marks · Short answerHaloalkanes and Haloarenes
Explain the following:
I. Toluene on treatment with in sunlight gives benzyl chloride whereas when treated with in dark gives o-chlorobenzene and p-chlorobenzene.
II. Finkelstein reaction is carried out in the presence of dry acetone.
III. neo pentylchloride has lower boiling point than isopentylchloride.
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2025-26.
Hints
Open one hint at a time and try again before the next.
Hint 1
Ask what kind of reactive species chlorine forms in light and in the dark.
Hint 2
For II, compare the solubility of NaI and NaCl in acetone.
Hint 3
For III, link branching to surface area and intermolecular forces.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
I. In sunlight Cl undergoes homolysis to Cl free radicals. These attack the side-chain CH (free-radical substitution), giving benzyl chloride, CHCHCl.
In the dark with a Lewis acid (FeCl), Cl (an electrophile) forms and attacks the ring (electrophilic substitution). Since –CH is ortho/para directing, o- and p-chlorotoluene are formed.
- 1 mark
II. In the Finkelstein reaction, . NaI dissolves in dry acetone but NaCl/NaBr do not, so they precipitate out. This shifts the equilibrium forward (Le Chatelier's principle). Water would dissolve NaCl and allow the reverse reaction.
- 1 mark
III. Neopentyl chloride is more branched than isopentyl chloride, so it is more compact (nearly spherical) with a smaller surface area. Its van der Waals forces are weaker, so its boiling point is lower.
Answer: I. Sunlight: free-radical side-chain substitution gives benzyl chloride; dark with FeCl₃: electrophilic ring substitution gives o/p-chlorotoluene. II. NaCl/NaBr precipitate in dry acetone, driving the reaction forward. III. Greater branching means smaller surface area, weaker van der Waals forces and a lower boiling point.
Where the marks are
- Free radical (sunlight) vs electrophile Cl⁺ (dark), giving side-chain vs ring substitution (1 mark)
- NaCl insoluble in dry acetone, so equilibrium shifts forward (1 mark)
- Branching lowers surface area and van der Waals forces, so lower b.p. (1 mark)
Revise the chapter
- Chapter: Haloalkanes and Haloarenes (notes, formulas, where marks are lost and every past question)
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