CBSE Class 12 Biology sample paper 2025-26: question 18
From the official CBSE sample question paper for 2025-26, section B, question 18, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q18 · 2 marks · Very short answerMolecular Basis of Inheritance
How is the rate of initiation of RNA polymerase at a given promoter in a transcriptional unit of prokaryotes regulated?
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2025-26.
Hints
Open one hint at a time and try again before the next.
Hint 1
Think of the lac operon and what binds next to the promoter.
Hint 2
Regulatory proteins can switch the gene on or off by acting at the operator.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
The ability of RNA polymerase to start transcription at a promoter depends on accessory (regulatory) proteins. These proteins help the polymerase recognise the start site.
- 1 mark
The regulatory proteins can act positively (activators) or negatively (repressors). In an operon, they work by interacting with the operator, which lies next to the promoter. A repressor bound to the operator blocks RNA polymerase, as in the lac operon.
Answer: By accessory regulatory proteins (activators/repressors) that act on the operator adjacent to the promoter and control recognition of start sites by RNA polymerase.
Where the marks are
- Accessory proteins regulate the recognition of start sites by RNA polymerase (1 mark)
- Positive (activator) and negative (repressor) regulation through the operator next to the promoter (1 mark)
Revise the chapter
- Chapter: Molecular Basis of Inheritance (notes, formulas, where marks are lost and every past question)
- Topic: Transcription
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