CBSE Class 12 Biology 2023: question 33(b)
Set in the CBSE Class 12 board exam of 2023, paper 57/5/1, section E, question 33(b), for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q33(b) · 5 marks · Long answerBiotechnology: Principles and Processes
Answer the following.
- (i)3 marks
‘EcoRI’ has played very significant role in r-DNA technology.
(I) Explain the convention for naming EcoRI.
(II) Write the recognition site and the cleavage sites of this restriction endonuclease. - (ii)2 marks
What are the protruding and hanging stretches of DNA produced by these restriction enzymes called ? Describe their role in formation of r-DNA.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 57/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
The letters of a restriction enzyme name come from the bacterium it was isolated from, and the Roman numeral has a meaning too.
Hint 2
EcoRI recognises a six-base palindrome that begins with G and ends with C. Find where the cut falls between two of those bases.
Hint 3
The overhangs can pair with complementary overhangs. Which enzyme then seals the joined fragments?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 2 marks
(i)(I) Naming convention of EcoRI:
- E = genus Escherichia
- co = species coli
- R = strain RY 13
- I (Roman numeral) = the order in which the enzyme was isolated from that strain (the first one)
- ½ mark
(i)(II) Recognition site: the palindromic sequence
5′–G A A T T C–3′
3′–C T T A A G–5′
- ½ mark
Cleavage site: EcoRI cuts between G and A on both strands (5′–G↓AATTC–3′ and 3′–CTTAA↑G–5′). This leaves 5′ AATT overhangs.
- 1 mark
(ii) The protruding, single-stranded hanging stretches are called sticky ends.
- 1 mark
Role in r-DNA formation:
- The vector and the foreign DNA are cut with the same enzyme, so their sticky ends are complementary. They pair with each other through hydrogen bonds.
- This stickiness holds the fragments together and makes it easier for the enzyme DNA ligase to join them, which forms the recombinant DNA.
Answer: (i)(I) E = Escherichia (genus), co = coli (species), R = strain RY13, I = first enzyme isolated from that strain. (II) Recognition site 5′GAATTC3′ / 3′CTTAAG5′; cut between G and A on both strands. (ii) Sticky ends; they hydrogen-bond with complementary ends and help DNA ligase join the DNA to form r-DNA.
Where the marks are
- E = genus, co = species, R = strain, I = order of isolation (½ × 4 = 2 marks)
- Correct palindromic recognition site GAATTC/CTTAAG (½ mark)
- Cleavage between G and A on both strands (½ mark)
- Names sticky ends (1 mark)
- Sticky ends hydrogen-bond with complementary cut ends (½ mark)
- This facilitates the action of DNA ligase to form r-DNA (½ mark)
Revise the chapter
- Chapter: Biotechnology: Principles and Processes (notes, formulas, where marks are lost and every past question)
- Topic: Restriction Enzymes
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