CBSE Class 12 Chemistry 2024: question 21
Set in the CBSE Class 12 board exam of 2024, paper 56/1/1, section B, question 21, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q21 · 2 marks · Very short answerAldehydes, Ketones and Carboxylic Acids
Write the chemical equation when :
(a) Butan-2-one is treated with Zn(Hg) and conc. HCl.
(b) Two molecules of benzaldehyde are treated with conc. NaOH.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 56/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Zn(Hg)/conc. HCl is a named reduction of carbonyl compounds.
Hint 2
An aldehyde without α-hydrogen in conc. alkali disproportionates.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(a) Clemmensen reduction converts C=O to CH₂: (butane).
- 1 mark
(b) Cannizzaro reaction (benzaldehyde has no α-H): (benzyl alcohol + sodium benzoate).
Answer: (a) Butane; (b) Benzyl alcohol + sodium benzoate (Cannizzaro reaction)
Where the marks are
- Clemmensen reduction equation giving butane (1 mark)
- Cannizzaro equation giving benzyl alcohol and sodium benzoate (1 mark)
Revise the chapter
- Chapter: Aldehydes, Ketones and Carboxylic Acids (notes, formulas, where marks are lost and every past question)
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