CBSE Class 12 Chemistry 2024: question 20(a)
Set in the CBSE Class 12 board exam of 2024, paper 56/1/1, section B, question 20(a), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q20(a) · 2 marks · Very short answerHaloalkanes and Haloarenes
Draw the structures of major monohalo products in each of the following reactions :
(i) styrene () + HBr
(ii) cyclohexene +
Figure in the paper: (i) benzene ring with CH=CH2 substituent plus HBr; (ii) cyclohexene ring plus Br2 under UV light. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 56/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
In (i) decide which carbocation is more stable after H⁺ adds.
Hint 2
In (ii) UV light means free radicals; which hydrogen gives the most stable radical?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(i) Electrophilic addition follows Markovnikov's rule; H⁺ adds to the terminal CH₂ giving the more stable benzylic carbocation, so Br attaches to the carbon bearing the ring: (1-bromo-1-phenylethane).
- 1 mark
(ii) In UV light Br₂ gives free-radical substitution at the allylic position (the ring CH₂ next to the double bond): cyclohexene + Br₂ → 3-bromocyclohexene (six-membered ring with C=C between C1 and C2 and Br on C3) + HBr.
Answer: (i) ; (ii) 3-bromocyclohexene
Where the marks are
- Markovnikov product 1-bromo-1-phenylethane (1 mark)
- Allylic substitution product 3-bromocyclohexene (1 mark)
Revise the chapter
- Chapter: Haloalkanes and Haloarenes (notes, formulas, where marks are lost and every past question)
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