CBSE Class 12 Biology sample paper 2025-26: question 20(B)
From the official CBSE sample question paper for 2025-26, section B, question 20(B), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q20(B) · 2 marks · Very short answerBiotechnology: Principles and Processes
Why does the 'insertional inactivation' method to detect recombinant DNA is preferred to 'antibiotic resistance' procedure?
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2025-26.
Hints
Open one hint at a time and try again before the next.
Hint 1
How many plates does the antibiotic method need?
Hint 2
Think of blue-white screening with a chromogenic substrate.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Selecting recombinants by inactivating an antibiotic resistance gene is cumbersome. It needs simultaneous replica plating on two plates with different antibiotics (e.g., ampicillin and tetracycline).
- 1 mark
In insertional inactivation, the foreign DNA is inserted within the coding sequence of β-galactosidase, which inactivates the enzyme. On a medium with a chromogenic substrate, non-recombinants give blue colonies, while recombinants give colourless/white colonies. Recombinants are thus identified on a single plate.
Answer: Antibiotic-based selection needs two plates (cumbersome); insertional inactivation of β-galactosidase gives blue (non-recombinant) vs colourless (recombinant) colonies on one plate.
Where the marks are
- States antibiotic resistance method is cumbersome due to plating on two antibiotic plates (1 mark)
- Explains β-galactosidase inactivation and blue/colourless colony selection (1 mark)
Revise the chapter
- Chapter: Biotechnology: Principles and Processes (notes, formulas, where marks are lost and every past question)
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