CBSE Class 12 Chemistry 2023: question 22
Set in the CBSE Class 12 board exam of 2023, paper 56/5/1, section B, question 22, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q22 · 2 marks · Very short answerHaloalkanes and Haloarenes
Why is boiling point of o-dichlorobenzene higher than p-dichlorobenzene but melting point of para isomer is higher than ortho isomer ?
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 56/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Boiling depends on intermolecular forces in the liquid; compare dipole moments of the two isomers.
Hint 2
Melting depends on how well molecules pack in the solid; which isomer is more symmetrical?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Boiling point: o-dichlorobenzene is polar (the two C–Cl dipoles do not cancel), while in p-dichlorobenzene they cancel (μ = 0). The stronger dipole–dipole forces in the ortho isomer give it the higher boiling point.
- 1 mark
Melting point: p-dichlorobenzene is more symmetrical, so its molecules pack more closely and fit better in the crystal lattice; more energy is needed to break the lattice, so it has the higher melting point.
Answer: o-isomer: higher dipole moment → higher b.p.; p-isomer: symmetrical, better packing → higher m.p.
Where the marks are
- B.p.: higher polarity / dipole–dipole interactions in o-isomer (1 mark)
- M.p.: symmetry and better crystal packing of p-isomer (1 mark)
Revise the chapter
- Chapter: Haloalkanes and Haloarenes (notes, formulas, where marks are lost and every past question)
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