CBSE Class 12 Chemistry 2024: question 20(b)
Set in the CBSE Class 12 board exam of 2024, paper 56/1/1, section B, question 20(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q20(b) · 2 marks · Very short answerHaloalkanes and Haloarenes
Give reasons for the following :
(i) Grignard reagent should be prepared under anhydrous conditions.
(ii) Alkyl halides give alcohol with aqueous KOH whereas in the presence of alcoholic KOH, alkenes are formed.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 56/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
The carbon in RMgX carries a partial negative charge — what does it do with an acidic H?
Hint 2
Compare the behaviour of a nucleophile and a base; which species is formed when KOH dissolves in ethanol?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(i) Grignard reagents are highly reactive and react with even traces of moisture to form alkanes, so the reagent is destroyed: . Hence they are prepared under anhydrous conditions.
- 1 mark
(ii) In aqueous KOH, the OH⁻ ions are highly hydrated and act mainly as nucleophiles, giving substitution (alcohol). In alcoholic KOH, alkoxide ions () are formed, which are stronger bases than OH⁻; they abstract a β-hydrogen, so dehydrohalogenation (elimination) gives alkenes.
Answer: (i) RMgX reacts with water to give alkane; (ii) alkoxide ion in alcoholic KOH is a strong base causing elimination, while aqueous OH⁻ acts as nucleophile.
Where the marks are
- Reaction of Grignard reagent with water forming alkane (1 mark)
- Alkoxide in alcoholic KOH is a stronger base → elimination; aqueous OH⁻ → substitution (1 mark)
Revise the chapter
- Chapter: Haloalkanes and Haloarenes (notes, formulas, where marks are lost and every past question)
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