CBSE Class 12 Chemistry sample paper 2023-24: question 18
From the official CBSE sample question paper for 2023-24, section B, question 18, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q18 · 2 marks · Very short answerSolutions
A 5% solution of (MW = 322) is isotonic with 2% solution of non-electrolytic, non volatile substance X. Find out the molecular weight of X.
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2023-24.
Hints
Open one hint at a time and try again before the next.
Hint 1
Isotonic means equal osmotic pressure at the same temperature.
Hint 2
The salt is an electrolyte — count the ions it gives to find i.
Hint 3
Both solutions are per 100 mL, so moles = mass/molar mass can be compared directly.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Isotonic solutions have equal osmotic pressure: , i.e. , so .
- ½ mark
, so ; X is a non-electrolyte, .
- ½ mark
Taking 100 mL of each solution:
- ½ mark
Answer: Molecular mass of X ≈ 42.9 g mol⁻¹
Where the marks are
- Uses equal osmotic pressure for isotonic solutions, iC₁ = C₂ (½ mark)
- Takes i = 3 for Na₂SO₄·10H₂O (½ mark)
- Correct substitution 3 × 5/322 = 2/M (½ mark)
- M = 42.9 g mol⁻¹ (½ mark)
Revise the chapter
- Chapter: Solutions (notes, formulas, where marks are lost and every past question)
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