CBSE Class 12 Biology 2023: question 21
Set in the CBSE Class 12 board exam of 2023, paper 57/5/1, section B, question 21, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q21 · 2 marks · Very short answerBiotechnology: Principles and Processes
Answer the following.
- (a)0 marks
Write the scientific name of the source organism of the themostable DNA polymerase used in PCR.
- (b)0 marks
State the advantage of using Thermostable DNA polymerase.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 57/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
The enzyme is named Taq. Expand the abbreviation into the bacterium's full scientific name.
Hint 2
Think about which PCR step uses very high temperature and what that would do to an ordinary enzyme.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(a) The source organism is the bacterium Thermus aquaticus, and the enzyme is called Taq polymerase.
- 1 mark
(b) Thermostable DNA polymerase remains active at the high temperature (about 94 °C) used to denature double-stranded DNA in each PCR cycle. So it need not be added again after every denaturation step, and the cycles can run repeatedly.
Answer: (a) Thermus aquaticus; (b) It stays active at high denaturation temperatures, so it need not be added afresh in every cycle.
Where the marks are
- Writes the scientific name Thermus aquaticus (1 mark)
- States it remains active during high-temperature denaturation, so no re-addition is needed each cycle (1 mark)
Revise the chapter
- Chapter: Biotechnology: Principles and Processes (notes, formulas, where marks are lost and every past question)
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