CBSE Class 12 Chemistry sample paper 2025-26: question 2
From the official CBSE sample question paper for 2025-26, section A, question 2, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q2 · 1 mark · MCQAlcohols, Phenols and Ethers
Consider the reaction and identify B and C
and
- (A)B=C= Butanol
- (B)B= Butanol, C=Butene
- (C)B= Butan-2-ol, C= Butanol
- (D)B= Butene, C=Butan-2-ol
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2025-26.
Hints
Open one hint at a time and try again before the next.
Hint 1
Alcoholic NaOH gives an alkene.
Hint 2
Compare Markovnikov hydration with hydroboration–oxidation.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
Alcoholic NaOH causes dehydrohalogenation: A = but-1-ene, .
- 1 mark
Acid-catalysed hydration follows Markovnikov's rule: B = butan-2-ol. Hydroboration–oxidation gives the anti-Markovnikov product: C = butan-1-ol.
Answer: B = Butan-2-ol, C = Butanol; option (C)
Where the marks are
- Correct identification of B (Markovnikov) and C (anti-Markovnikov) (1 mark)
Revise the chapter
- Chapter: Alcohols, Phenols and Ethers (notes, formulas, where marks are lost and every past question)
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